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当计算电抗Xjs大于3.45时,可以认为短路电流周期分量不随时间变化,其有效值按公式1/Xjs计算。
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更多 “当计算电抗Xjs大于3.45时,可以认为短路电流周期分量不随时间变化,其有效值按公式1/Xjs计算。” 相关考题
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( 27 )要想在过程 Proc 调用后返回形参 x 和 Y 的变化结果,下列定义语句中正确的是A ) Sub Proc ( x as Integer,y as Integer )B ) Sub Proc ( ByVal x as Integer, y as Integer )C ) Sub Proc ( x as Integer,Byval y as Integer )D ) Sub Proc ( Byval x as Integer, Byval y as Integer )
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有以下程序:int sub(int n) { return(n/10+n%10); }void main(){ int x,y; scanf("%d",x); y=sub(sub(sub(x))); printf("%d\n",y);}若运行时输入:4321回车,程序的输出结果是。
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以下能够正确计算n!的程序是( )。A.Private Sub Command1_Click()n=5: x=1Dox=x * II=I + 1Loop While I nPrint xEnd SubB.Private Sub Command1_Click()n=5: x=1: I=1Dox=x * II=I + 1Loop While I nPrint xEnd SubC.Private Sub Command1_Click()n=5: x=1: I=1Dox=x * II=I + 1Loop While I =nPrint xEnd SubD.Private Sub Command1_Click()n=5: x=1: I=1Dox=x * II=I + 1Loop While I nPrint xEnd Sub
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下列程序用来计算1+2+…n,当和大于100时停止计算,请填空。Private Sub Form_Click()Dim n as integer,s as integer,I as integer,k as integers=0k=0n=inputbox(″请输入n的值)For i=1 to 100k=k+1s=s+I【 】Next iPrint sEnd Sub
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以下过程的定义中,( )是错误的。
A、Public Sub Sum(x ; y)B、Public Sub Sum(ByVal x, ByVal y)C、Public Sub Sum(x As Integer,y As Integer)D、Public Sub Sum(x%, y%)
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以下程序的输出结果是【 】。main(){ int x=0;sub(x,8,1);printf(“%d\n”,x);}sub(int *a,int n,int k){ if(k<=n)sub(a,n/2,2*k);*a+=k;}
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下面各被调用函数首部书写正确的是( )A.void sub(float x;float y);B.void sub(float x,y)C.void sub(float x,float y)D.void sub(float x,float y);
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在窗体中添加一个名称为Command1的命令按钮,然后编写如下程序: Public x As Integer Private Sub Command1_Click() x=10 Call s1 Call s2 MSgBox x End Sub Private Sub s1() x=x+20 End Sub Private Sub s2() Dim x As Integer x=X+20 End Sub 窗体打开运行后,单击命令按钮,则消息框的输出结果为______。A.10B.30C.40D.50
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下面程序是由鼠标事件在窗体上画图,如果按下鼠标可以画图,双击窗体则可以清除所画图形。补充完整下面的程序。首先在窗体层定义如下变量:Dim PaintStart As Boolean编写如下事件过程:Private Sub Form_Load()DrawWidth=2ForeColor=vbGreenEnd SubPrivate Sub Form_MouseDown(Button As Integer,Shift As Integer,X AS Single,Y AS Single)PaintStart=TrueEnd SubPrivate Sub Form_MouseMove(Button As Integer,Shift As Integer,X As Single,Y As Single)If PaintStart ThenPSet(X,Y)End IfEnd SubPrivate Sub Form_MouseUp(Button As Integer,Shift As Integer,X As Single,Y As Single)End SubPrivate Sub Form_DblClick()ClsEnd Sub
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有以下程序:int sub(int n) { return(n/10+n%10); }main(){ int x, y;scanf("% d", x);y=sub(sub(sub(x)));printf("% d\n", y);}若运行时输入:1234<回车>,程序的输出结果是【 】。
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以下能够正确计算n!的程序是A.Private Sub Command1 Click() n=5:x=1 Do x=x * I I=I + 1 Loop While I < n Print x End SubB.Private Sub Command1_Click() n=5:X=1:I=1 Do X=X*I I=I + 1 Loop While I <n Print x End SubC.Private Sub Command1_Click() n=5:X=1:I=1 Do X=X * I I=I + 1 Loop While I<=n Print X End SubD.Private Sub Command1_Click() n=5:X=1:I=1 Do x=x * I I=I + 1 Loop While I>n Print X End Sub
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下列程序的功能是:当x100时, Private Sub Command1_
下列程序的功能是:当x<50时,y =0.8 xx;当50≤x≤100时,y=0.7 xx;当x>100时,Private Sub Command1_Click()Dim x As Singlex = InputBox("请输入x的值" )Select Case xCase Is<50y=0.8 * xCase 50 To 100y=0.7 * x【 】Print "输入数据出界!"End SelectPrint x, yEnd Sub
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有如下程序: Private Sub Command1_Click() Dim a As Single Dim b As Single a=5:b=4 Call Sub1(a,b) End Sub Sub Sub1(x As Single,y As Single) t=X X=t\Y Y=t Mod y End Sub 在调用运行上述程序后,a和b的值分别为A.0 0B. 1 1C.2 2D.1 2
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若有以下变量和函数说明:includecharCh='*';void sub(int x,int y,char ch,double*
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执行下面程序,第一行输出结果是【 】,第二行输出结果是47。Option ExplicitPrivate Sub Form_Click( )Dim A As IntegerA=2Call Sub1 (A) End SubPrivate Sub1 (x As Integer)x=x*2+1If x<10 ThenCall Sub1 (x)End Ifx=x*2+1Print xEnd Sub
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在窗体中添加一个名称为Commandl的命令按钮,然后编写如下程序:Public X As Integer Private Sub Commandl Click( )x=10 Call slCall s2MsgBox x End Sub Private Sub sl( )x=x+20 End Sub Private Sub s2( )Dim x As Integer x=x+20End Sub窗体打开运行后,单击命令按钮,则消息框的输出结果为( )。A.10B.30C.40D.50
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msub0/sub<msube/sub<(xB
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msub0/sub>msube/sub>(xD
msube/sub<msub0/sub<(x
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CALL SUB(N,N)B
CALL SUB(X,X)C
CALL SUB(N+2,X)D
CALL SUB(N,X+3)
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