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以下代码的运行结果为: counter=1 def doLotsOfStuff(): global counter for i in (1,2,3): counter+=1 doLotsOfStuff() print(counter)
A.4
B.5
C.1
D.代码错误
参考答案和解析
A
更多 “以下代码的运行结果为: counter=1 def doLotsOfStuff(): global counter for i in (1,2,3): counter+=1 doLotsOfStuff() print(counter)A.4B.5C.1D.代码错误” 相关考题
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