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有以下程序段 includemain(){ char s[4][10];int i;scanf("%s%s",s[0],s[1]);gets(s[2
有以下程序段 # include<stdio.h> main() { char s[4][10]; int i; scanf("%s%s",s[0],s[1]);gets(s[2])gets(s[3]); for(i=0;i<4;i++) puts(s[i]); } 输入数据如下,aaaa bbbb<CR>(此处<CR>代表回车符) cccc dddd<CR> 输出结果是( )
A.aaaa bbbb cccc dddd
B.aaaa bbbb cccc dddd
C.aaaa bbbb cccc dddd eeee
D.aaaa bbbb cccc dddd
参考答案
更多 “ 有以下程序段 includemain(){ char s[4][10];int i;scanf("%s%s",s[0],s[1]);gets(s[2 有以下程序段 # include<stdio.h> main() { char s[4][10]; int i; scanf("%s%s",s[0],s[1]);gets(s[2])gets(s[3]); for(i=0;i<4;i++) puts(s[i]); } 输入数据如下,aaaa bbbb<CR>(此处<CR>代表回车符) cccc dddd<CR> 输出结果是( )A.aaaa bbbb cccc ddddB.aaaa bbbb cccc ddddC.aaaa bbbb cccc dddd eeeeD.aaaa bbbb cccc dddd ” 相关考题
考题
有以下程序inclUdevoidfun(int*s,intn1,intn2){inti,j,t;i=n1;j=n2;while(i
有以下程序 #inclUde <stdio.h> void fun(int *s,int n1,int n2) { int i,j,t; i=n1; j=n2; while(i<j) {t=s[i];s[i]=s[j];s[j]=t;i++;j--;} } main() { int a[10]={1,2,3,4,5,6,7,8,9,0},k; fun(a,0,3); fun(a,4A.0987654321B.4321098765C.5678901234D.0987651234
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有下列程序: include include "string.h" void tim(char *s[],int n)
有下列程序: #include <stdio.h> #include "string.h" void tim(char *s[],int n) { char *t;int i,j; for(i=0;i<n-1;i++) for(j=i+1;j<n;j++) if(strlen(s[i])>strlen(s[j])) {t=s[i];s[i]=s[j];s[j]=t;} } main() { char *ss[]= {"bcc","bbcc","xy","aaaacc","aabcc"}; fun(ss,5);printf("%s,%s\n",ss[0],ss[4]); } 程序的运行结果是( )。A.xy,aaaaccB.aaaacc,xyC.bcc,aabccD.aabcc,bcc
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对于下面的程序includeincludechar *scmp(char*s1,char*s2){if(strcmp(s1,
对于下面的程序 #include<stdio.h> #include<string.h> char *scmp(char*s1,char*s2) { if(strcmp(s1,s2)<0)return(s1); else return(s2); } main() { int i:char string[20],sb[3][20]; for(i=0;i<3;i++)gets(str[i]); strcpy(string,scmp(str[0],str[1])); strcpy(string,scmp(string,str[21)); printf("%s\n",string); } 若运行时依次输入abcd、abba和abc三个字符串,则输出结果为______。A.abcdB.abbaC.abcD.abca
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有以下程序:includeincludevoid fun(char*s[],int n){char*t;int i,j;for(
有以下程序: #include<stdio.h> #include<string.h> void fun(char*s[],int n) { char*t;int i,j; for(i=0;i<n-1;i++) for(j=i+1;j<n;j++) if(strlen(s[i])>strlen(s[j])){t=s[i];s[i]=s[j];s[j]=t;} } main() { Char*ss[]={"bcc","bbcc","xy","aaaacc","aabcc"}; fun(ss,5);printf("%s,%s\n",ss[0],ss[4]); } 程序的运行结果是( )。A.xy,aaaaccB.aaaacc,xyC.bcc,aabccD.aabcc,bcc
考题
对于下面的程序includeincludechar * scmp(char * s1,char * s2){if(strcm
对于下面的程序 #include<stdio.h> #include<string.h> char * scmp(char * s1,char * s2) { if(strcmp(s1,s2)<0)return(s1); else return(s2); } main() { int i;char string[20],str[3][20]; for(i=0;i<3;i++)gets(str[i]); strcpy(string,scmp(str[0],str[1])); strcpy(string,scmp(string,str[2])); printf("%s\n",string); } 若运行时依次输入abcd、abba和abc三个字符串,则输出结果为 ______。A.abcdB.abbaC.abcD.abca
考题
有以下程序includeincludevoidfun(char*s[],intn){char*t;int i,j;for(i=0
有以下程序 #include <stdio.h> #include <string.h> void fun(char *s[],int n) { char *t; int i,j; for(i=0;i<n-1;++) for(j=i+1;j<n;j++) if(strlen(s[i])>strlen(s[j])) {t=s[i];s[i];s[j];s[j]=t;} } main() { char *ss[]={"bccA.xy,aaaaccB.aaaacc,xyC.bcc,aabccD.aabcc,bcc
考题
有以下程序:includeinclude"string.h"void fun(char*s[],int n){char*t;int i,j;for(
有以下程序: #include<stdio.h> #include"string.h" void fun(char*s[],int n) { char*t;int i,j; for(i=0;i<n-1;i++) for(j=i+1;j<n;j++) if(strlen(s[i])>strlen(s[j])){t=s[i];s[i]=s[j];s[j]=t;} } main() { char*ss[]={"bee","bbcc","xy","aaaacc","aabcc"}; fun(ss,5);printf("%s,%s\n",ss[0],ss[4]); } 程序的运行结果是( )。A.xy,aaaaccB.aaaacc,xyC.bcc,aabccD.aabcc,bcc
考题
设有如下程序段: main() { char s[4][20]; int i; scanf("%s%s",s[0],s[1]); gets(s[2]);gets(s[3]); for(i=0;i<4;i++) puts(s[i]); } 输入数据如下:(此处<CR>代表回车符) aa bb<CR> cc dd<CR> 则程序的输出结果是______。A.aa bb ccddB.aa bb cc ddC.aa bb cc ddD.aa bb cc dd
考题
有以下程序includeincludevoidfun(char,*s[],intn){char*t;inti,j; for(i=
有以下程序 #include <stdio.h> #include <string.h> void fun(char,*s[],int n) { char *t; int i,j; for(i=0;i<n-1;i++) for(j=i+1;j<n;j++) if(strlen(s[i])>strlen(s[j])) {t=s[i];s[i]:s[j];s[j]=t;} } main() { char *ss[]={"bcc","bbcc","xy","aaaacc","aabcc"}; fun(ss,5); printf("%s,%s\n",ss[0],ss[4]); } 程序的运行结果是A.xy,aaaaccB.aaaacc,xyC.bcc,aabccD.aabcc,bcc
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