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多选题
现有:  class HorseRadish  {      //insert code here  protected HorseRadish (int x)    {      System.out.println ("bok choy");      }      }  class Wasabi extends HorseRadish  {  public static void main (String  []  args){    Wasabi w- new Wasabi();     }     }  分别插入到第2行,哪两项允许代码编译并产生”bok choy”输出结果()
A

protected HorseRadish()  {this (42);}

B

protected HorseRadish()  {}

C

//just a comment

D

protected  HorseRadish()  {  new HorseRadish (42);}


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更多 “多选题现有:  class HorseRadish  {      //insert code here  protected HorseRadish (int x)    {      System.out.println ("bok choy");      }      }  class Wasabi extends HorseRadish  {  public static void main (String  []  args){    Wasabi w- new Wasabi();     }     }  分别插入到第2行,哪两项允许代码编译并产生”bok choy”输出结果()Aprotected HorseRadish()  {this (42);}Bprotected HorseRadish()  {}C//just a commentDprotected  HorseRadish()  {  new HorseRadish (42);}” 相关考题
考题 Given:Which three methods, inserted individually at line 14, will correctly complete class Two?() A.int foo() { /* more code here */ }B.void foo() { /* more code here */ }C.public void foo() { /* more code here */ }D.private void foo() { /* more code here */ }E.protected void foo() { /* more code here */ }

考题 1. class BaseClass {  2. private float x = 1.of;  3. protected float getVar() { return x; }  4. }  5. class SubClass extends BaseClass {  6. private float x = 2.Of;  7. // insert code here 8. }   Which two are valid examples of method overriding when inserted at line 7?() A、 float getVar() { return x; }B、 public float getVar() { return x; }C、 public double getVar() { return x; }D、 protected float getVar() { return x; }E、 public float getVar(float f) { return f; }

考题 现有包结构:  com |-- x | |-- Alpha.class | | | |-- y | |-- Beta.class | |-- Gamma.class  和类:  //insert code here  import com.*;  import com.x.y.*;  class Test { Alpha a; Beta b; Gamma c; }  哪两行分别插入后可允许代码编译?() A、package com.;B、import com.x;C、package com.x;D、import com.x.Alpha;

考题 Which lines of code are valid declarations of a native method when occurring within the declaration of the following class?()    public class Qf575 {   // insert declaration of a native method here   }  A、native public void setTemperature(int kelvin);B、private native void setTemperature(int kelvin);C、protected int native getTemperature();D、public abstract native void setTemperature(int kelvin);E、native int setTemperature(int kelvin) {}

考题 class One {  void foo() {}  }  class Two extends One {   //insert method here  }  Which three methods, inserted individually at line 14, will correctly complete class Two?()A、 int foo() { /* more code here */ }B、 void foo() { /* more code here */ }C、 public void foo() { /* more code here */ }D、 private void foo() { /* more code here */ }E、 protected void foo() { /* more code here */ }

考题 现有:   1.  class HorseRadish {   2.    // insert code here   3.    protected HorseRadish(int x) {    4.      System.out.println("bok choy");  5.    }  6.  }   7.  class Wasabi extends HorseRadish {   8.    public static void main(String [] args) {   9.      Wasabi w = new Wasabi();  10.   }    11. }   分别插入到第 2 行,哪两项允许代码编译并产生"bok choy" 输出结果?() A、 // just a commentB、 protected HorseRadish() { }C、 protected HorseRadish() { this(42);}D、 protected  HorseRadish() { new HorseRadish (42);}

考题 1. class HorseRadish {   2. // insert code here   3. protected HorseRadish(int x) {  4. System.out.println("bok choy");   5. }   6. }   7. class Wasabi extends HorseRadish {   8. public static void main(String [] args) {   9. Wasabi w = new Wasabi();  10. }   11. }   分别插入到第 2 行,哪两项允许代码编译并产生"bok choy" 输出结果?()  A、 // just a commentB、 protected HorseRadish() { }C、 protected HorseRadish() { this(42);}D、 protected HorseRadish() { new HorseRadish (42);}

考题 现有:  1. abstract class Color2  {      2.    //insert code here      3.  }      4.  5. public class Blue2 extends Color2  {  6.public  String getRGB()  {  return  "blue";  }      7.  }  和4个声明:  public abstract  String getRGB();     abstract  String getRGB();  private abstract  String getRGB();      protected abstract String getRGB();  分别插入到第2行,有多少行可以编译?()     A、  0B、  1C、  2D、  3

