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多选题
Examine the description of the MARKS table: STD_ID NUMBER(4) STUDENT_NAME VARCHAR2(30) SUBJ1 NUMBER(3) SUBJ2 NUMBER(3) SUBJ3 NUMBER(3) SUBJ1, SUBJ2, and SUBJ3 indicate the marks (grades) obtained by a student in the three subjects. Which two statements are valid? ()
A
SELECT SUM(subj1, subj2, subj3) FROM marks;
B
SELECT SUM(subj1 + subj2 + subj3) FROM marks;
C
SELECT SUM(subj1), SUM(subj2), SUM(subj3) FROM marks;
D
SELECT MAX(subj1, subj2, subj3) FROM marks;
E
SELECT MINIMUM(subj1) FROM marks;
F
SELECT COUNT(std_id) FROM marks WHERE subj1 >= AVG(subj1);
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更多 “多选题Examine the description of the MARKS table: STD_ID NUMBER(4) STUDENT_NAME VARCHAR2(30) SUBJ1 NUMBER(3) SUBJ2 NUMBER(3) SUBJ3 NUMBER(3) SUBJ1, SUBJ2, and SUBJ3 indicate the marks (grades) obtained by a student in the three subjects. Which two statements are valid? ()ASELECT SUM(subj1, subj2, subj3) FROM marks;BSELECT SUM(subj1 + subj2 + subj3) FROM marks;CSELECT SUM(subj1), SUM(subj2), SUM(subj3) FROM marks;DSELECT MAX(subj1, subj2, subj3) FROM marks;ESELECT MINIMUM(subj1) FROM marks;FSELECT COUNT(std_id) FROM marks WHERE subj1 = AVG(subj1);” 相关考题
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Examine the description of the MARKS table:STD_ID NUMBER(4)STUDENT_NAME VARCHAR2(30)SUBJ1 NUMBER(3)SUBJ2 NUMBER(3)SUBJ1 and SUBJ2 indicate the marks obtained by a student in two subjects. Examine this SELECT statement based on the MARKS table:SELECT subj1+subj2 total_marks, std_idFROM marksWHERE subj1 AVG(subj1) AND subj2 AVG(subj2) ORDER BY total_ marks;What is the result of the SELECT statement? ()A. The statement executes successfully and returns the student ID and sum of all marks for each student who obtained more than the average mark in each subject.B. The statement returns an error at the SELECT clause.C. The statement returns an error at the WHERE clause.D. The statement returns an error at the ORDER BY clause.
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Examine the description of the MARKS table:SUBJ1 and SUBJ2 indicate the marks obtained by a student in two subjects.Examine this SELECT statement based on the MARKS table:What is the result of the SELECT statement?()A. The statement executes successfully and returns the student ID and sum of all marks for each student who obtained more than the average mark in each subject.B. The statement returns an error at the SELECT clause.C. The statement returns an error at the WHERE clause.D. The statement returns an error at the ORDER BY clause.
