网友您好, 请在下方输入框内输入要搜索的题目:

题目内容 (请给出正确答案)

代数式|e3×a+1gy13+siny2|对应的Visual Bask表达式是( )。

A.Abs(e^3*a+1g(y1^3)+1/sin(y2))

B.Abs(Exp(3)*a+Log(y1^3)/Log(10)+sin(y2))

C.Abs(Exp(3)*a+Log(y1^3)+sin(y2))

D.Abs(Exp(3)*a+Log(y1^3)+1/sin(y2))


参考答案

更多 “ 代数式|e3×a+1gy13+siny2|对应的Visual Bask表达式是( )。A.Abs(e^3*a+1g(y1^3)+1/sin(y2))B.Abs(Exp(3)*a+Log(y1^3)/Log(10)+sin(y2))C.Abs(Exp(3)*a+Log(y1^3)+sin(y2))D.Abs(Exp(3)*a+Log(y1^3)+1/sin(y2)) ” 相关考题
考题 以下不能正确计算代数式值的C语言表达式是( )。A.1/3*sin(1/2)*sin(1/2)B.sin(0.5)*sin(0.5)/3C.pow(sin(0.5),2)/3D.40546.0*pow(sin(1.0/2),2)

考题 代数|3e+lgx+arctgy|对应的Visual Basic表达式是A.Abs(e3+lg(x)+1/Tg(y))B.Abs(Exp(3)+Log(x)/Log(10)+Atn(y))C.Abs(Exp(3)+Log(x)+Atn(y))D.Abs(Exp(3)+Log(x)+1/Atn(y))

考题 代数式,|e2×A+lgy13+sin y2|对应的Visual Basic表达式是 ______。A.Abs(e^2*a+Log(y1^3)+Sin(y2))B.Abs(Exp(2)*a+Log(y1^3)/Log(10)+Sin(y2))C.Abs(e^2*a+lg(y1^3)+Sin(y2))D.Abs(Exp(2)*a+Log(y1^3)+Sin(y2))

考题 以下不能正确计算代数式sin2()值的C语言表达式是______。A.1/3*sin(1/2)*sin(1/2)B.sin(0.5)*sin(0.5)/3C.pow(sin(0.5),2)/3D.1/3.0*pow(sin(1.0/2), 2)

考题 以下不能正确计算代数式1/3sin2(1/2)值的C语言表达式是 ______。A.1/3*sin(1/2)*sin(1/2)B.sin(0.5)*sin(0.5)/3C.pow(sin(0.5),2)/3D.1/3.0*pow(sin(1.0.2),2)

考题 代数|3e+lgx+arctgy|对应的Visual Basic表达式是A.Abs(e^3+Lg(x)+L/Tg(y) )B.Abs(Exp(3)+Log(x)/Log(10)+Atn(y))C.Abs(Exp(3)+Log(x)+Atn(y) )D.Abs(Exp(3)+Log(x)+1/Atn(y) )

考题 以下不能正确计算代数式sin2()值的C语言表达式是( )。A.1/3*sin(1/2)*sin(1/2)B.sin(0.5)*sin(0.5)/3C.pow(sin(0.5),2)/3D.1/3.0*pow(sin(1.0/2),2)

考题 运行以下程序,则在图形窗口中可以看到()条曲线。 x=0:0.1:10; y1=sin(x); y2=5*sin(x); y3=[10*sin(x);20*sin(x)]; plot(x,y1,x,y2,x,y3)A.3B.4C.5D.6

考题 分别用红、绿、蓝三种颜色在同一个图形窗口绘制下列函数在区间[-pi, pi]的图形,y=sin(x),y=cos(x),y=tan(x).A.clear x=-pi:0.1:pi; y1=sin(x); y2=cos(x); y3=tan(x); plot(x,y1,'r',x,y2,'g',x,y3,'b')#B.clear x=-pi:0.1:pi; y1=sin(x); plot(x,y1,'r') y2=cos(x); plot(x,y2,'g') y3=tan(x); plot(x,y3,'b')#C.clear x=-pi:0.1:pi; y1=sin(x); plot(x,y1,'r') hold on y2=cos(x); plot(x,y2,'g') y3=tan(x); plot(x,y3,'b')#D.clear x=-pi:0.1:pi; y1=sin(x); plot(x,y1,'r') y2=cos(x); plot(x,y2,'g') y3=tan(x); plot(x,y3,'b')#E.clear x=-pi:0.1:pi;