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Student A:I feel sick.Student B:______Student A:I'm not sure,but I have got a bad headache.
A: I'm sorry to hear that.
B: How are you feeling now?
C: How long have you been sick?
D: Do you have a temperature?
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更多 “ Student A:I feel sick.Student B:______Student A:I'm not sure,but I have got a bad headache. A: I'm sorry to hear that.B: How are you feeling now?C: How long have you been sick?D: Do you have a temperature? ” 相关考题
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Student: Good morning, Professor Liu. ______I'm late.Professor: You are late every morning. You were late Tuesday, yesterday...Don't you have a watch?
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c＋＋,运行下面代码出错
#include iostreamusing namespace std;struct student_info{ string name; int chinese; int math; int english;};student_info student[5];void inputinfo(){ int i = 0; char a[20]; for(i = 0;i 5;i++) { cout"enter the "i+1" student's information "endl; cout"enter the name"endl; cina; student[i].name = a; cout"enter chinese performance :"endl; cinstudent[i].chinese; cout"enter math performance :"endl; cinstudent[i].math; cout"enter english performance :"endl; cinstudent[i].english; }}void outputinfo(){ int i = 0; while(i 5) { couti+1" student's information"endl; coutstudent[i].name.c_str()endl; cout"chinese "endl; coutstudent[i].chineseendl; cout"math "endl; coutstudent[i].mathendl; cout"english "endl; coutstudent[i].englishendl; i++; }}int avgfunction(int arr[],int n){ int i = 0; int total = 0; for(i = 0;i n;i++) { total += arr[i]; } return total / n;}void computavg() //这里是否正确？{ int theavg = 0; theavg = avgfunction(student[i].chinese,5); }int main(){ inputinfo(); outputinfo(); computavg(); cin.get(); return 0;} 帮我找出错误 然后改过来 择优为满意答案 不分先后
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Hi, Helen, I'll have an interview tomorrow. I'm afraid I can't make it. ()A. Sure, you can. Take it easy.B. I'm sorry to hear that.C. That's all right.
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阅读下列程序说明和C++代码，将应填入(n)处的字句写在对应栏内。[说明]①定义私有数据成员code、english分别用于表示考生的编号、英语成绩，它们都是int型的数据。②完成成员函数void Student::inputinformation()的定义，该函数用于用户输入一个考生对象的信息，输入格式如下：输入编号：英语成绩：计算机成绩：③利用已实现的类Student的成员函数，完成函数void firstname(Student *A[]，int uum)的定义，该函数根据考生信息A[]，输出num个考生中总分最高者的编号及其相应的总分，在此不考虑总分相同的情况。源程序文件test1.cpp清单如下：include ＜ iostream. h ＞class Student(1)int computer;int total;publicvoid getinformation( );void computesum( );int getcode( );int gettotalscore( );~Student( );};void Student: :getinformation( ){(2)cout ＜＜"英语成绩:";cin＞ ＞english;cout ＜＜"计算机成绩:";cin ＞ ＞ computer;void Student:: computesum ( )total = english + computer;cout ＜＜"编号" ＜＜ code ＜＜"总分:" ＜＜total ＜＜ endl;int Student::getcode( )return code;}int Student:: gettotalscore ( ){return total;}void firstname(Student * A[] ,int num){(3)tempsum = ( * A[0] ). gettotalscore( );for( int i=1; i ＜num; i++){if ( ( ( * A[i] ). gettotalscore( ) ) ＞ tempsum){tempcode = ( * A[i] ). getcode( );tempsum = ( * A[i] ). gettotalscore( );}}cout ＜＜"总分最高者--" ＜＜ tempcode ＜＜":" ＜＜ tempsum ＜＜endl;}void main( ){Student * A[3];int i,n =3for(i=0;i＜n;i ++)A[i] = new Student;A[i] -＞ getinformation( )for(i=0;i＜n;i ++){A[i] -＞ computesum( )firstname ( A,3 );}
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设有以下结构类型，并且结构数组student中的元素都已有值，若要将这些元素写到硬盘文件fp中，以下形式错误的是 struct st { char name[8]; int num; float s[4]; } student[50];A．fwrite(student, 25 * sizeof(struct st), 2, fp);B．fwrite(student, sizeof(struct st), 50, fp);C．fwrite(student, 50 * sizeof(struct st), 1, fp);D．for (i = 0; i ＜ 50; i++) fwrite(student, sizeof(struct st), 1, fp);
考题
设有以下结构类型，并且结构数组student中的元素都已有值，若要将这些元素写到硬盘文件fp中，以下形式错误的是 struct st { char name[8]; int num; float s[4]; } student[50];A．fwrite(student, 25 * sizeof(struct st), 1, fp);B．fwrite(student, sizeof(struct st), 50, fp);C．fwrite(student, 50 * sizeof(struct st), 1, fp);D．for (i = 0; i ＜ 50; i++) fwrite(student, sizeof(struct st), 1, fp);
考题
设有以下结构类型，并且结构数组student中的元素都已有值，若要将这些元素写到硬盘文件fp中，以下形式错误的是 struct st { char name[8]; int num; float s[4]; } student[50];A．fwrite(student, 25 * sizeof(struct st), 2, fp);B．fwrite(student, sizeof(struct st), 50, fp);C．fwrite(student, 50 * sizeof(struct st), 1, fp);D．for (i = 0; i 50; i++) fwrite(student, sizeof(struct st), 1, fp);
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若有定义：char strl[10],str2[ ]="student"; 以下能把str2中的字符串赋给strl的语句是（）。A．for(int i=0; i＜=strlen(str2); i++) str1[ i ]=str2[ i ];B．str1="student";C．str1=str2;D．for(int i=0; str2[ i ]!=0; i++) str1[ i ]=str2[ i ];
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