考题 现有:   1. class Synapse {    2.    protected int gap() { return 7; }    3. }   4.     5. class Creb extends Synapse {    6.   // insert code here   7. }    分别插入到第 6 行,哪三行可以编译?()A、 int gap() { return 7; }B、 public int gap() { return 7; }C、 private int gap(int x) { return 7; }D、 protected Creb gap() { return this; }E、 public int gap() { return Integer.getInteger ("42"); }

考题 public class OuterClass {  private double d1  1.0;  //insert code here   }   You need to insert an inner class declaration at line2. Which two inner class declarations are valid?() A、 static class InnerOne {  public double methoda() {return d1;}  }B、 static class InnerOne {  static double methoda() {return d1;} }C、 private class InnerOne {  public double methoda() {return d1;} }D、 protected class InnerOne {  static double methoda() {return d1;} }E、 public abstract class InnerOne {  public abstract double methoda();  }

考题 1. class Synapse {   2. protected int gap() { return 7; }   3. }   4.   5. class Creb extends Synapse { 6. // insert code here  7. }  分别插入到第 6 行,哪三行可以编译?()A、 int gap() { return 7; }B、 public int gap() { return 7; }C、 private int gap(int x) { return 7; }D、 protected Creb gap() { return this; }E、 public int gap() { return Integer.getInteger ("42"); }

考题 现有:  class HorseRadish  {      //insert code here  protected HorseRadish (int x)    {      System.out.println ("bok choy");      }      }  class Wasabi extends HorseRadish  {  public static void main (String  []  args){    Wasabi w- new Wasabi();     }     }  分别插入到第2行,哪两项允许代码编译并产生”bok choy”输出结果()A、 protected HorseRadish()  {this (42);}B、  protected HorseRadish()  {}C、  //just a commentD、  protected  HorseRadish()  {  new HorseRadish (42);}

考题 1. public class OuterClass {  2. private double d1 = 1.0;  3. // insert code here  4. }  Which two are valid if inserted at line 3?()  A、 static class InnerOne { public double methoda() { return d1; } }B、 static class InnerOne { static double methoda() { return d1; } }C、 private class InnerOne { public double methoda() { return d1; } }D、 protected class InnerOne { static double methoda() { return d1; } }E、 public abstract class InnerOne { public abstract double methoda(); }

考题 11. public interface Status {  12. /* insert code here */ int MY_VALUE = 10;  13. }  Which three are valid on line 12?()A、 finalB、 staticC、 nativeD、 publicE、 privateF、 abstractG、 protected

考题 1. public class Blip {  2. protected int blipvert(int x) { return 0; }  3. }  4. class Vert extends Blip {  5. // insert code here  6. }  Which five methods, inserted independently at line 5, will compile?()  A、 public int blipvert(int x) { return 0; }B、 private int blipvert(int x) { return 0; }C、 private int blipvert(long x) { return 0; }D、 protected long blipvert(int x, int y) { return 0; }E、 protected int blipvert(long x) { return 0; }F、 protected long blipvert(long x) { return 0; }G、protected long blipvert(int x) { return 0; }

考题 Given:   10. class One {   11. void foo() { }   12. }   13. class Two extends One {   14. //insert method here   15. }   Which three methods, inserted individually at line 14, will correctly complete class Two?()A、 public void foo() { /* more code here */ }B、 private void foo() { /* more code here */ }C、 protected void foo() { /* more code here */ }D、 int foo() { /* more code here */ }  E、 void foo() { /* more code here */ }

考题 多选题Given:   10. class One {   11. void foo() { }   12. }   13. class Two extends One {   14. //insert method here   15. }   Which three methods, inserted individually at line 14, will correctly complete class Two?()Apublic void foo() { /* more code here */ }Bprivate void foo() { /* more code here */ }Cprotected void foo() { /* more code here */ }Dint foo() { /* more code here */ }Evoid foo() { /* more code here */ }

考题 多选题class One {  void foo() {}  }  class Two extends One {   //insert method here  }  Which three methods, inserted individually at line 14, will correctly complete class Two?()Aint foo() { /* more code here */ }Bvoid foo() { /* more code here */ }Cpublic void foo() { /* more code here */ }Dprivate void foo() { /* more code here */ }Eprotected void foo() { /* more code here */ }

考题 单选题现有:  1. abstract class Color  {  2.protected abstract  String getRGB();     3.  }     4.  5. public class Blue extends Color  {     6.    //insert code here      7.  }  和四个声明:  public String getRGB()  {  return "blue";  }      String getRGB()  {  return  "blue";  )  private  String getRGB()  {  return  "blue";  }      protected String getRGB()  {  return "blue";  )      分别插入到第6行,有几个可以通过编译?()A   0B   1C   2D   3

