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单选题
客户需要计算EMP表中所有职工12*salary* commission_pct的值.EMP表结构如下：LAST NAME VARCNAR2（35）NOT NULL SALARY NUMBER（9，2）NOT NULL COMMISION_PCTNUMBER（4，2）哪个语句可以查询计算EMP表中所有职工行？（）
A
SELECT last_name，12*salary* commission_pct FROM emp
B
SELECT last_name，12*salary*（commission_pct，0）FROM emp
C
SELECT last_name，12*salary*（nvl（commission_pct，0））FROM emp如果oracle第一个参数为空那么显示第二个参数的值，如果第一个参数的值不为空，则显示第一个参数本来的值
D
SELECT last_name，12*salary*（decode（commission_pct，0））FROM emp
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更多 “单选题客户需要计算EMP表中所有职工12*salary* commission_pct的值.EMP表结构如下：LAST NAME VARCNAR2（35）NOT NULL SALARY NUMBER（9，2）NOT NULL COMMISION_PCTNUMBER（4，2）哪个语句可以查询计算EMP表中所有职工行？（）A SELECT last_name，12*salary* commission_pct FROM empB SELECT last_name，12*salary*（commission_pct，0）FROM empC SELECT last_name，12*salary*（nvl（commission_pct，0））FROM emp如果oracle第一个参数为空那么显示第二个参数的值，如果第一个参数的值不为空，则显示第一个参数本来的值D SELECT last_name，12*salary*（decode（commission_pct，0））FROM emp” 相关考题
考题
客户需要计算EMP表中所有职工12*salary* commission_pct的值.EMP表结构如下:LAST NAME VARCNAR2(35)NOT NULL SALARY NUMBER(9,2)NOT NULL COMMISION_PCTNUMBER(4,2)哪个语句可以查询计算EMP表中所有职工行?()
A.SELECT last_name，12*salary* commission_pct FROM empB.SELECT last_name，12*salary*（commission_pct，0）FROM empC.SELECT last_name，12*salary*（nvl（commission_pct，0））FROM emp如果oracle第一个参数为空那么显示第二个参数的值，如果第一个参数的值不为空，则显示第一个参数本来的值D.SELECT last_name，12*salary*（decode（commission_pct，0））FROM emp
考题
EMPLOYEES中职员编号为90的职员的commission_pct为空值,salary为1000,语句select12*salary*(commission_pct＋0.2)comm from EMPLOYEES;comm显示的结果是()。
A.12000B.0C.2400D.NULL
考题
The EMPLOYEES table contains these columns:LAST_NAME VARCHAR2 (25)SALARY NUMBER (6,2)COMMISSION_PCT NUMBER (6)You need to write a query that will produce these results:1. Display the salary multiplied by the commission_pct.2. Exclude employees with a zero commission_pct.3. Display a zero for employees with a null commission value. Evaluate the SQL statement:SELECT LAST_NAME, SALARY*COMMISSION_PCT FROM EMPLOYEESWHERE COMMISSION_PCT IS NOT NULL;What does the statement provide? （）A. All of the desired resultsB. Two of the desired resultsC. One of the desired resultsD. An error statement
考题
The EMPLOYEE tables has these columns:LAST_NAME VARCHAR2(35)SALARY NUMBER(8,2)COMMISSION_PCT NUMBER(5,2)You want to display the name and annual salary multiplied by the commission_pct for all employees. For records that have a NULL commission_pct, a zero must be displayed against the calculated column.Which SQL statement displays the desired results? （）A. SELECT last_name, (salary * 12) * commission_pct FROM EMPLOYEES;B. SELECT last_name, (salary * 12) * IFNULL(commission_pct, 0) FROM EMPLOYEES;C. SELECT last_name, (salary * 12) * NVL2(commission_pct, 0) FROM EMPLOYEES;D. SELECT last_name, (salary * 12) * NVL(commission_pct, 0) FROM EMPLOYEES;
考题
Examine the data in the EMPLOYEES table:LAST_NAME DEPARTMENT_ID SALARYGetz 10 3000Davis 20 1500Bill 20 2200Davis 30 5000...Which three subqueries work? ()
