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81，64，121，36，（ ），16
A．144
B．169
C．196
D．25
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更多 “ 81，64，121，36，（ ），16A．144B．169C．196D．25 ” 相关考题
考题
以下语句的输出结果是( ) printf("%d，%d，%u\n"，016，16，-16)；A．16，16，65420B．14，16，6542C．16，16，-16D．14，16，-16
考题
What are two rules for compacting IPv6 addresses?()
A. Every 16 - bit segment segment that consists of all zeroes can be represented with a single colon.B. The trailing zeroes in any 16 - bit segment do not have to be written.C. The leading zeroes in any 16 - bit segment do not have to be written.D. Any single, continuous string of one or more 16 - bit segments that consists of all zeroes can be represented with a double colon.E. The maximum number of times a double colon can replace a 16 - bit segment that consists of all zeroes is two.F. Two zeroes in the middle of any 16 -bit segment do not have to be written.
考题
WhataretworulesforcompactingIPv6addresses?()
A.Themaximumnumberoftimesadoublecoloncanreplacea16-bitsegmentthatconsistsofallzeroesistwoB.Theleadingzeroesinany16-bitsegmentdonothavetobewritten.C.Every16-bitsegmentthatconsistsofallzeroescanberepresentedwithasinglecolonD.Thetrailingzeroesinany16-bitsegmentdonothavetobewritten.E.Anysingle，continuousstringofoneormore16-bitsegmentsthatconsistsofallzeroescanberepresentedwithadoublecolonF.Twozeroesinthemiddleofany16-bitsegmentdonothavetobewritten
考题
5．（19）16 －（2）16 ＝（）16
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