网友您好， 请在下方输入框内输入要搜索的题目：
题目内容
（请给出正确答案）
判断题
Autoresizing只可以通过Interface Builder实现。
A
对
B
错
参考答案
参考解析
解析：
暂无解析
更多 “判断题Autoresizing只可以通过Interface Builder实现。A 对B 错” 相关考题
考题
要实现设备的所有接口,都开启BFD与OSPF联动功能的命令是:()
A.bfd enableB.bfd all-interface enableC.all-interface bfd enableD.undo bfdall-interface disable
考题
下面哪条语句可以构造正确的对话框()。
A.AlertDialog dialog=new AlertDialog(context);B.AlertDialog.Builder builder=new AlertDialog.Builder(context);C.ProgressDialog dialog=new ProgressDialog();D.ProgressDialog.Builder builder=new ProgressDialog.Builder(context);
考题
阅读以下说明和Java代码，回答问题[说明]在某些系统中，存在非常复杂的对象，可以采用循序渐进的方式进行组合将小对象组合，成复杂的对象。以下实例展示了Builder(生成器)模式。该实例用来建立“文件”，文件内容包括：一个标题、一串字符以及一些有项目符号的项目。Builder类规定组成文件的方法，Director类利用这个方法产生一份具体的文件。图6-1显示了各个类间的关系。以下是Java语言实现，能够正确编译通过。[Java代码]//Builder. java文件public (1) class Builder {public abstract void makeTitle(String title);public abstract void makeString(String str);public abstract void makeItems(String[] items);public abstract Object getResult();}//Director. java文件public class Director{private (2) builder;public Director(Builder builder){this. builder = builder;}public Object construct(){builder.makeTitle("Greeting");builder.makeString("从早上到白天结束");builder.makeItems(new String[]{"早安", "午安",});builder.makeString("到了晚上");builder.makeItems(new String[]("晚安", "好梦",});return builder.getResult();}}//TextBuilder.java文件public class TextBuilder (3) Builder{private StringBuffer buffer = new StringBuffer();public void makeTitle(String title){buffer.append("『" + title + "』"\n\n");}public void makeString(String str){buffer.append('■' + str + "\n\n ");}public void makeItems(String[] items){for(int i = 0; i (4) ; i++){buffer.append('·' + items[i] + "\n");}buffer.append("\n");}public Object getResult(){return buffer.toString();}}//Main.java文件public class Main {public static void main(String[] args) {Director director = new Director(new TextBuilder());String result = (String)director. (5) ;System.out.println(result);
考题
阅读下列说明和 Java 代码,将应填入(n)处的字句写在答题纸的对应栏内。
【说明】
生成器( Builder)模式的意图是将一个复杂对象的构建与它的表示分离,使得同样的构建过程可以创建不同的表示。图 6-1 所示为其类图。
阅读下列说明和C++代码，将应填入（n）处的字句写在答题纸的对应栏内。
【说明】
???? 生成器（Builder）模式的意图是将一个复杂对象的构建与它的表示分离，使得同样的构建过程可以创建不同的表示。图5-1所示为其类图。
?
【C++代码】
#include
#include
using namespace std;
class Product {
private:?
string partA, partB;
public:?
Product() {?? }? ?
void setPartA(const string}
???? void setPartB(const string}? ?
//? 其余代码省略
};
class Builder {
public:? ? ??
（1）??
;?
virtual void buildPartB()=0;? ? ?
（2）??
;
};
class ConcreteBuilder1 : public Builder {
private:?
Product*?? product;
public:
ConcreteBuilder1() {product = new Product();???? }
void buildPartA() {????? （3）???? ("Component
A"); }?
void buildPartB() {????? （4）???? ("Component
B"); }??
Product* getResult() { return product; }
//? 其余代码省略
};
class ConcreteBuilder2 : public Builder {? ??? ? ? ?
/*??? 代码省略??? */
};
class Director {
private:? ??
Builder* builder;
public:??
Director(Builder* pBuilder) { builder= pBuilder;}? ??
void construct() {
????????????????? （5）???? ;
?????????????? //? 其余代码省略? ?
}??
//? 其余代码省略
};
int main() {? ? ??
Director* director1 = new Director(new ConcreteBuilder1());? ?
director1->construct();? ? ??
delete director1;? ? ?
return 0;
【Java代码】
import jav（6）A.util.*;
class Product {? ? ? ?
private String partA;? ? ? ?
private String partB;? ? ? ??
public Product() {}? ? ??
public void setPartA(String s) { partA = s; }? ? ? ?
public void setPartB(String s) { partB = s; }
}
interface Builder {? ?
public?????? （1）???? ;? ??
public void buildPartB();? ? ??
public?????? （2）???? ;
}
class ConcreteBuilder1 implements Builder {? ? ? ?
private Product product;? ? ? ?
public ConcreteBuilder1() { product = new Product();?? }? ? ? ??
public void buildPartA() {????????
（3）??
("Component A"); }
public void buildPartB() {???? ????（4）?? ("Component B"); }? ? ??
public Product getResult() { return product;}
}
class ConcreteBuilder2 implements Builder {?? ? ? ? ?
//? 代码省略
}
class Director {? ? ? ?
private Builder builder;? ? ? ?
public Director(Builder builder) {this.builder = builder; }
public void construct() {
? ? ? ? ? ? ? ? ? （5）???? ;
? ? ? ? ? ? ? //? 代码省略? ? ??
}
}
class Test {? ? ??
public static void main(String[] args) {
???????????????? Director director1 = new
Director(new ConcreteBuilder1());
???????????????? director1.construct();? ? ? ??
}
考题
客户的路由器通过DCC的方式接入运营商网络，那么在路由器上如下哪些接口可以实现DCC拨号？（）A、Dialer interfaceB、Serial interfaceC、Async interfaceD、PRI interface
考题
The IT department is creating a human resources application that will require several new tables. You need to develop a standard alone executable that will defines these tables and their relationships. Which developer/2000 component could you use to create the executable?（）A、Procedure builder. B、Query builder. C、Schema builder. D、Form builder. E、Project builder. F、Transactional builder.
考题
单选题要实现设备的所有接口，都开启BFD与OSPF联动（）A
Bfd enableB
Bfd all-interfaceenableC
All-interface bfd enableD
Undo bfd all-interface disable
考题
单选题The IT department is creating a human resources application that will require several new tables. You need to develop a standard alone executable that will defines these tables and their relationships. Which developer/2000 component could you use to create the executable?（）A
Procedure builder. B
Query builder. C
Schema builder. D
Form builder. E
Project builder. F
Transactional builder.
考题
判断题Size Class只能在Interface Builder中来使用。A
对B
错
热门标签
最新试卷