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将各个系教师的平均工资定义为视图average_salary. create view average_salary as select dept_name,max（salary) from instructor; group by dept_name;
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更多 “将各个系教师的平均工资定义为视图average_salary. create view average_salary as select dept_name,max（salary) from instructor; group by dept_name;” 相关考题
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建立一个视图salary，该视图包括了系号和(该系的)平均工资两个字段，正确的 SQL语句是A．CREATE VIEW salary AS系号，AVG(工资)AS平均工资FROM教师； GROUP BY系号B．CREATE VIEW salary AS SELECT系号,AVG(工资)AS平均工资FROM教师； GROUP BY系名C．CREATE VIEW salary SELECT系号,AVG(工资)AS平均工资FROM教师； GROUP BY系号D．CREATE VIEW salary AS SELECT系号,AVG(工资)AS平均工资FROM教师； GROUP BY系号
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根据SQL标准，创建一个视图abc，通过该视图只能对表student中系dept为‘IS’的记录进行更新操作。下面哪条语句适用?()A create view abc as select * from student where dept=’IS’B create view abc as select * from student where dept=’IS’ with check optionC create view abc as student where dept=’IS’D create view abc as select dept=’IS’ from student
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Examine the data in the EMPLOYEES table:Which three subqueries work? ()
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Examine the data in the EMPLOYEES table:LAST_NAME DEPARTMENT_ID SALARYGetz 10 3000Davis 20 1500Bill 20 2200Davis 30 5000...Which three subqueries work? ()
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Click the Exhibit button and examine the data in the EMPLOYEES table.Which three subqueries work? ()
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建立一个视图salary，该视图包括了系号和(该系的)平均工资两个字段，正确的SQL语句是（ ）。A.CREATE vIEw salary AS系号．AVG(工资)AS平均工资FRM教师GRUP BY系号B.CREATE VIEW salary AS SELECT 系号，AVG(工 资)AS平均工资FROM教师GROUP BY系名C.CREATE VIEw salary SELECT 系号，AVG(工资)AS平均工资FRM教师 GRUP BY系号D.CREATE VIEW salary AS SELECT系号，AVG(工 资)AS平均工资FRM教师 GROUP BY系号
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建立一个视图salary，该视图包括了系号和(该系的)平均工资两个字段，正确的SQL语句是（ ）。A)CREATE VIEW salary AS系号，AVG(工资)AS平均工资FROM教师；GROUPBY系号B)CREATEVIEW salaryAS SELECT系号，AVG(工资)AS平均工资FROM教师；GROUPBY系名C)CREATE VIEW Salary SELECT系号，AVG(工资)AS平均工资FROM教师；GROUP BY系号D)CREATE VIEW salaryAS SELECT系号，AVG(工资)AS平均工资FROM教师；GROUPBY系号
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有关系模式：学生表（学号，姓名，所在系），建立统计每个系的学生人数的视图的正确语句是（）A、CREATE VIEW v1AS SELECT所在系，COUNT（*）FROM学生表GROUP BY所在系B、CREATEVIEW v1AS SELECT所在系，SUM（*）FROM学生表GROUP BY所在系C、CREATE VIEW v1（系名，人数）AS SELECT所在系，SUM（*）FROM学生表GROUP BY所在系D、CREATE VIEW v1（系名，人数）AS ELECT所在系，COUNT（*）FROM学生表GROUP BY所在系
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Examine the description of the EMPLOYEES table: EMP_ID NUMBER(4) NOT NULL LAST_NAME VARCHAR2(30) NOT NULL FIRST_NAME VARCHAR2(30) DEPT_ID NUMBER(2) JOB_CAT VARCHAR2(30) SALARY NUMBER(8,2) Which statement shows the department ID, minimum salary, and maximum salary paid in that department, only of the minimum salary is less then 5000 and the maximum salary is more than 15000?（）A、SELECT dept_id, MIN(salary(, MAX(salary) FROM employees WHERE MIN(salary) 5000 AND MAX (salary) 15000;B、SELECT dept_id, MIN(salary), MAX(salary) FROM employees WHERE MIN(salary) 5000 AND MAX(salary) 15000 GROUP BY dept_id;C、SELECT dept_id, MIN(salary), MAX(salary) FROM employees HAVING MIN(salary) 5000 AND MAX (salary) 15000;D、SELECT dept_id, MIN(salary), MAX(salary) FROM employees GROUP BY dept_id HAVING MIN (salary) 5000 AND MAX(salary)E、SELECT dept_id, MIN(salary), MAX(salary) FROM employees GROUP BY dept_id, salary HAVING MIN (salary) 5000 AND MAX (salary) 15000;
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Examine the data in the EMPLOYEES table: LAST_NAME DEPARTMENT_ID SALARY Getz 10 3000 Davis 20 1500 Bill 20 2200 Davis 30 5000 ... Which three subqueries work? （）A、SELECT * FROM employees where salary (SELECT MIN(salary) FROM employees GROUP BY department _ id);B、SELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department _ id);C、SELECT distinct department_id FROM employees Where salary ANY (SELECT AVG(salary) FROM employees GROUP BY department _ id);D、SELECT department_id FROM employees WHERE SALARY ALL (SELECT AVG(salary) FROM employees GROUP BY department _ id);E、SELECT last_name FROM employees Where salary ANY (SELECT MAX(salary) FROM employees GROUP BY department _ id);F、SELECT department_id FROM employees WHERE salary ALL (SELECT AVG(salary) FROM employees GROUP BY ANG (SALARY));
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Examine the description of the EMPLOYEES table: EMP_ID NUMBER(4) NOT NULL LAST_NAME VARCHAR2(30) NOT NULL FIRST_NAME VARCHAR2(30) DEPT_ID NUMBER(2) JOB_CAT VARCHARD2(30) SALARY NUMBER(8,2) Which statement shows the maximum salary paid in each job category of each department? （）A、SELECT dept_id, job_cat, MAX(salary) FROM employees WHERE salary MAX (salary);B、SELECT dept_id, job_cat, MAX(salary) FROM employees GROUP BY dept_id,job_cat;C、SELECT dept_id, job_cat, MAX(salary) FROM employees;D、SELECT dept_id, job_cat, MAX(salary) FROM employees GROUP BY dept_id;E、SELECT dept_id, job_cat, MAX(salary) FROM employees GROUP BY dept _ id job _ cat salary;
