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Could you tell me how you ship the goods.()
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下列程序执行后的输出结果是 included main( ) { char arr[2][4]; strcpy(arr,"you")
下列程序执行后的输出结果是#included＜string.h＞main( ){ char arr[2][4];strcpy(arr,"you");strepy(arr[1],"me");arr[0][3]='';cout＜＜arr＜＜endl;}A．youmeB．youC．meD．err
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You ( ) me, because I never said I liked coffee without milk.
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以下程序的输出结果是()。main(){char*a[][5]={“how”,”do”,”you”,”do”,”!”};char**p;inti;p=a;for(i=0;i
A.howdoyoudo!B.howC.howdoyoudoD.hdyd
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Me,you是两个初始集合，则下列关于派生集合定义方式正确的是A．link/me,you/:a;B．link(me,you):a;C．link/me you/a;D．link(me,you)/a;
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me是一个包含3个成员属性为a的集合，you是一个包含2个成员属性为b的集合，则要定义一个2行3列的矩阵所对应的派生集合方法中正确的是A．ps(me,you):c;B．ps(you,me):c;C．ps(a,b):c;D．ps(b,a):c;
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