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单选题
Given the following tables: CONTINENTS ID NAME COUNTRIES 1 Antarctica 0 2 Africa 53 3 Asia 47 4 Australia 14 5 Europe 43 6 North America 23 7 South America 12 REGION ID LOCATION 1 East 2 West How many rows would be returned using the following statement? SELECT location FROM continents, region（）
A
2
B
7
C
9
D
14
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更多 “单选题Given the following tables: CONTINENTS ID NAME COUNTRIES 1 Antarctica 0 2 Africa 53 3 Asia 47 4 Australia 14 5 Europe 43 6 North America 23 7 South America 12 REGION ID LOCATION 1 East 2 West How many rows would be returned using the following statement? SELECT location FROM continents, region（）A 2B 7C 9D 14” 相关考题
考题
学生表(id,name,sex,age,depart_id,depart_name),存在的函数依赖是id→{name,sex,age,depart_id};dept_id→dept_name,其满足()、
A、1NFB、2NFC、3NFD、4NF
考题
学生表(id,name,sex,age,depart_id,depart_name),存在函数依赖是id→name,sex,age,depart_id;dept_id→dept_name,其满足()。
A、1NFB、2NFC、3NFD、BCNF
考题
ExhibitExamine the data in the EMPLOYEES and DEPARTMENTS tables.You want to retrieve all employees‘ last names, along with their manager‘s last names and their department names. Which query would you use?（）A. SELECT last_name, manager_id, department_name FROM employees e FULL OUTER JOIN department d ON (e.department_id = d.department_id);B. SELECT e.last_name, m.last_name, department_name FROM employees e LEFT OUTER JOIN employees m on ( e.managaer_id = m.employee_id) LEFT OUTER JOIN department d ON (e.department_id = d.department_id);C. SELECT e.last_name, m.last_name, department_name FROM employees e RIGT OUTER JOIN employees m on ( e.manager_id = m.employee_id) FULL OUTER JOIN department d ON (e.department_id = d.department_id);D. SELECT e.last_name, m.last_name, department_name FROM employees e LEFT OUTER JOIN employees m on ( e.manager_id = m.employee_id) RIGT OUTER JOIN department d ON (e.department_id = d.department_id);E. SELECT e.last_name, m.last_name, department_name FROM employees e RIGHT OUTER JOIN employees m on ( e.manager_id = m.employee_id) RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id)F. SELECT last_name, manager_id, department_name FROM employees e JOIN department d ON (e.department_id = d.department_id);
考题
Review the definition of the phone_list view.CHEATE OR REPLACE ALGORITHM=MERGE DEFINER= ‘root‘@localhost‘ SQL SECURITY DEFINER VIEW ‘phone_list‘ AS SELECTe . id as id ‘e . first_name AS ‘first_name‘ ‘e . last_name AS ‘last_name‘ ‘coalesce ( ph1.phone_no, ‘ – ‘) AS ‘office_no‘ ‘coalesce (ph2 .phone_no, ‘ – ‘) AS ‘cell_no‘ FROM employees e LEFT JOIN employee_phone ph1 ON ph1.emp_id = e.id AND ph1.type = ‘office‘ LEFT JOIN employee_phone ph2 ON ph2 .emp_id = e.id AND ph2 .type = ‘mobile‘The tables employees and employee_phone are InnoDB tables;all columns are used in this view. The contents of the phone_list view are as follows: Mysql select * from phone_list; 1 row in set (0.00 sec)Which method can you use to change the cell_no value to ‘555-8888‘ for John Doe?（）A.INSERT INTO employee_phone (emp_id, phone_no, type) VALUES (1, ‘555-8888‘,‘mobile‘)B.UPDATE phone_list SET cell_name ‘555-8888‘ WHERE first_name= ‘John‘ and last_name= ‘Doe‘C.DELETE FROM phone_list WHERE first_name= ‘John‘ and last_name= ‘Doe‘; INSERT INTO phone_list (first_name, last_name, office_no, cell_no) VALUES (‘John‘ , ‘Doe‘ , ‘x1234‘ , ‘555-8888)D.UPDATE employee_phone SET phone_no= ‘555-8888‘ where emp_id=1
考题
Examine the structure of the EMPLOYEES, DEPARTMENTS, and TAX tables.For which situation would you use a nonequijoin query?()
A. To find the tax percentage for each of the employees.B. To list the name, job id, and manager name for all the employees.C. To find the name, salary, and department name of employees who are not working with Smith.D. To find the number of employees working for the Administrative department and earning less then 4000.E. To display name, salary, manager ID, and department name of all the employees, even if the employees do not have a department ID assigned.
