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What is an obsolete backup set？（）
- A、 A backup set that is missing one or more backup set pieces
- B、 A backup that has exceeded the retention criteria and is no longer needed
- C、 A backup set that does not include archived redo logs
- D、 A backup set that can not be recovered due to corruption
- E、 A backup set superceded by a datafile copy
参考答案
更多 “What is an obsolete backup set？（） A、 A backup set that is missing one or more backup set piecesB、 A backup that has exceeded the retention criteria and is no longer neededC、 A backup set that does not include archived redo logsD、 A backup set that can not be recovered due to corruptionE、 A backup set superceded by a datafile copy” 相关考题
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When a project incorporates an Organizational Breakdown Structure (OBS), it is integrated with the WBS at theA.taskB.level of effortC.sub-taskD.projectE.work package
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● When a project incorporates an Organizational Breakdown Structure (OBS), it is integrated with the WBS at theA taskB level of effortC sub-taskD projectE work package
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阅读下列说明和HTML文本，分析其中嵌入的JavaScript脚本，将应填入(n)处的语句写在对应栏内．【说明】在网页正中靠上显示一个固定的时钟，如图8-1所示。HTML文本如下所示．＜html＞＜!-省略部分为HTML文本框＞＜body nload="rad();counter(); ob();setNum();setlnterval('timer(),100); setlnterval('runClock ()',100)"＞＜script. language="JavaScdpt"＞var dot=60; //挂钟外边缘上的60个刻度rads=(1);function rad () {for (i=1; i＜dot; i++) {//初始化刻度if (document.all) rads[i]=new Array (eval('rad'+i).style,-100, -100);else rads[i]: new Array (eval('document. rad'+i),-100,-100);}}function setCircle() {//求外缘上60 个刻度的实际位置for (i=1; i＜dot; i++) {rads[i][0].left=rads[i][1]+pX-15;if ((2))//检验是否是 NetScape4.xrads[i][0].left+=10;rads[i][0].top=rads[i][2]+pY-20;}}function counter() {//设置外边缘上 60 个刻度相对于刻度中心的位置for 0=1; i＜dot; i++) {rad=Math. P1*(i/((dot-1)/2));rads[i][1] = Math. sin(rad)*60;rads[i][2] = -Math.cos(rad)*60;}setCircle();}pX=400;pY=150; //中心位置obs=new Array(13); //储存秒针、分针、时针各组成部分位置的数组function ob () {//初始化秒针、分针、时针各组成部分for (i=0; i＜13; i++) {if (document.all) obs[i]=new Array (eval('ob'+i), style,-100, 100);else obs[i] = new Array (eval('document.ob'+i), -100, -100);}}function cl(a,b,c){if (document.all)//判断游览器种类，为真表示为IE{if (a!=0) b+= 1;eval('c'+a+'.style.pixelTop='+(pY+(c-5)));eval('o'+a+'.style.pixetLeft='+(pX+(b)));}else{if (a!=0) b+=10;eval('document.c'+a+'.top='+(pY+{c)));eval('document.c'+a+'.left:'+(pX+(b))):}}function runClock() {//求秒针、分针、时针各组成部分在屏幕上的实际位置for (i=0; i＜13; i++) {obs[i][0].left=(3);obs[i][0].top=obs[i][2]+pY;}}function timer() {time = new Date ();//获取系统当前时间sec=(4);//计算秒针、分针、时针各自转动的角度sec=Math. Pl*sec/30;min=Math. Pl*time.getMinutes()/30;hr =Math. Pl* ((time.getHours ()*60)+time, getMinutes ())/360;//设定秒针各组成部分在屏幕上的相对位置for ((5)) (obs[i][1] = Math.sin(sec) * (44 - (i-1)*11) -16;if (document.layers)obs[i][1]+=10;obs[i][2] =-Math.cos(sec) * (44-(i-1)*11)-27;}//设定分针各组成部分在屏幕上的相对位置for (i=6;i＜10;i++) {obs[i][1]= Math.sin(min) * (40-(i-6)*10)-16;if (document.layers)obs[i][l]+=10;obs[i][2] = Math.cos(min) * (40 - (i-6)*10) -27;}//设定时针各组成部分在屏幕上的相对位置for (i=10;i＜13;i++) {obs[i][1] = Math.sin(hr) * (37 - (i- 10)*11)-16;if (document.layers)obs[i][1]+=10;ohs[i][2] =-Math.cos(hr) * (37- (i-10)*11)-27;}}function setNum(){//设置并显示挂钟上的数字cl (0, -67, -65);cl (1,10,-51);cl (2, 28, -33);cl (3, 35,-8);cl (4, 28, 17);cl (5, 10, 35);cl (6, -15, 42);cl (7, -40, 35);cl (8, -58, 17);cl (9, -65, -8);cl (10, -58, -33);cl (11, -40, -51);c1(12, -16, -56);}＜/script＞
考题
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考题
单选题任何两个分解结构结合在一起，都可以形成一个矩阵，下列说法正确的是（）A
WBS和OBS形成帐户代码B
OBS和ABS形成费用估算表C
WBS和CBS形成责任矩阵D
WBS、PBS和OBS构成费用控制立方体
考题
单选题OBS是呼叫中心平台提供的向外发起呼叫的后台服务器。它能够执行各种定制的呼出任务，呼出任务可存放在呼叫中心平台数据库或第三方业务数据库中。OBS通过哪个数据库代理访问该数据库提取外呼数据（）。A
IVRB
AplogicC
DtproxyD
直接访问数据库
考题
问答题什么是观察值OBS？什么是变量及变量值？
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