考题 多选题现有:  class HorseRadish  {      //insert code here  protected HorseRadish (int x)    {      System.out.println ("bok choy");      }      }  class Wasabi extends HorseRadish  {  public static void main (String  []  args){    Wasabi w- new Wasabi();     }     }  分别插入到第2行,哪两项允许代码编译并产生”bok choy”输出结果()Aprotected HorseRadish()  {this (42);}Bprotected HorseRadish()  {}C//just a commentDprotected  HorseRadish()  {  new HorseRadish (42);}

考题 多选题现有:   1.  class HorseRadish {   2.    // insert code here   3.    protected HorseRadish(int x) {    4.      System.out.println("bok choy");  5.    }  6.  }   7.  class Wasabi extends HorseRadish {   8.    public static void main(String [] args) {   9.      Wasabi w = new Wasabi();  10.   }    11. }   分别插入到第 2 行,哪两项允许代码编译并产生"bok choy" 输出结果?()A// just a commentBprotected HorseRadish() { }Cprotected HorseRadish() { this(42);}Dprotected  HorseRadish() { new HorseRadish (42);}

考题 多选题1. class Synapse {   2. protected int gap() { return 7; }   3. }   4.   5. class Creb extends Synapse { 6. // insert code here  7. }  分别插入到第 6 行,哪三行可以编译?()Aint gap() { return 7; }Bpublic int gap() { return 7; }Cprivate int gap(int x) { return 7; }Dprotected Creb gap() { return this; }Epublic int gap() { return Integer.getInteger (42); }

考题 单选题现有:  1.class Over  {  2.int dolt (long x)  {  return 3;  }      3.  }      4.  5. class Under extends Over  {      6.//insert code here      7.  }  和四个方法:  short dolt (int y)  {  return 4;  }  int dolt(long Xr long y)  {  return 4;  }      private int dolt(short y)  {  return 4;  }     protected int dolt (long x)  {  return 4;  }      分别插入到第6行,有几个可以通过编译?()A   1B   2C   3D   4

考题 单选题public class Score implements Comparable {  private int wins, losses;  public Score(int w, int 1) { wins = w; losses = 1; }  public int getWins() { return wins; }  public int getLosses() { return losses; }  public String toString() {  return “”; }  // insert code here  }  Which method will complete this class?()A  public int compareTo(Object o) {/*mode code here*/}B  public int compareTo(Score other) {/*more code here*/}C  public int compare(Score s1,Score s2){/*more code here*/}D  public int compare(Object o1,Object o2){/*more code here*/}

考题 单选题现有:  1. abstract class Color2  {      2.    //insert code here      3.  }      4.  5. public class Blue2 extends Color2  {  6.public  String getRGB()  {  return  "blue";  }      7.  }  和4个声明:  public abstract  String getRGB();     abstract  String getRGB();  private abstract  String getRGB();      protected abstract String getRGB();  分别插入到第2行,有多少行可以编译?()A   0B   1C   2D   3

考题 多选题1. class HorseRadish {   2. // insert code here   3. protected HorseRadish(int x) {  4. System.out.println("bok choy");   5. }   6. }   7. class Wasabi extends HorseRadish {   8. public static void main(String [] args) {   9. Wasabi w = new Wasabi();  10. }   11. }   分别插入到第 2 行,哪两项允许代码编译并产生"bok choy" 输出结果?()A// just a commentBprotected HorseRadish() { }Cprotected HorseRadish() { this(42);}Dprotected HorseRadish() { new HorseRadish (42);}

考题 单选题现有:  interface Animal {       void eat () ;       }       //insert code here       public class HouseCat extends Feline {       public void eat() { }       }  和五个申明  abstract class Feline implements Animal { }  abstract  class  Feline  implements  Animal  {  void eat () ;  }  abstract class Feline implements Animal { public void eat();}  abstract class Feline implements Animal { public void eat() {}  }  abstract class Feline implements Animal { abstract public void eat();} 结果为:()A 1B 2C 3D 4

考题 多选题现有:   1. class Synapse {    2.    protected int gap() { return 7; }    3. }   4.     5. class Creb extends Synapse {    6.   // insert code here   7. }    分别插入到第 6 行,哪三行可以编译?()Aint gap() { return 7; }Bpublic int gap() { return 7; }Cprivate int gap(int x) { return 7; }Dprotected Creb gap() { return this; }Epublic int gap() { return Integer.getInteger (42); }