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多选题
1. class BigDog extends Dog { 2. // insert code here 3. } 分别插入到第 2 行,哪二项可以编译?()
A
BigDog() { super(); this(); }
B
BigDog() { String name = Fido; super(); }
C
BigDog() { super(); String name = Fido; }
D
private BigDog() { super();}
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考题
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多选题Given: 10. class One { 11. void foo() { } 12. } 13. class Two extends One { 14. //insert method here 15. } Which three methods, inserted individually at line 14, will correctly complete class Two?()Apublic void foo() { /* more code here */ }Bprivate void foo() { /* more code here */ }Cprotected void foo() { /* more code here */ }Dint foo() { /* more code here */ }Evoid foo() { /* more code here */ }
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单选题Given classes defined in two different files: 1. package util; 2. public class BitUtils { 3. public static void process(byte[]) { /* more code here */ } 4. } 1. package app; 2. public class SomeApp { 3. public static void main(String[] args) { 4. byte[] bytes = new byte[256]; 5. // insert code here 6. } 7. } What is required at line 5 in class SomeApp to use the process method of BitUtils?()A
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考题
单选题1. import java.util.*; 2. class SubGen { 3. public static void main(String [] args) { 4. //insert code here 5. } 6. } class Alpha { } class Beta extends Alpha { } class Gamma extends Beta { } 和四段代码片段: s1. ArrayList〈? extends Alpha〉 list1 = new ArrayList〈Gamma〉(); s2. ArrayList〈Alpha〉 list2 = new ArrayList〈? extends Alpha〉(); s3. ArrayList〈? extends Alpha〉 list3 = new ArrayList〈? extends Beta〉(); s4. ArrayList〈? extends Beta〉 list4 = new ArrayList〈Gamma〉(); ArrayList〈? extends Alpha〉 list5 = list4; 哪些片段分别插入到第4行,可允许代码编译?()A
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考题
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0B
1C
2D
3
考题
单选题现有: 1. interface Animal { 2. void eat(); 3. } 4. 5. // insert code here 6. 7. public class HouseCat extends Feline { 8. public void eat() { } 9. } 和五个声明: abstract class Feline implements Animal { } abstract class Feline implements Animal { void eat(); } abstract class Feline implements Animal { public void eat(); } abstract class Feline implements Animal { public void eat() { } } abstract class Feline implements Animal { abstract public void eat(); } 分别插入到第5行,有几个可以通过编译?()A
0B
1C
2D
3
考题
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考题
单选题1. public class Employee { 2. String name; 3. double baseSalary; 4. Employee(String name, double baseSalary) { 5. this.name = name; 6. this.baseSalary = baseSalary; 7. } 8. } And: 1. public class Salesperson extends Employee { 2. double commission; 3. public Salesperson(String name, double baseSalary, 4. double commission) { 5. // insert code here 6. } 7. } Which code, inserted at line 7, completes the Salesperson constructor?()A
this.commission = commission;B
superb(); commission = commission;C
this.commission = commission; superb();D
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this.commission = commission; super(name, baseSalary);
考题
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2B
3C
4D
0E
1
考题
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0B
1C
2D
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考题
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0B
1C
2D
3
考题
单选题1. interface Animal { 2. void eat(); 3. } 4. 5. // insert code here 6. 7. public class HouseCat implements Feline { 8. public void eat() { } 9. } 和以下三个接口声明: interface Feline extends Animal { } interface Feline extends Animal { void eat(); } interface Feline extends Animal { void eat() { } } 分别插入到第 5 行,有多少行可以编译?()A
0B
1C
2D
3
考题
单选题1. class Animal { Animal getOne() { return new Animal(); } } 2. class Dog extends Animal { 3. // insert code here 4. } 5. 6. class AnimalTest { 7. public static void main(String [] args) { 8. Animal [] animal = { new Animal(), new Dog() } ; 9. for( Animal a : animal) { 10. Animal x = a.getOne(); 11. } 12. } 13. } 和代码: 3a. Dog getOne() { return new Dog(); } 3b. Animal getOne() { return new Dog(); } 第 3 行中插入的哪项将编译且运行无异常?()A
3a行B
3b行C
3a行或3b行D
既非3a,也非3b
考题
单选题class Animal{ Animal getOne(){return new Animal();}} class Dog extends Animal{ //insert code here } class AnimalTest{ public static void main(String[] args){ Animal[] animal={ new Animal(), new Dog()}; for(Animal a:animal){ Animal x= a.getOne(); } } } 和代码: 3a.Dog getOne() { return new Dog();} 3b.Animal getOne() { return new Dog();} 第3行中插入的哪项编译且运行无异常?A
3a行或3b行B
既非3a,也非3bC
3a行D
3b行
考题
多选题现有: 1. class Synapse { 2. protected int gap() { return 7; } 3. } 4. 5. class Creb extends Synapse { 6. // insert code here 7. } 分别插入到第 6 行,哪三行可以编译?()Aint gap() { return 7; }Bpublic int gap() { return 7; }Cprivate int gap(int x) { return 7; }Dprotected Creb gap() { return this; }Epublic int gap() { return Integer.getInteger (42); }
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