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单选题
已知直线,mx+4y-2=0与2x-5y+n=0互相垂直,垂足为(1,P),则m—n+P的值为( )
A
24
B
20
C
0
D
-4
参考答案
参考解析
解析:
由两直线垂直的斜率关系可得m=10,直线方程为5x+2y-1=0和2x-5y+n=0,当x=1时,y=-2,即P=-2,将交点代入2x-5y+n=0得n=-12,因此m—n+P=20.
由两直线垂直的斜率关系可得m=10,直线方程为5x+2y-1=0和2x-5y+n=0,当x=1时,y=-2,即P=-2,将交点代入2x-5y+n=0得n=-12,因此m—n+P=20.
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