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Animal is a super-ordinate term, while cow, horse, pig, dog, cat, etc. are().

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更多 “填空题Animal is a super-ordinate term, while cow, horse, pig, dog, cat, etc. are().” 相关考题
考题 在Java中,类Animal中的方法printA()定义如下:publicvoidprintA(){inta=10;intresult=10%3;System.out.println(result);}在类Dog中方法printA()定义如下:publicvoidprintA(){inta=10;System.out.println(a/3);}Dog类的定义如下:classDogextendsAnimal{…}.Animalanimal=newDog();animal.printA();以上语句输出为()。A.0B.1C.2D.3E.3.3333

考题 B"Well ,we're in our new house. Let's get a new pet to go along with it.Mrs Brown said to her husband."That sounds like a pretty good idea ,"he answered. "Do you want to see the ads in the newspaper?"" Let-s go to the animal shelter. Many pets there need homes. Since tomorrow is Saturday, we can both go ,"she said.The next morning the Browns met MrS now at the animal shelter. "We want to be sure that the pets here go to good homes ,"Mr Snow said ,"so I need to ask you some questions. " After they talked for a while ,the Browns decided to get a small dog. It wouldn't need-a bighouse or a big yard; A small dog would bark(吠) and warn them if someone tried to break into their house. After Mr Snow gave the Browns a book on pet care ,they chose one and wanted to take her home right away. But the animal doctor hadn't checked her yet. So Mrs now told them to return on Sunday.On Sunday afternoon the Browns went to the animal shelter. The animal doctor said, "Shadow has had all of her shots(预防针). She will be healthy. "The Browns thanked the doc- tor and took Shadow home.( )26. From the reading we learn that_________ .A. the Browns have never had a pet beforeB. the Browns knew about Shadow from the newspaperC. Shadow is a small and healthy dogD. Mr Brown didn-t quite agree with his wife

考题 有如下程序: include using namespaee std;class Animal{ public: virtual char*g 有如下程序:include<iostream>using namespaee std;c lass Animal{public:virtual char*getType( )const{return"Animal";}virtual char*getVoice( )const{return"Voice";}};class Dog:public Animal{public:char*getType( )const{return"Dog";}char*getVoice( )eonst{return"Woof";}};void type(AnimalA) {cout<<a.getType( );}void speak(Animal A) {eout<<a.getVoice( );}int main( ){Dog d;type(D) ;cout<<"speak";speak(D) ;cout return 0;}程序的输出结果是______。

考题 ( 12 )有如下程序:#include iostreamusing namespace stdclass Animal{public:virtual char* getType () const { return "Animal" ; }virtual char* getVoice () const { return "Voice" ; }};Class Dog : public Animal {public:char* getType ( ) const {return "Dog" ; }char* getVoice ( ) const {return "Woof"}};void type ( Animal a ) {couta.getType ( ) ; }void speak ( Animal a ) {couta.getVoice ( ) ; }int main ( ) {Dog d; type ( d ) ; cout" speak" ; speak ( d ) ; coutendi;return 0;}运行时的输出结果是【 12 】 。

考题 We can infer from the third paragraph that .[A] rich people are more interested in cloning humans than animals[B] cloning of animal pets is becoming a prosperous industry[C] there is no distinction between a cloned and a natural dog[D] Missy’s master pays a lot in a hope to revive the dog

考题 Hyponymy is a relation of inclusion. Tiger, lion and dog are hyponyms of the word animal.()

考题 若Animal是Cat,Dog的父类,则下列选项中,正确的是()。 A.Animalanimal=newCat()B.Catcat=(Cat)newDog()C.Catcat=(Cat)newAnimal()D.Animalanimal=newDog()

考题 dog是animal的子类,下面代码错误的是_________。 A.Objecto=newDog();B.Animala=newDog();C.Objectd=(Dog)newAnimal()D.Animala=(Animal)newDog();

考题 设有以下说明和定义:typedef union {long i; int k[5]; char c;} DATE;struct data { int cat; DATE cow; double dog;} too;DATE max;则语句 printf("%d",sizeof(struct date)+sizeof(max));的执行结果是:___52____

考题 有如下程序:ncludeiostreamusing namespace std;class Animal{public:virtual char*getType()const{return“Animal”;}virtual char*getVoice()const{return“Voice”;}};class Dog:public Animal{public:char*getType()const{rgturn“Dog”;}char*getVoice()const{retum“Woof”;}};void type(AnimalA){couta.getType();}void speak(AnimalA){couta.getVoice();}int main(){Dog d.type(D);tout“speak”;speak(D);coutendl;return 0;}运行时的输出结果是【 】

考题 BGood evening, ladies and gentlemen, I’m Roy , and this is my show. This is a television show for all families, and I know you’ll enjoy it.Let’s start with a story. Once there was a proud pig on a farm . He thought he was the most important of all the animals on the farm. But it was not enough that he himself thought this: he had to be sure that other animals thought it, too. So he went up to a chicken and asked, “ Who is the most important animal on the farm?” The chicken answered, “ You are, Mr. Pig .” Then he asked a dog, and he got the same reply.Next, he asked a cow. When the cow seemed uncertained of the right answer, the pig looked angry, and showed his teeth, “ Oh, you are, of course, Mr. Pig.” said the cow. “ Of course, ” the pig said, “ there is no doubt about it. ”At last the pig asked a big horse the same question. The horse lifted one foot, rolled the pig over and placed his foot on the pig’s head. “ I think you know the answer now. ” said the horse.61. The Roy show is _________ .A. a family show on TV B. for kids only C. a sports show

考题 When the pig asked a dog, the dog ________ .A. said nothing B. said the pig was the most importantC. said the pig was as important as the horse

考题 The horse thought ________ was the most important on the farm.A. he himself B. the pig C. the cow

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考题 According to the passage we can see that Chinese people think of the pig as a ______animal.A. cleverB. richC. goodD. all the above

考题 50.—could you take care of our dog while we are away?—__________A. With pleasureB. It's my pleasureC. Never mindD. That's all right

考题 Animal is a super-ordinate term, while cow, horse, pig, dog, cat, etc. are().

