网友您好, 请在下方输入框内输入要搜索的题目:
题目内容
(请给出正确答案)
- Mr. Taylor, this is the project plan you asked me to make last week. -()
A、Sure. That’s a quick job.
B、OK, put it over there.
C、Congratulations.
参考答案
更多 “ - Mr. Taylor, this is the project plan you asked me to make last week. -() A、Sure. That’s a quick job.B、OK, put it over there.C、Congratulations. ” 相关考题
考题
What() you() he’ s the murderer?
A. make, thinkB. makes, thinkC. makes, to thinkD. make, thinking
考题
You ( ) me, because I never said I liked coffee without milk.
A、must misunderstandB、must have misunderstoodC、must be misunderstandingD、had to misunderstand
考题
49.—What about some drinks?—__________.A. Help, yourselfB. Good ideaC. You're welcomeD. Me,too
考题
已知last指向单向简单链表的尾结点,将s所指结点加在表尾,不正确的操作是____。A.last->next=s,last=s,last->next=NULL;B.last->next=s,s->next=NULL,last=s;C.s->next=NULL, last->next=s, s=last;D.s->next=NULL, last->next=s,last=s;
考题
7、已知last指向单向简单链表的尾结点,将s所指结点加在表尾,正确的操作是____。A.s->next=s,last=s,last->next=NULL;B.last->next=s,s->next=NULL,last=s;C.s->next=NULL, last->next=s, s=last;D.s->next=last, last->next=NULL,last=s;
考题
Me,you是两个初始集合,则下列关于派生集合定义方式正确的是A.link/me,you/:a;B.link(me,you):a;C.link/me you/a;D.link(me,you)/a;
考题
已知last指向单向简单链表的尾结点,将s所指结点插入在表尾,正确的操作是____。A.s->next=s,last=s,last->next=NULL;B.last->next=s,s->next=NULL,last=s;C.s->next=NULL, last->next=s, s=last;D.s->next=last, last->next=NULL,last=s;
考题
已知last指向单向简单链表的尾结点,将s所指结点加在表尾,正确的操作是____。A.s->next=s,last=s,last->next=NULL;B.last->next=s,s->next=NULL,last=s;C.s->next=NULL, last->next=s, s=last;D.s->next=last, last->next=NULL,last=s;
考题
SCOR模型从()方面供应链管理流程。A.plan、fulfill、control、feedbackB.plan、source、make、deliver、returnC.fulfill、control、feedbackD.deliver、return
考题
me是一个包含3个成员属性为a的集合,you是一个包含2个成员属性为b的集合,则要定义一个2行3列的矩阵所对应的派生集合方法中正确的是A.ps(me,you):c;B.ps(you,me):c;C.ps(a,b):c;D.ps(b,a):c;
热门标签
最新试卷