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阅读程序:
FunctionF(aAsInteger)AsInteger
b=0
Staticc
b=b+1
c=c+1
F=a+b+c
EndFunction
PrivateSubCommand1_Click()
DimaAsInteger
a=2
ForI=1To3
PrintF( )
NextI
EndSub
运行结果为( )
A.4和5和6
B.4和4和4
C.5和5和6
D.6和6和6
参考答案
更多 “ 阅读程序:FunctionF(aAsInteger)AsIntegerb=0Staticcb=b+1c=c+1F=a+b+cEndFunctionPrivateSubCommand1_Click()DimaAsIntegera=2ForI=1To3PrintF( )NextIEndSub运行结果为( )A.4和5和6B.4和4和4C.5和5和6D.6和6和6 ” 相关考题
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