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单选题
The EMPLOYEES table contains these columns: LAST_NAME VARCHAR2 (25) SALARY NUMBER (6,2) COMMISSION_PCT NUMBER (6) You need to write a query that will produce these results: 1. Display the salary multiplied by the commission_pct. 2. Exclude employees with a zero commission_pct. 3. Display a zero for employees with a null commission value. Evaluate the SQL statement: SELECT LAST_NAME, SALARY*COMMISSION_PCT FROM EMPLOYEES WHERE COMMISSION_PCT IS NOT NULL; What does the statement provide? （）
A
All of the desired results
B
Two of the desired results
C
One of the desired results
D
An error statement
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更多 “单选题The EMPLOYEES table contains these columns: LAST_NAME VARCHAR2 (25) SALARY NUMBER (6,2) COMMISSION_PCT NUMBER (6) You need to write a query that will produce these results: 1. Display the salary multiplied by the commission_pct. 2. Exclude employees with a zero commission_pct. 3. Display a zero for employees with a null commission value. Evaluate the SQL statement: SELECT LAST_NAME, SALARY*COMMISSION_PCT FROM EMPLOYEES WHERE COMMISSION_PCT IS NOT NULL; What does the statement provide? （）A All of the desired resultsB Two of the desired resultsC One of the desired resultsD An error statement” 相关考题
考题
The EMPLOYEES table contains these columns:LAST_NAME VARCHAR2 (25)SALARY NUMBER (6,2)COMMISSION_PCT NUMBER (6)You need to write a query that will produce these results:1. Display the salary multiplied by the commission_pct.2. Exclude employees with a zero commission_pct.3. Display a zero for employees with a null commission value. Evaluate the SQL statement:SELECT LAST_NAME, SALARY*COMMISSION_PCT FROM EMPLOYEESWHERE COMMISSION_PCT IS NOT NULL;What does the statement provide? （）A. All of the desired resultsB. Two of the desired resultsC. One of the desired resultsD. An error statement
考题
The EMPLOYEES table contains these columns:You need to write a query that will produce these results:1. Display the salary multiplied by the commission_pct.2. Exclude employees with a zero commission_pct.3. Display a zero for employees with a null commission value.Evaluate the SQL statement:What does the statement provide?（）A. All of the desired resultsB. Two of the desired resultsC. One of the desired resultsD. An error statement
考题
The EMP table contains these columns: LAST_NAME VARCHAR2 (25) SALARY NUMBER (6,2) DEPARTMENT_ID NUMBER (6) You need to display the employees who have not been assigned to any department. You write the SELECT statement: SELECT LAST_NAME, SALARY, DEPARTMENT_ID FROM EMP WHERE DEPARTMENT_ID = NULL; What is true about this SQL statement ?（） A、The SQL statement displays the desired results.B、The column in the WHERE clause should be changed to display the desired results.C、The operator in the WHERE clause should be changed to display the desired results.D、The WHERE clause should be changed to use an outer join to display the desired results.
考题
Examine the description of the EMPLOYEES table: EMP_ID NUMBER(4) NOT NULL LAST_NAME VARCHAR2(30) NOT NULL FIRST_NAME VARCHAR2(30) DEPT_ID NUMBER(2) Which statement produces the number of different departments that have employees with last name Smith?（）A、SELECT COUNT(*) FROM employees WHERE last_name='Smith';B、SELECT COUNT(dept_id) FROM employees WHERE last_name='Smith';C、SELECT DISTINCT(COUNT(dept_id)) FROM employees WHERE last_name='Smith';D、SELECT COUNT(DISTINCT dept_id) FROM employees WHERE last_name='Smith';E、SELECT UNIQUE(dept_id) FROM employees WHERE last_name='Smith';
考题
单选题You own a table called EMPLOYEES with this table structure: EMPLOYEE_ID NUMBER Primary Key FIRST_NAME VARCHAR2(25) LAST_NAME VARCHAR2(25) HIRE_DATE DATE What happens when you execute this DELETE statement? DELETE employees; （）A
You get an error because of a primary key violation.B
The data and structure of the EMPLOYEES table are deleted.C
The data in the EMPLOYEES table is deleted but not the structure.D
You get an error because the statement is not syntactically correct.
