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String与StringBuffer的区别,以及"+"与append的区别?
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下面是一段javabean程序,该程序的运行结果是( )。public class NullTest{public static void main(String[]?args){int M=0;String str=null;StringBuffer sb=new StringBuffer("=");sb.append(str);sb.append(M++);System.out.println(sb.toString( ));}}A.=null
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String与StringBuffer的区别()。A、String是不可变的对象,StringBuffer是可以再编辑的B、String是常量,StringBuffer是变量C、String是可变的对象,StringBuffer是不可以再编辑的D、以上说法都不正确
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String与StringBuffer最大的区别在于()A、它们没有区别B、String对原字符串的拷贝进行操作,而StringBuffer对原字符串本事操作C、StringBuffer拥有更多相关函数D、String更节省空间
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关于String,StringBuilder以及StringBuffer,描述错误的是()。A、对String对象的任何改变都不影响到原对象,相关的任何change操作都会生成新的对象B、StringBuffer是线程安全C、StringBuilder是线程安全D、可以修改StringBuilder和StringBuffer的内容
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Given this method in a class: public String toString() { StringBuffer buffer = new StringBuffer(); buffer.append(‟‟); buffer.append(this.name); buffer.append(‟‟); return buffer.toString(); } Which is true?() A、 This code is NOT thread-safe.B、 The programmer can replace StringBuffer with StringBuilder with no other changes.C、 This code will perform well and converting the code to use StringBuilder will not enhance the performance.D、 This code will perform poorly. For better performance, the code should be rewritten: return ““+ this.name + “”;
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Public class test ( Public static void stringReplace (String text) ( Text = text.replace (‘j’ , ‘i’); ) public static void bufferReplace (StringBuffer text) ( text = text.append (“C”) ) public static void main (String args[]} ( String textString = new String (“java”); StringBuffer text BufferString = new StringBuffer (“java”); stringReplace (textString); bufferReplace (textBuffer); System.out.printLn (textString + textBuffer); ) ) What is the output?()
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以下语句的含义是() char[] arrcrlf={13,10}; String crlf=new String(arrcrlf); stringBuffer dest = new StringBuffer("西行漫记"); dest.append(crlf); A、字符串"西行漫记"不变B、字符串"西行漫记"的最后一个字被删除C、语句存在语法错误D、在字符串"西行漫记"的后面加回车换行符
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单选题Given this method in a class: public String toString() { StringBuffer buffer = new StringBuffer(); buffer.append(‟‟); return buffer.toString(); } Which is true?()A
This code is NOT thread-safe.B
The programmer can replace StringBuffer with StringBuilder with no other changes.C
This code will perform well and converting the code to use StringBuilder will not enhance the performance.D
This code will perform poorly. For better performance, the code should be rewritten: return ““+ this.name + “”;
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填空题Public class test ( Public static void stringReplace (String text) ( Text = text.replace (‘j’ , ‘i’); ) public static void bufferReplace (StringBuffer text) ( text = text.append (“C”) ) public static void main (String args[]} ( String textString = new String (“java”); StringBuffer text BufferString = new StringBuffer (“java”); stringReplace (textString); BufferReplace (textBuffer); System.out.printLn (textString + textBuffer); ) ) What is the output?()
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单选题以下语句的含义是() char[] arrcrlf={13,10}; String crlf=new String(arrcrlf); stringBuffer dest = new StringBuffer("西行漫记"); dest.append(crlf);A
字符串西行漫记不变B
字符串西行漫记的最后一个字被删除C
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它们没有区别B
String对原字符串的拷贝进行操作,而StringBuffer对原字符串本事操作C
StringBuffer拥有更多相关函数D
String更节省空间
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问答题STRING与STRINGBUFFER的区别是什么?
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