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Examine the description of the MARKS table: STD_ID NUMBER(4) STUDENT_NAME VARCHAR2(30) SUBJ1 NUMBER(3) SUBJ2 NUMBER(3) SUBJ3 NUMBER(3) SUBJ1, SUBJ2, and SUBJ3 indicate the marks (grades) obtained by a student in the three subjects. Which two statements are valid? ()A、SELECT SUM(subj1, subj2, subj3) FROM marks;B、SELECT SUM(subj1 + subj2 + subj3) FROM marks;C、SELECT SUM(subj1), SUM(subj2), SUM(subj3) FROM marks;D、SELECT MAX(subj1, subj2, subj3) FROM marks;E、SELECT MINIMUM(subj1) FROM marks;F、SELECT COUNT(std_id) FROM marks WHERE subj1 = AVG(subj1);
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Examine the description of the EMPLOYEES table: EMP_ID NUMBER(4) NOT NULL LAST_NAME VARCHAR2(30) NOT NULL FIRST_NAME VARCHAR2(30) DEPT_ID NUMBER(2) Which statement produces the number of different departments that have employees with last name Smith?()A、SELECT COUNT(*) FROM employees WHERE last_name='Smith';B、SELECT COUNT(dept_id) FROM employees WHERE last_name='Smith';C、SELECT DISTINCT(COUNT(dept_id)) FROM employees WHERE last_name='Smith';D、SELECT COUNT(DISTINCT dept_id) FROM employees WHERE last_name='Smith';E、SELECT UNIQUE(dept_id) FROM employees WHERE last_name='Smith';
考题
You need to design a student registration database that contains several tables storing academic information. The STUDENTS table stores information about a student. The STUDENT_GRADES table stores information about the student's grades. Both of the tables have a column named STUDENT_ID. The STUDENT_ID column in the STUDENTS table is a primary key. You need to create a foreign key on the STUDENT_ID column of the STUDENT_GRADES table that points to the STUDENT_ID column of the STUDENTS table. Which statement creates the foreign key?()A、CREATE TABLE student_grades (student_id NUMBER(12),semester_end DATE, gpa NUMBER(4,3), CONSTRAINT student_id_fk REFERENCES (student_id) FOREIGN KEY student (student_id));B、CREATE TABLE student_grades(student_id NUMBER(12),semester_end DATE, gpa NUMBER(4,3), student_id_fk FOREIGN KEY (student_id) REFERENCES students (student_id));C、CREATE TABLE student_grades(student_id NUMBER(12),semester_end DATE, gpa NUMBER(4,3), CONSTRAINT FOREIGN KEY (student_id) REFERENCES student (student_id));D、CREATE TABLE student_grades(student_id NUMBER(12),semester_end DATE, gpa NUMBER(4,3), CONSTRAINT student_id_fk FOREIGN KEY (student_id) REFERENCES students (student_id));
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Which statement accomplish this? ()A、CREATE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status VARCHAR2 (10), date_ordered DATE = SYSDATE);B、CREATE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status VARCHAR2 (10), date_ordered DATE DEFAULT SYSDATE);C、CREATE OR REPLACE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status VARCHAR2 (10), date_ordered DATE DEFAULT SYSDATE);D、CREATE OR REPLACE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status NUMBER (10), date_ordered DATE = SYSDATE);E、CREATE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status NUMBER (10), date_ordered DATE = SYSDATE);F、CREATE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status NUMBER (10), date_ordered DATE DEFAULT SYSDATE);
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Examine the command that is used to create a table: SQL CREATE TABLE orders(oid NUMBER(6) PRIMARY KEY, odate DATE, ccode NUMBER(6), oamt NUMBER(10,2)) TABLESPACE users; Which two statements are true about the effect of the above command) ()A、A CHECK constraint is created on the OID column.B、A NOT NULL constraint is created on the OID column.C、The ORDERS table is the only object created in the USERS tablespace.D、The ORDERS table and a unique index are created in the USERS tablespace.E、The ORDERS table is created in the USERS tablespace and a unique index is created on the OIDcolumn in the SYSTEM tablespace.
考题
Examine the following command: CREATE TABLE (prod_id number(4), Prod_name varchar2 (20), Category_id number(30), Quantity_on_hand number (3) INVISIBLE); Which three statements are true about using an invisible column in the PRODUCTS table?()A、The %ROWTYPE attribute declarations in PL/SQL to access a row will not display the invisible column in the output.B、The DESCRIBE commands in SQL *Plus will not display the invisible column in the output.C、Referential integrity constraint cannot be set on the invisible column.D、The invisible column cannot be made visible and can only be marked as unused.E、A primary key constraint can be added on the invisible column.