考题
Examine the structure of the EMPLOYEES, DEPARTMENTS, and TAX tables.EMPLOYEESNOT NULL, PrimaryEMPLOYEE_ID NUMBERKeyVARCHAR2EMP_NAME(30)VARCHAR2JOB_ID(20)SALARY NUMBERReferencesMGR_ID NUMBEREMPLOYEE_IDcolumnDEPARTMENT_ID NUMBER Foreign key toDEPARTMENT_IDcolumn ofthe DEPARTMENTStableDEPARTMENTSNOT NULL,DEPARTMENT_ID NUMBERPrimary KeyVARCHAR2DEPARTMENT_NAME|30|ReferencesMGR_ID columnMGR_ID NUMBERof theEMPLOYEES tableTAXMIN_SALARY NUMBERMAX_SALARY NUMBERTAX_PERCENT NUMBERFor which situation would you use a nonequijoin query?（）A. To find the tax percentage for each of the employees.B. To list the name, job id, and manager name for all the employees.C. To find the name, salary, and department name of employees who are not working with Smith.D. To find the number of employees working for the Administrative department and earning less then 4000.E. To display name, salary, manager ID, and department name of all the employees, even if the employees do not have a department ID assigned.
考题
Examine the structure of the EMPLOYEES, DEPARTMENTS, and LOCATIONS tables.EMPLOYEESNOT NULL,EMPLOYEE_ID NUMBERPrimary KeyVARCHAR2EMP_NAME(30)VARCHAR2JOB_ID(20)SALARY NUMBERReferencesMGR_ID NUMBEREMPLOYEE_IDcolumnDEPARTMENT_ID NUMBER Foreign key toDEPARTMENT_IDcolumn of theDEPARTMENTStableDEPARTMENTSNOT NULL, PrimaryDEPARTMENT_ID NUMBERKeyVARCHAR2DEPARTMENT_NAME(30)References NGR_IDMGR_ID NUMBERcolumn ofthe EMPLOYEES tableForeign key toLOCATION_ID NUMBERLOCATION_IDcolumn of theLOCATIONS tableLOCATIONSNOT NULL, PrimaryLOCATION_ID NUMBERKeyVARCHAR2CITY|30)Which two SQL statements produce the name, department name, and the city of all the employees who earn more then 10000?（）A. SELECT emp_name, department_name, city FROM employees e JOIN departments d USING (department_id) JOIN locations 1 USING (location_id) WHERE salary 10000;B. SELECT emp_name, department_name, city FROM employees e, departments d, locations 1 JOIN ON (e.department_id = d.department id) AND (d.location_id =1.location_id) AND salary 10000;C. SELECT emp_name, department_name, city FROM employees e, departments d, locations 1 WHERE salary 10000;D. SELECT emp_name, department_name, city FROM employees e, departments d, locations 1 WHERE e.department_id = d.department_id AND d.location_id = 1.location_id AND salary 10000;E. SELECT emp_name, department_name, city FROM employees e NATURAL JOIN departments, locations WHERE salary 10000;
考题
Click the Exhibit button to examine the structures of the EMPLOYEES, DEPARTMENTS, and TAX tables.For which situation would you use a nonequijoin query?()
A.to find the tax percentage for each of the employeesB.to list the name, job_id, and manager name for all the employeesC.to find the name, salary, and the department name of employees who are not working with SmithD.to find the number of employees working for the Administrative department and earning less than 4000E.to display name, salary, manager ID, and department name of all the employees, even if the employees do not have a department ID assigned
考题
Given the following tables: CONTINENTS ID NAME COUNTRIES1 Antarctica 02 Africa 533 Asia 474 Australia 145 Europe 436 North America 237 South America 12REGION ID LOCATION 1 East 2 WestHow many rows would be returned using the following statement? SELECT location FROM continents, region（）A.2B.7C.9D.14
考题
