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Replyfrom220.181.12.218：bytes=32time=65msTTL=55，上述结果中显示发送的数据包的生存时间是（）。
- A、32
- B、65
- C、55
- D、1
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更多 “Replyfrom220.181.12.218：bytes=32time=65msTTL=55，上述结果中显示发送的数据包的生存时间是（）。A、32B、65C、55D、1” 相关考题
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Givenclassesdefinedintwodifferentfiles：1.packageutil；2.publicclassBitUtils{3.publicstaticvoidprocess（byte[]）{/*morecodehere*/}4.}1.packageapp；2.publicclassSomeApp{3.publicstaticvoidmain（String[]args）{4.byte[]bytes=newbyte[256]；5.//insertcodehere6.}7.}Whatisrequiredatline5inclassSomeApptousetheprocessmethodofBitUtils？（）A.process（bytes）；B.BitUtils.process（bytes）；C.util.BitUtils.process（bytes）；D.SomeAppcannotusemethodsinBitUtils.E.importutil.BitUtils.*；process（bytes）；
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如果在-台主机的Windows环境下执行Ping命令得到下列信息：Pinging www．nankai．edu．cn[202．113．16．33 ]with 32 bytes of data：Reply from 202．113．16．33：bytes=32 time<；1ms TTL=128Reply from 202．113．16．33：bytes=32 time<；1ms TTL=128Reply from 202．113．16．33：bytes=32 time<；1ms TTL=128Reply from 202．113．16．33：bytes=32 time<；1ms TTL=128Ping statistics for 202．1 13．16．33：Packets：Sent=4，Received=4，Lost=0（0％loss），Approximate round trip times in milli-seconds：Minimum=0ms，Maximum=Oms，Average=Oms那么下列结论中无法确定的是（ ）。A.为www．nankai．edu．cn提供名字解析的服务器工作正常B.本机使用的DNS服务器工作正常C.主机www．nankai．edu．cn上WWW服务工作正常D.主机www．nankai．edu．cn的网关配置正确
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Refer to the exhibit. What is the meaning of the output MTU 1500 bytes?()
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考题
在 Windows 中，运行（请作答此空）命令得到下图所示结果。以下关于该结果的叙述中，错误的是（）。Pinging 59.74.111.8 with 32 bytes of data:Reply from 59.74.111.8: bytes=32 time=3ms TTL=60Reply from 59.74.111.8: bytes=32 time=5ms TTL=60Reply from 59.74.111.8: bytes=32 time=3ms TTL=60Reply from 59.74.111.8: bytes=32 time=5ms TTL=60Ping statistics for 59.74.111.8: Packets: Sent = 4, Received = 4, Lost = 0 (0% loss),Approximate round trip times in milli-seconds: Minimum = 3ms, Maximum = 5ms, Average = 4msA.ipconfig/all
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在 Windows 中，运行（请作答此空）命令得到下图所示结果。Pinging 59.74.111.8 with 32 bytes of data:Reply from 59.74.111.8: bytes=32 time=3ms TTL=60Reply from 59.74.111.8: bytes=32 time=5ms TTL=60Reply from 59.74.111.8: bytes=32 time=3ms TTL=60Reply from 59.74.111.8: bytes=32 time=5ms TTL=60Ping statistics for 59.74.111.8: Packets: Sent = 4, Received = 4, Lost = 0 (0% loss),Approximate round trip times in milli-seconds:Minimum = 3ms, Maximum = 5ms, Average = 4ms）A.ipconfig/all
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考题
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考题
单选题What are the header sizes for point-to-point and multi-point GRE（also known asmGRE） with tunnel key？（）A
4 bytes for bothB
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8 bytes for bothD
24 bytes for both
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多选题单用户Ping包时延测试步骤（）。A邻小区开启B测试终端处于主测小区内覆盖好点进行测试C测试终端接入系统，发起32Bytes包，连续ping100次D测试终端接入系统，发起32Bytes包，连续ping5次
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process(bytes);B
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SomeApp cannot use methods in BitUtils.E
import util.BitUtils.*; process(bytes);
考题
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考题
单选题Given classes defined in two different files: What is required at line 5 in class SomeApp to use the process method of BitUtils?（）A
process(bytes);B
BitUtils.process(bytes);C
app.BitUtils.process(bytes);D
util.BitUtils.process(bytes);E
import util.BitUtils.*; process(bytes);F
SomeApp cannot use the process method in BitUtils.
考题
单选题OTN2500-X3M的帧字节为9216bytes其中系统字节为（）。A
256 bytesB
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