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The STUDENT_GRADES table has these columns: STUDENT_ID NUMBER(12) SEMESTER_END DATE GPA NUMBER(4,3) Which statement finds the highest grade point average (GPA) per semester?()A、SELECT MAX(gpa) FROM student_grades WHERE gpa IS NOT NULL;B、SELECT (gpa) FROM student_grades GROUP BY semester_end WHERE gpa IS NOT NULL;C、SELECT MAX(gpa) FROM student_grades WHERE gpa IS NOT NULL GROUP BY semester_end;D、SELECT MAX(gpa) GROUP BY semester_end WHERE gpa IS NOT NULL FROM student_grades;E、SELECT MAX(gpa) FROM student_grades GROUP BY semester_end WHERE gpa IS NOT NULL;
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Which SQL statement defines a FOREIGN KEY constraint on the DEPTNO column of the EMP table?()A、CREATE TABLE EMP (empno NUMBER(4), ename VARCHAR2(35), deptno NUMBER(7,2) NOT NULL, CONSTRAINT emp_deptno_fk FOREIGN KEY deptno REFERENCES dept deptno);B、CREATE TABLE EMP (empno NUMBER(4), ename VARCHAR2(35), deptno NUMBER(7,2) CONSTRAINT emp_deptno_fk REFERENCES dept (deptno));C、CREATE TABLE EMP (empno NUMBER(4), ename VARCHAR2(35), deptno NUMBER(7,2) NOT NULL, CONSTRAINT emp_deptno_fk REFERENCES dept (deptno) FOREIGN KEY (deptno));D、CREATE TABLE EMP (empno NUMBER(4), ename VARCHAR2(35), deptno NUMBER(7,2) FOREIGN KEY CONSTRAINT emp_deptno_fk REFERENCES dept (deptno));
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You need to create a table named ORDERS that contains four columns: 1.an ORDER_ID column of number data type 2.a CUSTOMER_ID column of number data type 3.an ORDER_STATUS column that contains a character data type 4.a DATE_ORDERED column to contain the date the order was placed When a row is inserted into the table, if no value is provided for the status of the order, the value PENDING should be used instead. Which statement accomplishes this?()A、CREATE TABLE orders ( order_id NUMBER(10), customer_id NUMBER(8), order_status NUMBER(10) DEFAULT 'PENDING', date_ordered DATE );B、CREATE TABLE orders ( order_id NUMBER(10), customer_id NUMBER(8), order_status VARCHAR2(10) = 'PENDING', date_ordered DATE );C、CREATE OR REPLACE TABLE orders ( order_id NUMBER(10), customer_id NUMBER(8), order_status VARCHAR2(10) DEFAULT 'PENDING', date_ordered DATE );D、CREATE OR REPLACE TABLE orders ( order_id NUMBER(10), customer_id NUMBER(8), order_status VARCHAR2(10) = 'PENDING', date_ordered DATE );E、CREATE TABLE orders ( order_id NUMBER(10), customer_id NUMBER(8), order_status VARCHAR2(10) DEFAULT 'PENDING', date_ordered DATE );F、CREATE TABLE orders ( order_id NUMBER(10), customer_id NUMBER(8), order_status VARCHAR2(10) DEFAULT 'PENDING', date_ordered VARCHAR2 );
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You need to create a table named ORDERS that contain four columns: 1. an ORDER_ID column of number data type 2. aCUSTOMER_ID column of number data type 3. an ORDER_STATUS column that contains a character data type 4. aDATE_ORDERED column to contain the date the order was placed. When a row is inserted into the table, if no value is provided when the order was placed, today's date should be used instead. Which statement accomplishes this?()A、CREATE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status VARCHAR2 (10), date_ordered DATE = SYSDATE);B、CREATE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status VARCHAR2 (10), date_ordered DATE DEFAULT SYSDATE);C、CREATE OR REPLACE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status VARCHAR2 (10), date_ordered DATE DEFAULT SYSDATE);D、CREATE OR REPLACE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status VARCHAR2 (10), date_ordered DATE = SYSDATE);E、CREATE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status NUMBER (10), date_ordered DATE = SYSDATE);F、CREATE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status NUMBER (10), date_ordered DATE DEFAULT SYSDATE);