A. SELECT * FROM employees where salary (SELECT MIN(salary) FROM employees GROUP BY department _ id);B. SELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department _ id);C. SELECT distinct department_id FROM employees Where salary ANY (SELECT AVG(salary) FROM employees GROUP BY department _ id);D. SELECT department_id FROM employees WHERE SALARY ALL (SELECT AVG(salary) FROM employees GROUP BY department _ id);E. SELECT last_name FROM employees Where salary ANY (SELECT MAX(salary) FROM employees GROUP BY department _ id);F. SELECT department_id FROM employees WHERE salary ALL (SELECT AVG(salary) FROM employees GROUP BY ANG (SALARY));
考题
The EMPLOYEES table contains these columns: LAST_NAME VARCHAR2 (25) SALARY NUMBER (6,2) COMMISSION_PCT NUMBER (6) You need to write a query that will produce these results: 1.Display the salary multiplied by the commission_pct. 2.Exclude employees with a zero commission_pct. 3.Display a zero for employees with a null commission value. Evaluate the SQL statement: SELECT LAST_NAME, SALARY*COMMISSION_PCT FROM EMPLOYEES WHERE COMMISSION_PCT IS NOT NULL; What does the statement provide?（）A、all of the desired resultsB、two of the desired resultsC、one of the desired resultsD、an error statement
考题
EMPLOYEES中职员编号为90的职员的commission_pct为空值，salary为1000，语句select12*salary*（commission_pct+0.2）comm from EMPLOYEES；comm显示的结果是（）。A、12000B、0C、2400D、NULL
考题
如果对关系emp（eno，ename，salary）成功执行下面的SQL语句： CREATE CLUSTER INDEX name_index ON emp（salary） 对此结果的正确描述是（）。A、在emp表上按salary升序创建了一个唯一索引B、在emp表上按salary降序创建了一个唯一索引C、在emp表上按salary升序创建了一个聚簇索引D、在emp表上按salary降序创建了一个聚簇索引
考题
The EMPLOYEE tables has these columns: LAST_NAME VARCHAR2(35) SALARY NUMBER(8,2) COMMISSION_PCT NUMBER(5,2) You want to display the name and annual salary multiplied by the commission_pct for all employees. For records that have a NULL commission_pct, a zero must be displayed against the calculated column. Which SQL statement displays the desired results?（）A、SELECT last_name, (salary * 12) * commission_pct FROM EMPLOYEES;B、SELECT last_name, (salary * 12) * IFNULL(commission_pct, 0) FROM EMPLOYEES;C、SELECT last_name, (salary * 12) * NVL2(commission_pct, 0) FROM EMPLOYEES;D、SELECT last_name, (salary * 12) * NVL(commission_pct, 0) FROM EMPLOYEES;
考题
Evaluate this SQL statement: SELECT ename, sal, 12* sal+100 FROM emp; The SAL column stores the monthly salary of the employee. Which change must be made to the above syntax to calculate the annual compensation as "monthly salary plus a monthly bonus of $100, multiplied by 12"? （）A、No change is required to achieve the desired results.B、SELECT ename, sal, 12* (sal+100) FROM emp;C、SELECT ename, sal, (12* sal)+100 FROM emp;D、SELECT ename, sal +100,*12 FROM emp;
考题
Management has asked you to calculate the value 12*salary* commission_pct for all the employees in the EMP table. The EMP table contains these columns: LAST NAME VARCNAR2(35) NOT NULL SALARY NUMBER(9,2) NOT NULL COMMISION_PCT NUMBER(4,2) Which statement ensures that a value is displayed in the calculated columns for all employees?（）A、SELECT last_name, 12*salary* commission_pct FROM emp;B、SELECT last_name, 12*salary* (commission_pct,0) FROM emp;C、SELECT last_name, 12*salary*(nvl(commission_pct,0)) FROM emp;D、SELECT last_name, 12*salary*(decode(commission_pct,0)) FROM emp;