考题 词的关系分类主要有:对比,如wet-dry(湿-干);相似,如blossom-flower(开花-花);从属,如animal-dog(动物-狗);并列,如apple-peach(苹果-桃)。

考题 在Java中, 类Animal中的方法printA()定义如下: publicvoidprintA(){ inta=10; intresult=10%3; System.out.println(result);} 在类Dog中方法printA()定义如下: publicvoidprintA(){ inta=10; System.out.println(a/3);} Dog类的定义如下: classDogextendsAnimal{…}.Animalanimal=newDog();animal.printA(); 以上语句输出为()。A、0B、1C、2D、3E、3.3333

考题 10. interface Jumper { public void jump(); }  ......  20. class Animal {}  ......  30. class Dog extends Animal { 31. Tail tail; 32. }  ......  40. class Beagle extends Dog implements Jumper {  41. public void jump() { }  42. }  .......  50. class Cat implements Jumper {  51. public void jump() { }  52. }  Which three are true?()A、 Cat is-a AnimalB、 Cat is-a JumperC、 Dog is-a AnimalD、 Dog is-a JumperE、 Cat has-a AnimalF、 Beagle has-a TailG、 Beagle has-a Jumper

考题 11. class Animal { public String noise() { return “peep”; } }  12. class Dog extends Animal {  13. public String noise() { return “bark”; }  14. }  15. class Cat extends Animal {  16. public String noise() { return “meow”; }  17. }  .....  30. Animal animal = new Dog();  31. Cat cat = (Cat)animal;  32. System.out.printIn(cat.noise());  What is the result?() A、 peepB、 barkC、 meowD、 Compilation fails.E、 An exception is thrown at runtime.

考题 多选题Given: 10. interface Jumper { public void jump(); } ...   20. class Animal {} ...   30. class Dog extends Animal {   31. Tail tail;   32. }   ...   40. class Beagle extends Dog implements Jumper{   41. public void jump() {}  42. }   ...   50. class Cat implements Jumper{   51. public void jump() {}   52. }. Which three are true?()ACat is-a JumperBCat is-a AnimalCDog is-a JumperDDog is-a AnimalEBeagle has-a JumperFCat has-a AnimalGBeagle has-a Tail

考题 单选题11. class Animal { public String noise() { return “peep”; } }  12. class Dog extends Animal {  13. public String noise() { return “bark”; }  14. }  15. class Cat extends Animal {  16. public String noise() { return “meow”; }  17. }  .....  30. Animal animal = new Dog();  31. Cat cat = (Cat)animal;  32. System.out.printIn(cat.noise());  What is the result?()A  peepB  barkC  meowD  Compilation fails.E  An exception is thrown at runtime.

考题 单选题在Java中,类Animal中的方法printA()定义如下:  public void printA() {    Int a=10;    Int result =10%3;    System.out.println(result); }  在类Dog中方法printA()定义如下:  public void printA() {   Int a=10;    System.out.println(a/3); }  Dog类的定义如下:  Class Dog extends Animal{…}.  Animal animal=new Dog();  animal.printA();  以上语句输出结果为()。A  0B  1C  2D 3E 3.3333

考题 多选题10. interface Jumper { public void jump(); }  ......  20. class Animal {}  ......  30. class Dog extends Animal { 31. Tail tail; 32. }  ......  40. class Beagle extends Dog implements Jumper {  41. public void jump() { }  42. }  .......  50. class Cat implements Jumper {  51. public void jump() { }  52. }  Which three are true?()ACat is-a AnimalBCat is-a JumperCDog is-a AnimalDDog is-a JumperECat has-a AnimalFBeagle has-a TailGBeagle has-a Jumper

考题 单选题1. class Animal { Animal getOne() { return new Animal(); } }  2. class Dog extends Animal {  3. // insert code here   4. }  5.  6. class AnimalTest {  7. public static void main(String [] args) {  8. Animal [] animal = { new Animal(), new Dog() } ;  9. for( Animal a : animal) {  10. Animal x = a.getOne();  11. }  12. }  13. }  和代码:  3a. Dog getOne() {  return new Dog();  }  3b. Animal getOne() {  return new Dog();  }  第 3 行中插入的哪项将编译且运行无异常?()A 3a行B 3b行C 3a行或3b行D 既非3a,也非3b

考题 单选题class Animal{ Animal getOne(){return new Animal();}}   class Dog extends Animal{   //insert code here   }   class AnimalTest{   public static void main(String[] args){   Animal[] animal={ new Animal(), new Dog()};   for(Animal a:animal){   Animal x= a.getOne();   }   }   }   和代码:   3a.Dog getOne() { return new Dog();}   3b.Animal getOne() { return new Dog();}   第3行中插入的哪项编译且运行无异常?A 3a行或3b行B 既非3a,也非3bC 3a行D 3b行