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I wonder how many years ago _______.
A.did you father retire
B.your father retired
C.has your father retired
D.your father has retired
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更多 “ I wonder how many years ago _______.A.did you father retireB.your father retiredC.has your father retiredD.your father has retired ” 相关考题
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“Father, I think my dream is pointing me down another path. ”is said by ().
A、PocahontasB、KarenC、SarahD、Natalie
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阅读下列函数说明和C函数，将应填入(n)处的字句写在对应栏内。[说明]Kruskal算法是一种构造图的最小生成树的方法。设G为一无向连通图，令T是由G的顶点构成的于图，Kmskal算法的基本思想是为T添加适当的边使之成为最小生成树：初始时，T中的点互相不连通；考察G的边集E中的每条边，若它的两个顶点在T中不连通，则将此边添加到T中，同时合并其两顶点所在的连通分量，如此下去，当添加了n-1条边时，T的连通分量个数为1，T便是G的一棵最小生成树。下面的函数void Kruskal(EdgeType edges[],int n)利用Kruskal算法，构造了有n个顶点的图 edges的最小生成树。其中数组father[]用于记录T中顶点的连通性质：其初值为father[i]=-1 (i=0,1,…,n-1)，表示各个顶点在不同的连通分量上；若有father[i]=j，j＞-1，则顶点i，j连通；函数int Find(int father[],int v)用于返回顶点v所在树形连通分支的根结点。[函数]define MAXEDGE 1000typedef struct{ int v1;int v2;}EdgeType;void Kruskal(EdgeType edges[],int n){ int father[MAXEDGE];int i,j,vf1,vt2;for(i=0;i＜n;i+ +) father[i]=-1;i=0;j=0;while(i＜MAXEDGE j＜(1)){ vf1=Find(father,edges[i].v1);vf2=Find(father,edges[i].v2);if((2)){(3)=vf1;(4);printf("%3d%3d\n",edges[i].v1,edges[i].v2);}(5);}}int Find(int father[],int v){ int t;t=v;while(father[t]＞=0) t=father[t];return(t);}
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Father __________ goes to the gym with us although he dislikes going there.A.hardly
B.seldom
C.sometimes
D.never
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Father和Son是两个java类，下列哪一选项正确的标识出Father是Son的父类：A．class Son implements FatherB．class Father implements SonC．class Father extends SonD．class Son extends Father
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Father和Son是两个java类，下列哪一选项正确的标识出Father是Son的父类？（)。A．class Son implements FatherB．class Father implements SonC．class Father extends SonD．class Son extends Father
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