Given the following tables: CONTINENTS ID NAME COUNTRIES 1 Antarctica 0 2 Africa 53 3 Asia 47 4 Australia 14 5 Europe 43 6 North America 23 7 South America 12 REGION ID LOCATION 1 East 2 West How many rows would be returned using the following statement? SELECT location FROM continents, region（）A、2B、7C、9D、14
考题
On IBM System Stoage DS8000 which of the following information pairs are mandatory to create a volume（）A、extent pool id and volume idB、extent pool id and volume nameC、volume id and extent allocation methodD、volume name and extent allocation method
考题
You executed the following code： SQL CERATE TABLE COUNTRY （COUNTRY_ID CHAR（2） CONSTRAINT COUNTRY_ID_nn NOT NULL， COUNTRY_NAME VARCHAR2（20）， CURRENCY_NAME VARCHAR2（20）， CONSTRAINT COUNTRY_ID_PK PRIMARY KEY （COUNTRY_ID）） ORGANIZATION INDEX； Which types of tables will be created automatically？（）A、 journal tableB、 clustered tableC、 mapping tableD、 partitioned table
考题
Examine the structure of the EMPLOYEES and NEW_EMPLOYEES tables: EMPLOYEES EMPLOYEE_ID NUMBER Primary Key FIRST_NAME VARCHAR2(25) LAST_NAME VARCHAR2(25) HIRE_DATE DATE NEW_EMPLOYEES EMPLOYEE_ID NUMBER Primary Key NAME VARCHAR2 (60) Which DELETE statement is valid?（）A、DELETE FROM employees WHERE employee_id = (SELECT employee_id FROM employees);B、DELETE * FROM employees WHERE employee_id = (SELECT employee_id FROM new_ employees);C、DELETE FROM employees WHERE employee_id IN (SELECT employee_id FROM new_employees WHERE name = 'carrey');D、DELETE * FROM employees WHERE employee_id IN (SELECT employee_id FROM new_employees WHERE name = 'carrey');
考题
单选题You executed the following code： SQL CERATE TABLE COUNTRY （COUNTRY_ID CHAR（2） CONSTRAINT COUNTRY_ID_nn NOT NULL， COUNTRY_NAME VARCHAR2（20）， CURRENCY_NAME VARCHAR2（20）， CONSTRAINT COUNTRY_ID_PK PRIMARY KEY （COUNTRY_ID）） ORGANIZATION INDEX； Which types of tables will be created automatically？（）A
journal tableB
clustered tableC
mapping tableD
partitioned table
考题
单选题下列关于匿名类正确的是（）。A
ListStudentlist=new{Id=1，Name=张三}；B
varstu=newStudent{Id=1，Name=张三}；C
varstu=new{Id=1，Name=张三}；D
publicclassvar{}varstu=new{Id=1，Name=张三}；
考题
单选题Examine the structure of the EMPLOYEES and DEPARTMENTS tables: EMPLOYEES EMPLOYEE_ID NUMBER DEPARTMENT_ID NUMBER MANAGER_ID NUMBER LAST_NAME VARCHAR2(25) DEPARTMENTS DEPARTMENT_ID NUMBER MANAGER_ID NUMBER DEPARTMENT_NAME VARCHAR2(35) LOCATION_ID NUMBER You want to create a report displaying employee last names, department names, and locations. Which query should you use to create an equi-join?（）A
SELECT last_name, department_name, location_id FROM employees , department ;B
SELECT employees.last_name, departments.department_name, departments.location_id FROM employees e, departments D WHERE e.department_id = d.department_id;C
SELECT e.last_name, d.department_name, d.location_id FROM employees e, departments D WHERE manager_id = manager_id;D
SELECT e.last_name, d.department_name, d.location_id FROM employees e, departments D WHERE e.department_id = d.department_id;
考题
单选题You created a view called EMP_DEPT_VU that contains three columns from the EMPLOYEES and DEPARTMENTS tables: EMPLOYEE_ID, EMPLOYEE_NAME AND DEPARTMENT_NAME. The DEPARTMENT_ID column of the EMPLOYEES table is the foreign key to the primary key DEPARTMENT_ID column of the DEPARTMENTS table. You want to modify the view by adding a fourth column, MANAGER_ID of NUMBER data type from the EMPLOYEES tables. How can you accomplish this task?（）A
ALTER VIEW EMP_dept_vu (ADD manger_id NUMBER);B
MODIFY VIEW EMP_dept_vu (ADD manger_id NUMBER);C