考题
Examine the description of the STUDENTS table: STD_ID NUMBER(4) COURSE_ID VARCHAR2(10) START_DATE DATE END_DATE DATE Which two aggregate functions are valid on the START_DATE column? ( )A、SUM(start_date)B、AVG(start_date)C、COUNT(start_date)D、AVG(start_date,end_date)E、MIN(start_date)F、MAXIMUM(start_date)
考题
The STUDENT_GRADES table has these columns: STUDENT_ID NUMBER(12) SEMESTER_END DATE GPA NUMBER(4,3) Which statement finds the highest grade point average (GPA) per semester?()A、SELECT MAX (gpa) FROM student _ grades WHERE gpa IS NOT NULL;B、SELECT (gpa) FROM student _ grades GROUP BY semester_end WHERE gpa IS NOT NULL;C、SELECT MAX (gpa) FROM student _ grades WHERE gpa IS NOT NULL GROUP BY semester_end;D、SELECT MAX (gpa) GROUP BY semester_end WHERE gpa IS NOT NULL FROM student _ grades;E、SELECT MAX (gpa) FROM student _ grades GROUP BY semester_end WHERE gpa IS NOT NULL;
考题
Examine the description of the MARKS table: STD_ID NUMBER(4) STUDENT_NAME VARCHAR2(30) SUBJ1 NUMBER(3) SUBJ2 NUMBER(3) SUBJ1 and SUBJ2 indicate the marks obtained by a student in two subjects. Examine this SELECT statement based on the MARKS table: SELECT subj1+subj2 total_marks, std_id FROM marks WHERE subj1 AVG(subj1) AND subj2 AVG(subj2) ORDER BY total_marks; What is the result of the SELECT statement?()A、The statement executes successfully and returns the student ID and sum of all marks for each student who obtained more than the average mark in each subject.B、The statement returns an error at the SELECT clause.C、The statement returns an error at the WHERE clause.D、The statement returns an error at the ORDER BY clause.
考题
多选题Examine the following command: CREATE TABLE (prod_id number(4), Prod_name varchar2 (20), Category_id number(30), Quantity_on_hand number (3) INVISIBLE); Which three statements are true about using an invisible column in the PRODUCTS table?()AThe %ROWTYPE attribute declarations in PL/SQL to access a row will not display the invisible column in the output.BThe DESCRIBE commands in SQL *Plus will not display the invisible column in the output.CReferential integrity constraint cannot be set on the invisible column.DThe invisible column cannot be made visible and can only be marked as unused.EA primary key constraint can be added on the invisible column.
考题
单选题Examine the description of the MARKS table: STD_ID NUMBER(4) STUDENT_NAME VARCHAR2(30) SUBJ1 NUMBER(3) SUBJ2 NUMBER(3) SUBJ1 and SUBJ2 indicate the marks obtained by a student in two subjects. Examine this SELECT statement based on the MARKS table: SELECT subj1+subj2 total_marks, std_id FROM marks WHERE subj1 AVG(subj1) AND subj2 AVG(subj2) ORDER BY total_ marks; What is the result of the SELECT statement?()A
The statement executes successfully and returns the student ID and sum of all marks for each student who obtained more than the average mark in each subject.B
The statement returns an error at the SELECT clause.C
The statement returns an error at the WHERE clause.D
The statement returns an error at the ORDER BY clause.
考题
多选题Examine the command that is used to create a table: SQL CREATE TABLE orders(oid NUMBER(6) PRIMARY KEY, odate DATE, ccode NUMBER(6), oamt NUMBER(10,2)) TABLESPACE users; Which two statements are true about the effect of the above command) ()AA CHECK constraint is created on the OID column.BA NOT NULL constraint is created on the OID column.CThe ORDERS table is the only object created in the USERS tablespace.DThe ORDERS table and a unique index are created in the USERS tablespace.EThe ORDERS table is created in the USERS tablespace and a unique index is created on the OIDcolumn in the SYSTEM tablespace.
