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关于以下代码的描述,错误的选项是() with open('abc.txt', 'r+') as f: lines = f.readlines() for item in lines: print(item)

A.执行代码后,abc.txt文件未关闭,必须通过close()函数关闭

B.程序功能是打印输出abc.txt文件内容

C.lines是列表类型

D.item是字符串类型


参考答案和解析
修改代码为:a = [1,2,3]print(id(a))a = "Runoob"print(id(a))执行时,输出2行的内容相同。
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