考题
The EMPLOYEES table contains these columns: LAST_NAME VARCHAR2 (25) SALARY NUMBER (6,2) COMMISSION_PCT NUMBER (6) You need to write a query that will produce these results: 1. Display the salary multiplied by the commission_pct. 2. Exclude employees with a zero commission_pct. 3. Display a zero for employees with a null commission value. Evaluate the SQL statement: SELECT LAST_NAME, SALARY*COMMISSION_PCT FROM EMPLOYEES WHERE COMMISSION_PCT IS NOT NULL; What does the statement provide? （）A、All of the desired resultsB、Two of the desired resultsC、One of the desired resultsD、An error statement
考题
You need to display the last names of those employees who have the letter "A" as the second character in their names. Which SQL statement displays the required results? （）A、SELECT last_name FROM EMP WHERE last_ name LIKE '_A%';B、SELECT last_name FROM EMP WHERE last name ='*A%'C、SELECT last_name FROM EMP WHERE last name ='_A%';D、SELECT last_name FROM EMP WHERE last name LIKE '*A%'
考题
You need to display the last names of those employees who have the letter “A” as the second character in their names.Which SQL statement displays the required results?（）A、SELECT last_name FROM EMP WHERE last_name LIKE ‘_A%’;B、SELECT last_name FROM EMP WHERE last name =’*A%’C、SELECT last_name FROM EMP WHERE last name =’_A%’;D、SELECT last_name FROM EMP WHERE last name LIKE ‘*A%’
考题
Examine the data in the EMPLOYEES table: LAST_NAME DEPARTMENT_ID SALARY Getz 10 3000 Davis 20 1500 Bill 20 2200 Davis 30 5000 ... Which three subqueries work? （）A、SELECT * FROM employees where salary (SELECT MIN(salary) FROM employees GROUP BY department _ id);B、SELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department _ id);C、SELECT distinct department_id FROM employees Where salary ANY (SELECT AVG(salary) FROM employees GROUP BY department _ id);D、SELECT department_id FROM employees WHERE SALARY ALL (SELECT AVG(salary) FROM employees GROUP BY department _ id);E、SELECT last_name FROM employees Where salary ANY (SELECT MAX(salary) FROM employees GROUP BY department _ id);F、SELECT department_id FROM employees WHERE salary ALL (SELECT AVG(salary) FROM employees GROUP BY ANG (SALARY));
考题
The EMP table contains these columns: LAST_NAME VARCHAR2 (25) SALARY NUMBER (6,2) DEPARTMENT_ID NUMBER (6) You need to display the employees who have not been assigned to any department. You write the SELECT statement: SELECT LAST_NAME, SALARY, DEPARTMENT_ID FROM EMP WHERE DEPARTMENT_ID = NULL; What is true about this SQL statement ?（）A、The SQL statement displays the desired results.B、The column in the WHERE clause should be changed to display the desired results.C、The operator in the WHERE clause should be changed to display the desired results.D、The WHERE clause should be changed to use an outer join to display the desired results.