考题
单选题The EMPLOYEES table contains these columns: LAST_NAME VARCHAR2 (25) SALARY NUMBER (6,2) COMMISSION_PCT NUMBER (6) You need to write a query that will produce these results: 1.Display the salary multiplied by the commission_pct. 2.Exclude employees with a zero commission_pct. 3.Display a zero for employees with a null commission value. Evaluate the SQL statement: SELECT LAST_NAME, SALARY*COMMISSION_PCT FROM EMPLOYEES WHERE COMMISSION_PCT IS NOT NULL; What does the statement provide?（）A
all of the desired resultsB
two of the desired resultsC
one of the desired resultsD
an error statement
考题
多选题Which three statements inserts a row into the table?（）AINSERT INTO employees VALUES ( NULL, ‘John’,‘Smith’);BINSERT INTO employees( first_name, last_name) VALUES(‘John’,‘Smith’);CINSERT INTO employees VALUES (‘1000’,‘John’,NULL);DINSERT INTO employees(first_name,last_name, employee_id) VALUES ( 1000, ‘John’,‘Smith’);EINSERT INTO employees (employee_id) VALUES (1000);FINSERT INTO employees (employee_id, first_name, last_name) VALUES ( 1000, ‘John’,‘’);
考题
单选题The EMPLOYEES table has these columns: LAST_NAME VARCHAR2(35) SALARY NUMBER(8,2) HIRE_DATE DATE Management wants to add a default value to the SALARY column. You plan to alter the table by using this SQL statement: ALTER TABLE EMPLOYEES MODIFY (SALARY DEFAULT 5000); Which is true about your ALTER statement?（）A
Column definitions cannot be altered to add DEFAULT values.B
A change to the DEFAULT value affects only subsequent insertions to the table.C
Column definitions cannot be altered to add DEFAULT values for columns with a NUMBER data type.D
All the rows that have a NULL value for the SALARY column will be updated with the value 5000.
考题
单选题The EMPLOYEES table has these columns:LAST_NAME VARCHAR2(35) SALARY NUMBER(8,2) HIRE_DATE DATEManagement wants to add a default value to the SALARY column. You plan to alter the table by using this SQL statement:ALTER TABLE EMPLOYEES MODIFY (SALARY DEFAULT 5000);Which is true about your ALTER statement?（）A
Column definitions cannot be altered to add DEFAULT values.B
A change to the DEFAULT value affects only subsequent insertions to the table.C
Column definitions cannot be altered to add DEFAULT values for columns with a NUMBER data type.D
All the rows that have a NULL value for the SALARY column will be updated with the value 5000.
考题
单选题Examine the structure of the EMPLOYEES table: EMPLOYEE_ID NUMBER Primary Key FIRST_NAME VARCHAR2(25) LAST_NAME VARCHAR2(25) HIRE_DATE DATE Which UPDATE statement is valid?（）A
UPDATE employees SET first_name = 'John' SET last_name ='Smith' WHERE employee_id = 180;B
UPDATE employees SET first_name = 'John', SET last_name ='Smith' WHERE employee_id = 180;C
UPDATE employees SET first_name = 'John' AND last_name ='Smith' WHERE employee_id = 180;D
UPDATE employees SET first_name = 'John', last_name ='Smith' WHERE employee_id = 180;
考题
单选题The EMPLOYEES table contains these columns: EMPLOYEE_ID NUMBER(4) LAST_NAME VARCHAR2 (25) JOB_ID VARCHAR2(10) You want to search for strings that contain 'SA_' in the JOB_ID column. Which SQL statement do you use?（）A
SELECT employee_id, last_name, job_id FROM employees WHERE job_id LIKE '%SA/_%' ESCAPE '/';B
SELECT employee_id, last_name, job_id FROM employees WHERE job_id LIKE '%SA_';C
SELECT employee_id, last_name, job_id FROM employees WHERE job_id LIKE '%SA_' ESCAPE /;D
