网友您好, 请在下方输入框内输入要搜索的题目:

题目内容 (请给出正确答案)
() is the volume of chemical goods.

A.Constantly growing too

B.Too constantly growing

C.Growing constant to

D.Too growing constant


参考答案

更多 “ () is the volume of chemical goods. A.Constantly growing tooB.Too constantly growingC.Growing constant toD.Too growing constant ” 相关考题
考题 在下面的运算符重载函数的原型中,错误的是A.Volume operator-(double,double);B.double Volume::operator-(double);C.Volume Volume::operator-(Volume);D.Volume operator-(Volume,Volume);

考题 在下面的运算符重载函数的原型中,错误的是______ 。A.Volume operator-(double,double);B.double Volume:: operator-(double);C.Volume Volume:: operator-(Volume);D.Volume operator-(Volume,Volume);

考题 下列运算符重载函数的原型错误的是( )。A.Volume operator-(double,double);B.double Volume::operator-(double);C.Volume Volume::operator-(Volume);D.Volume operator-(Volume,Volume);

考题 请把下面程序补充完整,正确答案是( )。 main( ) { float radius,length,area,volume; printf("Input a radius:"); Scanf("%f",radius); length=2.0*PI*radius; /*引用无参宏求周长*/area=PI*radius*redius; /*引用无参宏求而积*/ volume=PI*radius*radius*radius*3/4; /*引用无参宏求体积*/ printf("length=%.2f,area=%.2f,volume=%.2f\n",length,area,volume); }A.PI=3.1415926B.Const PI=3.14159C.#define PI3.1415926D.Float PI=3.14159

考题 Youaredesigningastrategytoimprovetheperformanceandreliabilityofthedomaincontrollers.Whatshouldyoudo?() A.CreateoneRAID-5volume.B.CreatetwoRAID-5volumes.C.CreateonemirroredvolumeandtwoRAID-5volumes.D.CreatetwomirroredvolumesandoneRAID-5volume.

考题 在下面的运算符重载函数的原型中,错误的是( )。A.Volume operator-(double,double);B.double Volume::operator-(double);C.Volume Volume::operator-(Volume);D.Volume operator-(Volume,Volume);

考题 The factory manufactures a ______ of products. A. variety B. mixture C. quality D. volume

考题 在下面的运算符重载函数的原型中,错误的是:A.volume operator-(double,double);B.double volume::operator-(double);C.volume volume ::operator-(volume);D.volume operator-(volume,volume);

考题 假定BOX为一个类,volume()为该类公有的函数成员,x为该类的一个对象,则访问x对象中函数成员volume ()的格式为()。A.x.volume ()B.x. volumeC.x-> volumeD.x-> volume ()

考题 在下面的二目运算符重载函数的原型中,错误的是:A.volume operator-(double,double);B.double volume::operator-(double);C.volume volume ::operator-(volume);D.volume operator-(volume,volume);