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单选题根据“职工”表建立一个“部门”视图，该视图包括了部门编号和（该部门的）平均工资两个字段，正确的SQL语句是（ ）。A
CREATE VIEW部门AS部门编号，AVG（工资）AS平均工资FROM职工GROUP BY部门编号B
CREATE VIEW部门AS SELECT部门编号，AVG（工资）AS平均工资FROM职工GROUP BY部门名称C
CREATE VIEW部门SELECT部门编号，AVG（工资）AS平均工资FROM职工GROUP BY部门编号D
CREATE VIEW部门AS SELECT部门编号，AVG（工资）AS平均工资FROM职工GROUP BY部门编号
考题
单选题Examine the structure of the EMPLOYEES table: EMPLOYEE_ID NUMBER Primary Key FIRST_NAME VARCHAR2(25) LAST_NAME VARCHAR2(25) DEPARTMENT_ID NUMBER SALARY NUMBER What is the correct syntax for an inline view?（）A
SELECT a.last_name, a.salary, a.department_id,B
maxsal FROM employees a, (SELECT department_id, max(salary)maxsal FROM employees GROUP BY department_id) b WHERE a.department_id = b.department_id AND a.salary b.maxsal;C
SELECT a.last name, a.salary, a.department_id FROM employees a WHERE a.department_id IN (SELECT department_id FROM employees b GROUP BY department_id having salary = (SELECT max(salary) from employees))D
SELECT a.last_name, a.salary, a.department_id FROM employees a WHERE a.salary = (SELECT max(salary) FROM employees b WHERE a.department _ id = b.department _ id);E
SELECT a.last_name, a.salary, a.department_id FROM employees a WHERE (a.department_id, a.salary) IN (SELECT department_id, a.salary) IN (SELECT department_id max(salary) FROM employees b GROUP BY department_id ORDER BY department _ id);
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单选题Using the report wizard you create a tabular report to display all the columns in the EMP table. The records are ordered by the deptname and job columns. You need to create a hierarchical report that breaks on the deptname and job values. Using the data model how would you create this break structure?（）A
Specify the break order on the gemp group Property palette. B
Specify a break order on the dept_name and job columns property palettes. C
Click and drag the dept_name and jobs column out and above of the gemp group to create a new parent group. D
Change the position of the dept_name and the job columns within the gemp group.
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多选题Examine the data in the EMPLOYEES table: Which three subqueries work? （）ASELECT * FROM employees where salary (SELECT MIN(salary) FROM employees GROUP BY department _ id);BSELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department _ id);CSELECT distinct department_id FROM employees Where salary ANY (SELECT AVG(salary) FROM employees GROUP BY department _ id);DSELECT department_id FROM employees WHERE SALARY ALL (SELECT AVG(salary) FROM employees GROUP BY department _ id);ESELECT last_name FROM employees Where salary ANY (SELECT MAX(salary) FROM employees GROUP BY department _ id);FSELECT department_id FROM employees WHERE salary ALL (SELECT AVG(salary) FROM employees GROUP BY ANG (SALARY));
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多选题Click the Exhibit button and examine the data in the EMPLOYEES table. Which three subqueries work?（）ASELECT * FROM employees where salary (SELECT MIN(salary) FROM employees GROUP BY department_id);BSELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department_id);CSELECT distinct department_id FROM employees WHERE salary ANY (SELECT AVG(salary) FROM employees GROUP BY department_id);DSELECT department_id FROM employees WHERE salary ALL (SELECT AVG(salary) FROM employees GROUP BY department_id);ESELECT last_name FROM employees WHERE salary ANY (SELECT MAX(salary) FROM employees GROUP BY department_id);FSELECT department_id FROM employees WHERE salary ALL (SELECT AVG(salary) FROM employees GROUP BY AVG(SALARY));
考题
多选题Examine the data in the EMPLOYEES table: LAST_NAME DEPARTMENT_ID SALARY Getz 10 3000 Davis 20 1500 Bill 20 2200 Davis 30 5000 ... Which three subqueries work? （）ASELECT * FROM employees where salary (SELECT MIN(salary) FROM employees GROUP BY department _ id);BSELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department _ id);CSELECT distinct department_id FROM employees Where salary ANY (SELECT AVG(salary) FROM employees GROUP BY department _ id);DSELECT department_id FROM employees WHERE SALARY ALL (SELECT AVG(salary) FROM employees GROUP BY department _ id);ESELECT last_name FROM employees Where salary ANY (SELECT MAX(salary) FROM employees GROUP BY department _ id);FSELECT department_id FROM employees WHERE salary ALL (SELECT AVG(salary) FROM employees GROUP BY ANG (SALARY));
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