SELECT employee_id, last_name, job_id FROM employees WHERE job_id = '%SA_';
考题
单选题The EMPLOYEES table contains these columns: LAST_NAME VARCHAR2 (25) SALARY NUMBER (6,2) COMMISSION_PCT NUMBER (6) You need to write a query that will produce these results: 1.Display the salary multiplied by the commission_pct. 2.Exclude employees with a zero commission_pct. 3.Display a zero for employees with a null commission value. Evaluate the SQL statement: SELECT LAST_NAME, SALARY*COMMISSION_PCT FROM EMPLOYEES WHERE COMMISSION_PCT IS NOT NULL; What does the statement provide?（）A
all of the desired resultsB
two of the desired resultsC
one of the desired resultsD
an error statement
考题
多选题Examine the structure of the EMPLOYEES table: EMPLOYEE_ID NUMBER Primary Key FIRST_NAME VARCHAR2(25) LAST_NAME VARCHAR2(25) Which three statements inserts a row into the table? （）AINSERT INTO employees VALUES (NULL, 'JOHN','Smith');BINSERT INTO employees( first_name, last_name) VALUES ('JOHN','Smith');CINSERT INTO employees VALUES ('1000','JOHN','NULL');DINSERT INTO employees(first_name,last_name, employee_id) VALUES ('1000, 'john','Smith');EINSERT INTO employees (employee_id) VALUES (1000);FINSERT INTO employees (employee_id, first_name, last_name) VALUES ( 1000, 'john',);
考题
单选题Management has asked you to calculate the value 12*salary* commission_pct for all the employees in the EMP table. The EMP table contains these columns: LAST NAME VARCNAR2(35) NOT NULL SALARY NUMBER(9,2) NOT NULL COMMISION_PCT NUMBER(4,2) Which statement ensures that a value is displayed in the calculated columns for all employees?（）A
SELECT last_name, 12*salary* commission_pct FROM emp;B
SELECT last_name, 12*salary* (commission_pct,0) FROM emp;C
SELECT last_name, 12*salary*(nvl(commission_pct,0)) FROM emp;D
SELECT last_name, 12*salary*(decode(commission_pct,0)) FROM emp;
考题
单选题The EMPLOYEE tables has these columns: LAST_NAME VARCHAR2(35) SALARY NUMBER(8,2) COMMISSION_PCT NUMBER(5,2) You want to display the name and annual salary multiplied by the commission_pct for all employees. For records that have a NULL commission_pct, a zero must be displayed against the calculated column. Which SQL statement displays the desired results?（）A
SELECT last_name, (salary * 12) * commission_pct FROM EMPLOYEES;B
SELECT last_name, (salary * 12) * IFNULL(commission_pct, 0) FROM EMPLOYEES;C
SELECT last_name, (salary * 12) * NVL2(commission_pct, 0) FROM EMPLOYEES;D
SELECT last_name, (salary * 12) * NVL(commission_pct, 0) FROM EMPLOYEES;
考题
单选题Examine the structure of the EMPLOYEES table: Column name Data type Remarks EMPLOYEE_ID NUMBER NOT NULL, Primary Key LAST_NAME VARCNAR2(30) FIRST_NAME VARCNAR2(30) JOB_ID NUMBER SAL NUMBER MGR_ID NUMBER References EMPLOYEE_ID column DEPARTMENT_ID NUMBER You need to create an index called NAME_IDX on the first name and last name fields of the EMPLOYEES table. Which SQL statement would you use to perform this task?（）A
CREATE INDEX NAME _IDX (first_name, last_name);B
CREATE INDEX NAME _IDX (first_name, AND last_name)C
CREATE INDEX NAME_IDX ON (First_name, last_name);D
CREATE INDEX NAME_IDX ON employees (First_name, AND last_name);E
CREATE INDEX NAME_IDX ON employees (First_name, last_name);F
CREATE INDEX NAME_IDX FOR employees (First_name, last_name);
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