考题
Examine the structure of the EMPLOYEES, DEPARTMENTS, and LOCATIONS tables. EMPLOYEES NOT NULL, EMPLOYEE_ID NUMBER Primary Key VARCHAR2 EMP_NAME (30) VARCHAR2 JOB_ID (20) SALARY NUMBER References MGR_ID NUMBER EMPLOYEE_ID column DEPARTMENT_ID NUMBER Foreign key to DEPARTMENT_ID column of the DEPARTMENTS table DEPARTMENTS NOT NULL, Primary DEPARTMENT_ID NUMBER Key VARCHAR2 DEPARTMENT_NAME (30) References NGR_ID MGR_ID NUMBER column of the EMPLOYEES table Foreign key to LOCATION_ID NUMBER LOCATION_ID column of the LOCATIONS table LOCATIONS NOT NULL, Primary LOCATION_ID NUMBER Key VARCHAR2 CITY |30) Which two SQL statements produce the name, department name, and the city of all the employees who earn more then 10000?（）A、SELECT emp_name, department_name, city FROM employees e JOIN departments d USING (department_id) JOIN locations 1 USING (location_id) WHERE salary 10000;B、SELECT emp_name, department_name, city FROM employees e, departments d, locations 1 JOIN ON (e.department_id = d.department id) AND (d.location_id =1.location_id) AND salary 10000;C、SELECT emp_name, department_name, city FROM employees e, departments d, locations 1 WHERE salary 10000;D、SELECT emp_name, department_name, city FROM employees e, departments d, locations 1 WHERE e.department_id = d.department_id AND d.location_id = 1.location_id AND salary 10000;E、SELECT emp_name, department_name, city FROM employees e NATURAL JOIN departments, locations WHERE salary 10000;
考题
客户需要计算EMP表中所有职工12*salary* commission_pct的值.EMP表结构如下：LAST NAME VARCNAR2（35）NOT NULL SALARY NUMBER（9，2）NOT NULL COMMISION_PCTNUMBER（4，2）哪个语句可以查询计算EMP表中所有职工行？（）A、SELECT last_name，12*salary* commission_pct FROM empB、SELECT last_name，12*salary*（commission_pct，0）FROM empC、SELECT last_name，12*salary*（nvl（commission_pct，0））FROM emp如果oracle第一个参数为空那么显示第二个参数的值，如果第一个参数的值不为空，则显示第一个参数本来的值D、SELECT last_name，12*salary*（decode（commission_pct，0））FROM emp
考题
单选题Management has asked you to calculate the value 12*salary* commission_pct for all the employees in the EMP table. The EMP table contains these columns: LAST NAME VARCNAR2(35) NOT NULL SALARY NUMBER(9,2) NOT NULL COMMISION_PCT NUMBER(4,2) Which statement ensures that a value is displayed in the calculated columns for all employees?（）A
SELECT last_name, 12*salary* commission_pct FROM emp;B
SELECT last_name, 12*salary* (commission_pct,0) FROM emp;C
SELECT last_name, 12*salary*(nvl(commission_pct,0)) FROM emp;D
SELECT last_name, 12*salary*(decode(commission_pct,0)) FROM emp;
考题
单选题The EMPLOYEE tables has these columns: LAST_NAME VARCHAR2(35) SALARY NUMBER(8,2) COMMISSION_PCT NUMBER(5,2) You want to display the name and annual salary multiplied by the commission_pct for all employees. For records that have a NULL commission_pct, a zero must be displayed against the calculated column. Which SQL statement displays the desired results?（）A
SELECT last_name, (salary * 12) * commission_pct FROM EMPLOYEES;B
SELECT last_name, (salary * 12) * IFNULL(commission_pct, 0) FROM EMPLOYEES;C
SELECT last_name, (salary * 12) * NVL2(commission_pct, 0) FROM EMPLOYEES;D
SELECT last_name, (salary * 12) * NVL(commission_pct, 0) FROM EMPLOYEES;
考题
单选题如果对关系emp（eno，ename，salary）成功执行下面的SQL语句： CREATE CLUSTER INDEX name_index ON emp（salary） 对此结果的正确描述是（）。A
在emp表上按salary升序创建了一个唯一索引B
在emp表上按salary降序创建了一个唯一索引C
在emp表上按salary升序创建了一个聚簇索引D
在emp表上按salary降序创建了一个聚簇索引
考题
单选题The EMP table contains these columns: LAST NAME VARCHAR2(25) SALARY NUMBER(6,2) DEPARTMENT_ID NUMBER(6) You need to display the employees who have not been assigned to any department. You write the SELECT statement: SELECT LAST_NAME, SALARY, DEPARTMENT_ID FROM EMP WHERE DEPARMENT_ID = NULL; What is true about this SQL statement? （）A
The SQL statement displays the desired results.B
The column in the WHERE clause should be changed to display the desired results.C
The operator in the WHERE clause should be changed to display the desired results.D
The WHERE clause should be changed to use an outer join to display the desired results.
