网友您好， 请在下方输入框内输入要搜索的题目：
题目内容
（请给出正确答案）
For the network 192.0.2.0/23, which option is a valid IP address that can be assigned to a host?（）
- A、192.0.2.0
- B、192.0.2.255
- C、192.0.3.255
- D、192.0.4.0
参考答案
更多 “For the network 192.0.2.0/23, which option is a valid IP address that can be assigned to a host?（）A、192.0.2.0B、192.0.2.255C、192.0.3.255D、192.0.4.0” 相关考题
考题
Basic question types are __________.
A.yes-no questionB.or question and wh-questionC.yes-no questionD.tag question and wh-question
考题
理论塔板数为（ ）。A．n=5.44(tR/Wh/2)B．n=5.54(tR/Wh/2)C．n=5.54(tR/W)2D．n=5.44(tR/Wh/2)2E．n=5.54(tR/Wh/2)2
考题
删除仓库关系中仓库号值为WH2的元组，应使用命令A．DELETE FROM 仓库 WHERE 仓库号=＂WH2＂B．DROP FROM 仓库 WHERE 仓库号=＂WH2＂C．DELETE 仓库 WHERE 仓库号=＂WH2＂D．DROP FROM仓库 WHERE 仓库号=WH2
考题
When a sentence changes from a statement to a general／ special question, which movement is struc－turally required
A NP–movement/WH-movementB NP–movement/Aux-movementC AUX-movement/WH–movementD WH–movement/AUX-movement
考题
在烃湿度值法解释油气层时,下列参数可以解释为气层的一组是()。
A、Wh=10，Bh=80B、Wh=60，Bh=20，Ch=0.1C、Wh=20，Bh=15，Ch=0.3D、Wh=0.4，Bh=110
考题
利用烃湿度值法也可以解释气测异常,下列参数中可以解释为油层的一组是()。
A、Wh=28.5，Bh=19，Ch=0.15B、Wh=0.5，Bh=120，Ch=0.03C、Wh=1.0，Bh=100.5，Ch=0.05D、Wh=80，Bh=2.05，Ch=0.01
考题
在SQL语句中，与表达式“仓库号NOT IN(“wh1”，“wh2”)”功能相同的表达式是A．仓库号=“wh1”AND仓库号：“wh2”B．仓库号!=“wh1”OR仓库号：=“wh2”C．仓库号＜＞“wh1”OR仓库号!=“wh2”D．仓库号!=“wh1”AND仓库号!=“wh2”
考题
在SQL语句中，与表达式“仓库号NOT IN("whl","wh2")”功能相同的表达式是 ______。A．仓库号="wh1" AND仓库号="wh2"B．仓库号!="wh1"OR仓库号#"wh2"，C．仓库号＜＞"wh1" OR仓库号!"wh2"D．仓库号户'whl，tAND仓库号!：”wh2”
考题
在SQL语句中，与表达式“仓库号NOT IN（"whl ","wh2")”功能相同的表达式是A）仓库号="wh1"AND仓库号="wh2"B）仓库号!="whl" OR仓库号="wh2"C) 仓库号"wh 1" OR仓库号！="wh2"D）仓库号!="whl" AND仓库号!= "wh2"
考题
执行下列sQL语句后，显示查询到的仓库号有( )。 SELECT DISTINCT仓库号FROM职工WHERE工 资=ALL (SELECT工资FROM职工WHERE仓库号 一”WH3”)A.WHlB.WH2C.WH4D.WHl、WH3
考题
请参见图示。公司的新安全策略允许来自工程部LAN的所有IP流量访问Internet，但对于来自营销部LAN的流量，则只允许其中的web流量访问Internet。为实施新的安全策略，可在营销部路由器的Serial0/1接口的出站方向上应用哪一ACL()A.access-list 197 permit ip 192.0.2.0 0.0.0.255 any access-list 197 permit ip 198.18.112.0 0.0.0.255 any eq wwwB.access-list 165 permit ip 192.0.2.0 0.0.0.255 any access-list 165 permit tcp 198.18.112.0 0.0.0.255 any eq www access-list 165 permit ip any anyC.access-list 137 permit ip 192.0.2.0 0.0.0.255 any access-list 137 permit tcp 198.18.112.0 0.0.0.255 any eq wwwD.access-list 89 permit 192.0.2.0 0.0.0.255 any access-list 89 permit tcp 198.18.112.0 0.0.0.255 any eq www
考题
下列SQL语句能实现的功能是( )。 SELECT*FROM 仓库 WHERE 仓库号="WH1"; UNION; SELECT * FROM 仓库 WHERE 仓库号="WH2"A．查询在WH1或者WH2仓库中的职工信息B．查询仓库号为WH1或者WH2的仓库信息C．查询即在仓库号为WH1，又在仓库号为WH2工作的职工信息D．语句错误，不能执行
考题
For the network 192.0.2.0／23, which option is a valid IP address that can be assigned to a host?()
A.192.0.2.0B.192.0.2.255C.192.0.3.255D.192.0.4.0
考题
