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5、Nn受体主要位于
A.神经节细胞
B.心肌细胞
C.血管平滑肌细胞
D.骨骼肌细胞
参考答案和解析
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【程序】SET TALK OFFN=325X=“ABCDEFGHIJ”Y=“甲乙丙丁戊已.”NC=ALLTRIM(STR(N,6))L=LEN(NC)N2=2*L-1NN="K=1DO WHILE K<=LN1=INT(VAL(SUBSTR(NC,K,1))* 2+1)NN=NN+SUBSTR(X,N1,1)NN=NN+SUBSTR(Y,N2,2)? N1,N2,NNN2=N2-2K=K+1ENDDO? KSET TALK ON第一次输出结果为 ______。A.7 4G 甲B.7 5G乙C.7 5G 丙D.7 4G乙
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对受体叙述正确的是()A、α1受体主要位于突触前膜B、α2受体主要位于突触后膜及非突触部位C、血管平滑肌细胞有α1、α2共存现象D、β2受体主要分布在心肌及其他部位E、在脊髓,β受体比α受体更有生理学意义
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Consider the following command: Backup database plus archivelog delete input; How many backup sets would be created by this command if the following were true:() Control-file a NN uto backups were enabled. NN The size of backup sets was not restricted. NN One channel was allocated. A、 1B、 2C、 3D、 4E、 5
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单选题Consider the following command: Backup database plus archivelog delete input; How many backup sets would be created by this command if the following were true:() Control-file a NN uto backups were enabled. NN The size of backup sets was not restricted. NN One channel was allocated.A
1B
2C
3D
4E
5
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单选题Which statement adds a constraint that ensures the CUSTOMER_NAME column of the CUSTOMERS table holds a value?()A
ALTER TABLE customers ADD CONSTRAINT cust_name_nn CHECK customer_name IS NOT NULL;B
ALTER TABLE customers MODIFY CONSTRAINT cust_name_nn CHECK customer_name IS NOT NULL;C
ALTER TABLE customers MODIFY customer_name CONSTRAINT cust_name_nn NOT NULL;D
ALTER TABLE customers MODIFY customer_name CONSTRAINT cust_name_nn IS NOT NULL;E
ALTER TABLE customers MODIFY name CONSTRAINT cust_name_nn NOT NULL;F
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单选题有以下程序:#includemain(){ char *s=120119110; int n0,n1,n2,nn,i; n0=n1=n2=nn=i=0; do { switch(s[i++]) { default:nn++; case '0':n0++; case '1':n1++; case '2':n2++; } }while(s[i]); printf(n0=%d,n1=%d,n2=%d,nn=%d,n0,n1,n2,nn);}程序的运行结果是( )。A
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n0=4,n1=8,n2=9,nn=1
考题
单选题对受体叙述正确的是()A
α1受体主要位于突触前膜B
α2受体主要位于突触后膜及非突触部位C
血管平滑肌细胞有α1、α2共存现象D
β2受体主要分布在心肌及其他部位E
在脊髓,β受体比α受体更有生理学意义
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