网友您好, 请在下方输入框内输入要搜索的题目:
题目内容
(请给出正确答案)
Hyponymy is a relation of inclusion. Tiger, lion and dog are hyponyms of the word animal.()
参考答案
更多 “ Hyponymy is a relation of inclusion. Tiger, lion and dog are hyponyms of the word animal.() ” 相关考题
考题
The young peasant went out west to try his ________.
A. fortuneB. healthC. ambitionD. relation
考题
Youneedtoallowtheusertotogglebetweenautomaticqueryandnoautomaticqueryusingapop-upmenu.Whichbuilt-inwouldyouuseinthemenuitemcommandtoobtaintherelationshipname?()
A.GET_RELATION_PROPERTYB.SET_RELATION_PROPERTYC.GET_BLOCK_PROPERTYD.GET_FORM_PROPERTY
考题
Which of the following best describes the relation between night and knight
A.metonymy
B.homonymy
C.antonymy
D.hyponymy
考题
在前面几题的基础上,有子类Dog和Cat继承了父类Animal,如下空格的输出是以下哪个选项? dog = Dog('coco','small'); cat = Cat('kawaii') >>> isinstance(dog, Animal) ___________ >>> isinstance(cat, Animal) ___________ >>> isinstance(dog, Dog) ___________ >>> isinstance(dog, Cat) ____________A.True True False FalseB.True True True FalseC.True False False TrueD.True True True True
考题
设置 d3 力导向图文本时,不可以使用以下哪种方式?A.xx.text((d)=>{return d.relation});B.xx.text("hello")C.xx.text(d.relation);D.xx.text(function(d)=>{return d.relation});
考题
1、在前面几题的基础上,有子类Dog和Cat继承了父类Animal,如下空格的输出是以下哪个选项? dog = Dog('coco','small'); cat = Cat('kawaii') >>> isinstance(dog, Animal) ___________ >>> isinstance(cat, Animal) ___________ >>> isinstance(dog, Dog) ___________ >>> isinstance(dog, Cat) ____________A.True True False FalseB.True True True FalseC.True False False TrueD.True True True True
热门标签
最新试卷