网友您好, 请在下方输入框内输入要搜索的题目:

题目内容 (请给出正确答案)

The thief tried to open the locked door but _________.

A) in no way           B) in vain         C) without effect           D) at a loss

 


参考答案

更多 “ Thethieftriedtoopenthelockeddoorbut_________.A)innowayB)invainC)withouteffectD)ataloss ” 相关考题
考题 43. A. kept B. continued C. lastedD. tried

考题 Judge: And where have you stolen these things?Thief: Oh, (57) .

考题 Thief: Hey, you didn't tell me (59) .

考题 整箱货的交接方式有()。 A.CY-CYB.CY-DOORC.DOOR-CYD.DOOR-DOOR

考题 ___ don’t have to pay for large shopping spaces and thus are able to sell their goods at lower prices. A.Mail-Order HousesB.Door-To-Door SellersC.Specialty StoresD.General Stores

考题 阅读以下说明和C++代码。【说明】传输门是传输系统中的重要装置。传输门具有Open(打开)、Closed(关闭)、Opening (正在打开)、StayOpen(保持打开)和Closing(正在关闭)五种状态。触发传输门状态转换的事件有click、complete和timeout三种。事件与其相应的状态转换如下图所示。下面的C++代码1与C++代码2分别用两种不同的设计思路对传输门进行状态模拟,请填补代码中的空缺。【C++代码1】const int CLOSED=1; const int PENING=2;const int PEN=3; const int CLOSING=4;const int STAYOPEN=5; //定义状态变量,用不同整数表示不同状态class Door {Private:int state; //传输门当前状态void setState(int state){ this->state=state;} //设置当前状态public:Door():state(CLOSED){};void getState(){ //根据当前状态输出相应的字符串switch(state){case OPENING: cout<<"OPENING"<<endl; break;case CLOSED: cout<<"CLOSED"<<endl; break;case OPEN: cout<<"OPEN"<<endl; break;case CLOSING: cout<<"CLOSING"<<endl; break;case STAYOPEN:cout<<"STAYOPEN"<<endl; break;}};void click() { //发生click事件时进行状态转换if ((1)) setState(OPENING);else if ((2)) setState(CLOSING);else if ((3)) setState(STAYOPEN);}void timeout(){ //发生timeout事件时进行状态转换if (state == OPEN) setState(CLOSING);}void complete(){ //发生complete事件时进行状态转换if (state == OPENING) setState(OPEN);else if (state == CLOSING) setState(CLOSED);}};int main(){Door aDoor;aDoor.getState();aDoor.click(); aDoor.getState();aDoor.complete();aDoor.getState(); aDoor.click();aDoor.getState();aDoor.click(); aDoor.getState(); return 0;}【C++代码2】class Door {public:DoorState *CLOSED,*OPENING,*OPEN,*CLOSING,*STAYOPEN,*state;Door();virtual~Door(){……//释放申请的内存,此处代码省略);void setState(DoorState *state) { this->state = state;}void getState(){//此处代码省略,本方法输出状态字符串,//例如,当前状态为CLOSED时,输出字符串为“CLOSED”};void click();void timeout();void complete();};Door::Door(){CLOSED = new DoorClosed(this); OPENING = new DoorOpening(this);PEN = new DoorOpen(this); CLOSING = new DoorClosing(this);STAYOPEN = new DoorStayOpen(this);state = CLOSED;}void Door :: click() {(4);)void Door :: timeout() {(5);)void Door :: complete() {(6);}class DoorState//定义一个抽象的状态,它是所有状态类的基类{protected:Door *door;public:DoorState(Door *door) {this->door = door;}virtual~DoorState(void);virtual void click() {}virtual void complete(

考题 请认真阅读以下关于某传输系统的技术说明、状态转换图及C++代码,根据要求回答问题1和问题2。【说明】传输门是传输系统中的重要装置。传输门具有Open(打开)、Closed(关闭)、Opening(正在打开)、StayOpen(保持打开)和Closing(正在关闭)5种状态。触发状态的转换事件有click、complete和timeout 3种,事件与其相应的状态转换如图6-18所示。下面的【C++代码1】与【C++代码2】分别用两种不同的设计思路对传输门进行状态模拟,请填补代码段中的空缺语句。【C++代码1】const int CLOSED = 1; const int PENING = 2;const int PEN = 3; const int CLOSING = 4;const int STAYOPEN = 5; //定义状态变量,用不同整数表示不同状态class Door {private:private:int state; //传输门当前状态void setState(int state) { this->state = stale; } //设置当前状态public:Door () :state (CLOSED) { };void getState() { //根据当前状态输出相应的字符串switch(state) {case OPENING: cout <<"OPENING" << endl; break;case CLOSED: cout << "CLOSED" << endl; break;case OPEN: cout << "OPEN" << endl; break;case CLOSING: cout << "CLOSING" << endl; break;case STAYOPEN: cout << "STAYOPEN" << endl; break;}}void click() { //发生click事件时进行状态转换if ( (1) ) setState(OPENING);else if ( (2) ) setState(CLOSING);else if ( (3) ) setState(STAYOPEN);}void timeout() { //发生timeout事件时进行状态转换if (state == OPEN) setState(CLOSING);}void complete() { //发生complete事件时进行状态转换if (state == OPENING) setState(OPEN);else if (state == CLOSING) setState(CLOSED);}};int main(){Door aDoor;aDoor.getState(); aDoor.click(); aDoor.getState(); aDoor.complete();aDoor.getState(); aDoor.click(); aDoor.getState(); aDoor.click();aDoor.getState(); return 0;}【C++代码2】class Door {public:DoorState *CLOSED, *OPENING, *OPEN, *CLOSING, *STAYOPEN, *state;Door();virtual ~Door() { ... //释放申请的内存,此处代码省略};void s

考题 The roller hatch beam at the edge of the open section of the hatch shall be ______ so that it cannot be moved toward the open section.A.bracedB.choppedC.lashed or pinned backD.locked

考题 下列何种不属于集装箱整箱接收、拆箱交付方式?()A.DOOR/CYB.DOOR/CFSC.CY/CFSD.CY/CY

考题 对下面的代码,哪段描述是错误的?() public class Door{ } public class House{ public House(){ Door door = new Door();}}A.Door是一个类。B.House是一个从Door继承的类。C.House的构造函数中声明了一个名为door的变量。D.door是一个对象。