考题
单选题The EMPLOYEES table contains these columns: LAST_NAME VARCHAR2 (25) SALARY NUMBER (6,2) COMMISSION_PCT NUMBER (6) You need to write a query that will produce these results: 1. Display the salary multiplied by the commission_pct. 2. Exclude employees with a zero commission_pct. 3. Display a zero for employees with a null commission value. Evaluate the SQL statement: SELECT LAST_NAME, SALARY*COMMISSION_PCT FROM EMPLOYEES WHERE COMMISSION_PCT IS NOT NULL; What does the statement provide?（）A
All of the desired resultsB
Two of the desired resultsC
One of the desired resultsD
An error statement
考题
单选题The EMP table contains these columns: LAST_NAME VARCHAR2 (25) SALARY NUMBER (6,2) DEPARTMENT_ID NUMBER (6) You need to display the employees who have not been assigned to any department. You write the SELECT statement: SELECT LAST_NAME, SALARY, DEPARTMENT_ID FROM EMP WHERE DEPARTMENT_ID = NULL; What is true about this SQL statement ?（）A
The SQL statement displays the desired results.B
The column in the WHERE clause should be changed to display the desired results.C
The operator in the WHERE clause should be changed to display the desired results.D
The WHERE clause should be changed to use an outer join to display the desired results.
考题
单选题The EMPLOYEES table contains these columns: LAST_NAME VARCHAR2 (25) SALARY NUMBER (6,2) COMMISSION_PCT NUMBER (6) You need to write a query that will produce these results: 1. Display the salary multiplied by the commission_pct. 2. Exclude employees with a zero commission_pct. 3. Display a zero for employees with a null commission value. Evaluate the SQL statement: SELECT LAST_NAME, SALARY*COMMISSION_PCT FROM EMPLOYEES WHERE COMMISSION_PCT IS NOT NULL; What does the statement provide? （）A
All of the desired resultsB
Two of the desired resultsC
One of the desired resultsD
An error statement
考题
单选题The EMPLOYEES table contains these columns: LAST_NAME VARCHAR2 (25) SALARY NUMBER (6,2) COMMISSION_PCT NUMBER (6) You need to write a query that will produce these results: 1. Display the salary multiplied by the commission_pct. 2. Exclude employees with a zero commission_pct. 3. Display a zero for employees with a null commission value. Evaluate the SQL statement: SELECT LAST_NAME, SALARY*COMMISSION_PCT FROM EMPLOYEES WHERE COMMISSION_PCT IS NOT NULL; What does the statement provide? （）A
All of the desired resultsB
Two of the desired resultsC
One of the desired resultsD
An error statement
考题
单选题Management has asked you to calculate the value 12*salary* commission_pct for all the employees in the EMP table. The EMP table contains these columns: LAST NAME VARCNAR2(35) NOT NULL SALARY NUMBER(9,2) NOT NULL COMMISION_PCT NUMBER(4,2) Which statement ensures that a value is displayed in the calculated columns for all employees? （）A
SELECT last_name, 12*salary* commission_pct FROM emp;B
SELECT last_name, 12*salary* (commission_pct,0) FROM emp;C
SELECT last_name, 12*salary*(nvl(commission_pct,0)) FROM emp;D
SELECT last_name, 12*salary*(decode(commission_pct,0)) FROM emp;
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