考题
多选题Examine the description of the STUDENTS table: STD_ID NUMBER(4) COURSE_ID VARCHAR2(10) START_DATE DATE END_DATE DATE Which two aggregate functions are valid on the START_DATE column? ( )ASUM(start_date)BAVG(start_date)CCOUNT(start_date)DAVG(start_date,end_date)EMIN(start_date)FMAXIMUM(start_date)
考题
单选题Examine the structure of the STUDENTS table: STUDENT_ID NUMBER NOT NULL, Primary Key STUDENT_NAME VARCHAR2(30) COURSE_ID VARCHAR2(10) NOT NULL MARKS NUMBER START_DATE DATE FINISH_DATE DATE You need to create a report of the 10 students who achieved the highest ranking in the course INT SQL and who completed the course in the year 1999. Which SQL statement accomplishes this task? ()A
SELECT student_ id, marks, ROWNUM Rank FROM students WHERE ROWNUM = 10 AND finish_date BETWEEN '01-JAN-99' AND '31-DEC-99 AND course_id = 'INT_SQL' ORDER BY mark DESC;B
SELECT student_id, marks, ROWID Rank FROM students WHERE ROWID = 10 AND finish_date BETWEEN '01-JAN-99' AND '31-DEC-99' AND course_id = 'INT_SQL' ORDER BY mark;C
SELECT student_id, marks, ROWNUM Rank FROM (SELECT student_id, marks FROM students WHERE ROWNUM = 10 AND finish_date BETWEEN '01-JAN-99' AND '31-DEC- 99' AND course_id = 'INT_SQL' ORDER BY mark DESC;D
SELECT student_id, marks, ROWNUM Rank FROM (SELECT student_id, marks FROM students WHERE (finish_date BETWEEN '01-JAN-99 AND '31-DEC-99' AND course_id = 'INT_SQL' ORDER BY marks DESC) WHERE ROWNUM = 10;E
SELECT student id, marks, ROWNUM Rank FROM (SELECT student_id, marks FROM students ORDER BY marks) WHERE ROWNUM = 10 AND finish date BETWEEN '01-JAN-99' AND '31-DEC-99' AND course _ id 'INT_SQL';
考题
单选题Which of the following statements is true concerning the cetane number rating of diesel fuel? ()A
The cetane number is obtained by comparing the fuel with cetane a colorless liquid hydrocarbonB
The higher the cetane number, the shorter the ignition lagC
The highest cetane number of fuel is 100D
All of the above
考题
单选题Examine the structure of the EMPLOYEES, DEPARTMENTS, and TAX tables. EMPLOYEES NOT NULL, Primary EMPLOYEE_ID NUMBER Key VARCHAR2 EMP_NAME (30) VARCHAR2 JOB_ID (20) SALARY NUMBER References MGR_ID NUMBER EMPLOYEE_ID column DEPARTMENT_ID NUMBER Foreign key to DEPARTMENT_ID column of the DEPARTMENTS table DEPARTMENTS NOT NULL, DEPARTMENT_ID NUMBER Primary Key VARCHAR2 DEPARTMENT_NAME |30| References MGR_ID column MGR_ID NUMBER of the EMPLOYEES table TAX MIN_SALARY NUMBER MAX_SALARY NUMBER TAX_PERCENT NUMBER For which situation would you use a nonequijoin query?()A
To find the tax percentage for each of the employees.B
To list the name, job id, and manager name for all the employees.C
To find the name, salary, and department name of employees who are not working with Smith.D
To find the number of employees working for the Administrative department and earning less then 4000.E
To display name, salary, manager ID, and department name of all the employees, even if the employees do not have a department ID assigned.
考题
多选题Examine the description of the STUDENTS table: STD_ID NUMBER(4) COURSE_ID VARCHARD2(10) START_DATE DATE END_DATE DATE Which two aggregate functions are valid on the START_DATE column?()ASUM(start_date)BAVG(start_date)CCOUNT(start_date)DAVG(start_date, end_date)EMIN(start_date)FMAXIMUM(start_date)
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