ALTER VIEW emp_dept_vu AS SELECT employee_id, employee_name, department_name, manager_id FROM employee e, departments d WHERE e.department _ id = d.department_id;D
MODIFY VIEW emp_dept_vu AS SELECT employee_id, employee_name, department_name, manager_id FROM employees e, departments d WHERE e.department _ id = d.department_id;E
CREATE OR REPLACE VIEW emp_dept_vu AS SELECT employee_id, employee_name, department_name, manager_id FROM employees e, departments d WHERE e.department _ id = d.department_id;F
You must remove the existing view first, and then run the CREATE VIEW command with a new column list to modify a view.
考题
多选题Examine the structure of the EMPLOYEES, DEPARTMENTS, and LOCATIONS tables. EMPLOYEES NOT NULL, EMPLOYEE_ID NUMBER Primary Key VARCHAR2 EMP_NAME (30) VARCHAR2 JOB_ID (20) SALARY NUMBER References MGR_ID NUMBER EMPLOYEE_ID column DEPARTMENT_ID NUMBER Foreign key to DEPARTMENT_ID column of the DEPARTMENTS table DEPARTMENTS NOT NULL, Primary DEPARTMENT_ID NUMBER Key VARCHAR2 DEPARTMENT_NAME (30) References NGR_ID MGR_ID NUMBER column of the EMPLOYEES table Foreign key to LOCATION_ID NUMBER LOCATION_ID column of the LOCATIONS table LOCATIONS NOT NULL, Primary LOCATION_ID NUMBER Key VARCHAR2 CITY |30) Which two SQL statements produce the name, department name, and the city of all the employees who earn more then 10000?（）ASELECT emp_name, department_name, city FROM employees e JOIN departments d USING (department_id) JOIN locations 1 USING (location_id) WHERE salary 10000;BSELECT emp_name, department_name, city FROM employees e, departments d, locations 1 JOIN ON (e.department_id = d.department id) AND (d.location_id =1.location_id) AND salary 10000;CSELECT emp_name, department_name, city FROM employees e, departments d, locations 1 WHERE salary 10000;DSELECT emp_name, department_name, city FROM employees e, departments d, locations 1 WHERE e.department_id = d.department_id AND d.location_id = 1.location_id AND salary 10000;ESELECT emp_name, department_name, city FROM employees e NATURAL JOIN departments, locations WHERE salary 10000;
考题
单选题Examine the structure of the EMPLOYEES and DEPARTMENTS tables: EMPLOYEESColumn name Data type Remarks EMPLOYEE_ID NUMBER NOT NULL, Primary Key EMP_NAME VARCHAR2 (30) JOB_ID VARCHAR2 (20) SALARY NUMBER MGR_ID NUMBER References EMPLOYEE_ID COLUMN DEPARTMENT ID NUMBER Foreign key to DEPARTMENT ID column of the DEPARTMENTS table DEPARTMENTSColumn name Data type Remarks DEPARTMENT_ID NUMBER NOT NULL, Primary Key DEPARTMENT_NAME VARCHAR2(30) MGR_ID NUMBER References MGR_ID column of the EMPLOYEES table Evaluate this SQL statement: SELECT employee_id, e.department_id, department_name, salary FROM employees e, departments d WHERE e. department_id = d.department_id; Which SQL statement is equivalent to the above SQL statement? （）A
SELECT employee_id, department_id, department_name, salary FROM employees WHERE department_id IN (SELECT department_id FROM departments);B
SELECT employee_id, department_id, department_name, salary FROM employees NATURAL JOIN departments;C
SELECT employee_id, d.department_id, department_name, salary FROM employees e JOIN departments d ON e.department _ id = d. department_id;D
SELECT employee_id, department_id, department_name, Salary FROM employees JOIN departments USING (e.department_id, d.department_id);
考题
