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下列程序的执行结果为 Private Sub Command1_C1ick( ) Dim sl As String,s2 AS String s1="abcdef" Call lnvert(s1,s2) Print s2 End Sub Private Sub lnvert(ByVal xstr As String,ystr As String) Dim tempstr As Stdng i=Len(xstr) Do While i>=1 tempstr=tempstr+Mid(xstr,i,1) i=i-1 Loop ystr=tempstr End Sub

A.fedcba

B.abcdef

C.afbecd

D.defabc


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更多 “ 下列程序的执行结果为 Private Sub Command1_C1ick( ) Dim sl As String,s2 AS String s1="abcdef" Call lnvert(s1,s2) Print s2 End Sub Private Sub lnvert(ByVal xstr As String,ystr As String) Dim tempstr As Stdng i=Len(xstr) Do While i>=1 tempstr=tempstr+Mid(xstr,i,1) i=i-1 Loop ystr=tempstr End SubA.fedcbaB.abcdefC.afbecdD.defabc ” 相关考题
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考题 下列程序的执行结果为 Private Sub Command1_Click() Dim s1 As String,s2 As String S1;="abcdef" Call Invert(s1,s2) Print s2 End Sub Private Sub Invert (ByVal xstr As String,ystr As String) Dim tempstr As String i=Len(xstr) Do While i=1 tempstr=tempstr+Mid(xstr,i,1) i=i-1 Loop ystr=tempstr End SubA.fedcbaB.abcdefC.afbecdD.defabc

考题 下列程序的执行结果为 Private Sub Commandl_Click() Dim s1 As String ,s2 As String s1= "abcd" Call Transfer(sl,s2) Print s2 End Sub Private Sub Transfer (ByVal xstr As String,ystr As String) Dim tempstr As String ystr=tempstr End SubA.dcbaB.abdcC.abcdD.dabc

考题 下列程序打印结果为 ______。Private Sub Command1_ Click() Dim a(5)As String Dim b As Integer Dim i As Integer for i = 0 To 5 a(i)= i +1 Print a(i); Next iEnd SubA.12345B.6C.1 2 3 4 5 6D.0