给出在仓库“WHl”或“WH2”工作，且年龄小于40岁的职工号和姓名，正确的命令是（ ）。A)SELECT 职工号，姓名 FROM 职工：WHERE 年龄40 AND 仓库号=”WH1”OR 仓库号=”WH2”B)SELECT职工号，姓名 FROM 职工；WHERE年龄40 AND(仓库号=”WH1”AND 仓库号=”WH2”)C)SELECT职工号，姓名 FROM 职工；WHERE年龄40 OR 工仓库号=”WH1”OR 仓库号=”WH2”D)SELECT职工号，姓名 FROM 职工：WHERE年龄40 AND(仓库号=”WH1”OR 仓库号=”WH2”)
考题
在烃湿度值法解释油气层时，下列参数可以解释为气层的一组是（）。A、Wh=10，Bh＝80B、Wh=60，Bh=20，Ch＝O.1C、Wh=20，Bh＝15，Ch=O.3D、Wh＝0.4，Bh＝110
考题
You have been asked to use a 23-bit network mask to segment the network block 209.18.12.0, How many usable host address will there e per subnet?（）A、510B、1022C、2046D、8190
考题
Your company is designing its public network. The network will use an IPv4 range of 131.107.40.0/22.The network must be configured as shown in the following exhibit.You need to configure subnets for each segment. Which network addresses should you assign？（）A、Segment A: 131.107.40.0/23 Segment B: 131.107.42.0/24 Segment C: 131.107.43.0/25 Segment D: 131.107.43.128/27B、Segment A: 131.107.40.0/25 Segment B: 131.107.40.128/26 Segment C: 131.107.43.192/27 Segment D: 131.107.43.224/30C、Segment A: 131.107.40.0/23 Segment B: 131.107.41.0/24Segment C: 131.107.41.128/25 Segment D: 131.107.43.0/27D、Segment A: 131.107.40.128/23 Segment B: 131.107.43.0/24Segment C: 131.107.44.0/25 Segment D: 131.107.44.128/27
考题
单选题For the network 192.0.2.0/23, which option is a valid IP address that can be assigned to a host?（）A
192.0.2.0B
192.0.2.255C
192.0.3.255D
192.0.4.0
考题
单选题You are the network administrator for your company. The Denver office is currently connected to the corporate WAN by using a Windows Server 2003 computer named Server23.Server23 is configured as a dial-up router. Server23 has two network adapters. One network adapter connects to the Ethernet LAN. The other network adapter is a broadband networking device.The company plans to increase the number of employees in the Denver office by at least 25 percent. You need to confirm that the current network bandwidth of the broadband connection will be sufficient for the future expansion of the Denver office.You want to use System Monitor on Server23 to find out the current utilization of the broadband network connection. What should you do？（）A
Monitor the Bytes Total/sec counter on the Network Interface object.B
Monitor the Bytes Total/sec counter on the Server object.C
Monitor the Server//Packets/sec counter on the Server object.D
Monitor the Current Bandwidth counter on the Network Interface object.
考题
单选题You have been asked to use a 23-bit network mask to segment the network block 209.18.12.0.How many usable host addresses will there be per subnet?（）A
510B
1022C
2046D
8190
考题
单选题Which network mask is the equivalent of 255.255.248.0?（）A
/20B
/21C
/22D
/23
热门标签
最新试卷