单选题Examine the structure of the EMPLOYEES and NEW_EMPLOYEES tables: EMPLOYEES EMPLOYEE_ID NUMBER Primary Key FIRST_NAME VARCHAR2 (25) LAST_NAME VARCHAR2 (25) HIRE_DATE DATE NEW EMPLOYEES EMPLOYEE_ID NUMBER Primary Key NAME VARCHAR2 (60) Which DELETE statement is valid? （）A
DELETE FROM employees WHERE employee_id = (SELECT employee_id FROM employees);B
DELETE * FROM employees WHERE employee_id = (SELECT employee_id FROM new_ employees);C
DELETE FROM employees WHERE employee_id IN (SELECT employee_id FROM new_employees WHERE name = ('Carrey')'D
DELETE * FROM employees WHERE employee_id IN (SELECT employee_id FROM new_employees WHERE last_ name = ('Carrey')'
考题
单选题Click the Exhibit button and examine the data in the EMPLOYEES and DEPARTMENTS tables.You want to retrieve all employees, whether or not they have matching departments in the departments table. Which query would you use?（）A
SELECT last_name, department_name FROM employees NATURAL JOIN departments;B
SELECT last_name, department_name FROM employees JOIN departments ;C
SELECT last_name, department_name FROM employees e JOIN departments d ON (e.department_id = d.department_id);D
SELECT last_name, department_name FROM employees e RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id);E
SELECT last_name, department_name FROM employees FULL JOIN departments ON (e.department_id = d.department_id);F
SELECT last_name, department_name FROM employees e LEFT OUTER JOIN departments d ON (e.department_id = d.department_id);
考题
单选题Examine the data in the EMPLOYEES and DEPARTMENTS tables. EMPLOYEES LAST_NAME DEPARTMENT_ID SALARY Getz 10 3000 Davis 20 1500 Bill 20 2200 Davis 30 5000 Kochhar 5000 DEPARTMENTS DEPARTMENT_ID DEPARTMENT_NAME 10 Sales 20 Marketing 30 Accounts 40 Administration You want to retrieve all employees, whether or not they have matching departments in the departments table. Which query would you use?（）A
SELECT last_name, department_name FROM employees , departments(+);B
SELECT last_name, department_name FROM employees JOIN departments(+);C
SELECT last_name, department_name ON (e. department_ id = d. departments_id); FROM employees(+) e JOIN departments dD
SELECT last_name, department_name FROM employees e RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id);E
SELECT last_name, department_name FROM employees(+) , departments ON (e. department _ id = d. department _id);F
SELECT last_name, department_name FROM employees e LEFT OUTER JOIN departments d ON (e. department _ id = d. department _id);
考题
单选题Examine the structure of the EMPLOYEES and DEPARTMENTS tables: EMPLOYEESColumn name Data type Remarks EMPLOYEE_ID NUMBER NOT NULL, Primary Key EMP_NAME VARCHAR2 (30) JOB_ID VARCHAR2 (20) SALARY NUMBER MGR_ID NUMBER References EMPLOYEE_ID COLUMN DEPARTMENT ID NUMBER Foreign key to DEPARTMENT ID column of the DEPARTMENTS table DEPARTMENTSColumn name Data type Remarks DEPARTMENT_ID NUMBER NOT NULL, Primary Key DEPARTMENT_NAME VARCHAR2(30) MGR_ID NUMBER References MGR_ID column of the EMPLOYEES table Evaluate this SQL statement: SELECT employee_id, e.department_id, department_name, salary FROM employees e, departments d WHERE e. department_id = d.department_id; Which SQL statement is equivalent to the above SQL statement?（）A
SELECT employee_id, department_id, department_name, salary FROM employees WHERE department_id IN (SELECT department_id FROM departments);B
SELECT employee_id, department_id, department_name, salary FROM employees NATURAL JOIN departments;C
SELECT employee_id, d.department_id, department_name, salary FROM employees e JOIN departments d ON e.department _ id = d. department_id;D
