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单选题
If one pair of opposite sides of a square are increased in length by 20% and the other pair of sides are increased in length by 50%, by what percent is the area of the rectangle that results greater than the area of the original square?
A
10%
B
50%
C
70%
D
75%
E
80%
参考答案
参考解析
解析：
Suppose the length of a side of the original square is 10; then the area of that square is 10×10 or 100. Since one pair of opposite sides of the square are increased in length by 20%, and 20% of 10 is 2, the length of that pair of opposite sides of the new rectangle is 10+2 or 12. Since the other pair of sides are increased in length by 50%, and 50% of 10 is 5, the length of the other pair of opposite sides of the new rectangle is 10+5 or 15. The area of the new rectangle formed is 12×15 or 180, which is 80% greater than 100, the area of the original square.
Suppose the length of a side of the original square is 10; then the area of that square is 10×10 or 100. Since one pair of opposite sides of the square are increased in length by 20%, and 20% of 10 is 2, the length of that pair of opposite sides of the new rectangle is 10+2 or 12. Since the other pair of sides are increased in length by 50%, and 50% of 10 is 5, the length of the other pair of opposite sides of the new rectangle is 10+5 or 15. The area of the new rectangle formed is 12×15 or 180, which is 80% greater than 100, the area of the original square.
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