SELECT employee_id, department_id, department_name, Salary FROM employees JOIN departments USING (e.department_id, d.department_id);
考题
单选题Examine the structure of the EMPLOYEES and DEPARTMENTS tables: EMPLOYEES EMPLOYEE_ID NUMBER DEPARTMENT_ID NUMBER MANAGER_ID NUMBER LAST_NAME VARCHAR2(25) DEPARTMENTS DEPARTMENT_ID NUMBER MANAGER_ID NUMBER DEPARTMENT_NAME VARCHAR2(35) LOCATION_ID NUMBER You want to create a report displaying employee last names, department names, and locations. Which query should you use?（）A
SELECT e.last_name, d. department_name, d.location_id FROM employees e NATURAL JOIN departments D USING department_id ;B
SELECT last_name, department_name, location_id FROM employees NATURAL JOIN departments WHERE e.department_id =d.department_id;C
SELECT e.last_name, d.department_name, d.location_id FROM employees e NATURAL JOIN departments d;D
SELECT e.last_name, d.department_name, d.location_id FROM employees e JOIN departments d USING (department_id );
考题
单选题Examine the structure of the EMPLOYEES, DEPARTMENTS, and TAX tables. EMPLOYEES NOT NULL, Primary EMPLOYEE_ID NUMBER Key VARCHAR2 EMP_NAME (30) VARCHAR2 JOB_ID (20) SALARY NUMBER References MGR_ID NUMBER EMPLOYEE_ID column DEPARTMENT_ID NUMBER Foreign key to DEPARTMENT_ID column of the DEPARTMENTS table DEPARTMENTS NOT NULL, DEPARTMENT_ID NUMBER Primary Key VARCHAR2 DEPARTMENT_NAME |30| References MGR_ID column MGR_ID NUMBER of the EMPLOYEES table TAX MIN_SALARY NUMBER MAX_SALARY NUMBER TAX_PERCENT NUMBER For which situation would you use a nonequijoin query?（）A
To find the tax percentage for each of the employees.B
To list the name, job id, and manager name for all the employees.C
To find the name, salary, and department name of employees who are not working with Smith.D
To find the number of employees working for the Administrative department and earning less then 4000.E
To display name, salary, manager ID, and department name of all the employees, even if the employees do not have a department ID assigned.
考题
单选题Examine the structure of the EMPLOYEES, DEPARTMENTS, and TAX tables. EMPLOYEES NOT NULL, Primary EMPLOYEE_ID NUMBER Key VARCHAR2 EMP_NAME (30) VARCHAR2 JOB_ID (20) SALARY NUMBER References MGR_ID NUMBER EMPLOYEE_ID column DEPARTMENT_ID NUMBER Foreign key to DEPARTMENT_ID column of the DEPARTMENTS table DEPARTMENTS NOT NULL, DEPARTMENT_ID NUMBER Primary Key VARCHAR2 DEPARTMENT_NAME |30| References MGR_ID column MGR_ID NUMBER of the EMPLOYEES table TAX MIN_SALARY NUMBER MAX_SALARY NUMBER TAX_PERCENT NUMBER For which situation would you use a nonequijoin query?（）A
To find the tax percentage for each of the employees.B
To list the name, job id, and manager name for all the employees.C
To find the name, salary, and department name of employees who are not working with Smith.D
To find the number of employees working for the Administrative department and earning less then 4000.E
To display name, salary, manager ID, and department name of all the employees, even if the employees do not have a department ID assigned.
考题
单选题Given the following tables: CONTINENTS ID NAME COUNTRIES 1 Antarctica 0 2 Africa 53 3 Asia 47 4 Australia 14 5 Europe 43 6 North America 23 7 South America 12 REGION ID LOCATION 1 East 2 West How many rows would be returned using the following statement? SELECT location FROM continents, region（）A
2B
7C
9D
14
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