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公司有一个客户的数据表，此表的建立语句如下：
CREATE TABLE Customers
(CustomerID int NOT NULL,
CustomerName varchar(50) NOT NULL,
ContactName varchar(30) NULL,
Phone varchar(20) NULL,
Country varchar(30) NOT NULL,
CONSTRAINT PK_Customers PRIMARY KEY(CustomerID)
)
大部分的国家或地区只包含2-3个客户，而一些国家包括多于20个客户。现在公司想对客户数量在10(含10)个以上的国家进行广告宣传，你使用( )语句将这些国家列出。
A SELECT Country FROM Customers
GROUP BY Country HAVING COUNT (Country)>=10
B SELECT TOP 10 Country FROM Customers
C SELECT TOP 10 Country FROM Customers
FROM (SELECT DISTINCT Country FROM Customers) AS X
GROUP BY Country HAVING COUNT(*)>= 10
D SET ROWCOUNT 10
SELECT Country, COUNT (*) as “NumCountries”
FROM Customers
GROUP BY Country ORDER BY NumCountries, Desc
参考答案
更多 “ 公司有一个客户的数据表，此表的建立语句如下：CREATE TABLE Customers(CustomerID int NOT NULL,CustomerName varchar(50) NOT NULL,ContactName varchar(30) NULL,Phone varchar(20) NULL,Country varchar(30) NOT NULL,CONSTRAINT PK_Customers PRIMARY KEY(CustomerID))大部分的国家或地区只包含2-3个客户，而一些国家包括多于20个客户。现在公司想对客户数量在10(含10)个以上的国家进行广告宣传，你使用( )语句将这些国家列出。A SELECT Country FROM CustomersGROUP BY Country HAVING COUNT (Country)>=10B SELECT TOP 10 Country FROM CustomersC SELECT TOP 10 Country FROM CustomersFROM (SELECT DISTINCT Country FROM Customers) AS XGROUP BY Country HAVING COUNT(*)>= 10D SET ROWCOUNT 10SELECT Country, COUNT (*) as “NumCountries”FROM CustomersGROUP BY Country ORDER BY NumCountries, Desc ” 相关考题
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Given the following requirements:Create a table to contain employee data, with a unique numeric identifier automatically assigned when a row is added, has an EDLEVEL column that permits only the values ‘C‘, ‘H‘ and ‘N‘, and permits inserts only when a corresponding value for the employee‘s department exists in the DEPARTMENT table.Which of the following CREATE statements will successfully create this table?（）A.CREATE TABLE emp ( empno SMALLINT NEXTVAL GENERATED ALWAYS AS IDENTITY, firstname VARCHAR(30) NOT NULL, lastname VARCHAR(30) NOT NULL, workdept CHAR(3) NOT NULL, edlevel CHAR(1), PRIMARY KEY emp_pk (empno), FOREIGN KEY emp_workdept_fk ON (workdept) REFERENCES department (deptno), CHECK edlevel_ck VALUES (edlevel IN (‘C‘,‘H‘,‘N‘)), );B.CREATE TABLE emp ( empno SMALLINT NOT NULL GENERATED BY DEFAULT AS IDENTITY, firstname VARCHAR(30) NOT NULL, lastname VARCHAR(30) NOT NULL, workdept CHAR(3), edlevel CHAR(1), CONSTRAINT emp_pk PRIMARY KEY (empno), CONSTRAINT emp_workdept_fk FOREIGN KEY (workdept) REFERENCES department (deptno), CONSTRAINT edlevel_ck CHECK edlevel VALUES (‘C‘,‘H‘,‘N‘) );C.CREATE TABLE emp ( empno SMALLINT NEXTVAL GENERATED BY DEFAULT AS IDENTITY, firstname VARCHAR(30) NOT NULL, lastname VARCHAR(30) NOT NULL, workdept CHAR(3) NOT NULL, edlevel CHAR(1) CHECK IN (‘C‘,‘H‘,‘N‘)), CONSTRAINT emp_pk PRIMARY KEY (empno), CONSTRAINT emp_workdept_fk FOREIGN KEY department (deptno) REFERENCES (workdept) );D.CREATE TABLE emp ( empno SMALLINT NOT NULL GENERATED BY DEFAULT AS IDENTITY, firstname VARCHAR(30) NOT NULL, lastname VARCHAR(30) NOT NULL, workdept CHAR(3), edlevel CHAR(1), CONSTRAINT emp_pk PRIMARY KEY (empno), CONSTRAINT emp_workdept_fk FOREIGN KEY (workdept) REFERENCES department (deptno), CONSTRAINT edlevel_ck CHECK (edlevel IN (‘C‘,‘H‘,‘N‘)) );
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Which SQL statement defines a FOREIGN KEY constraint on the DEPTNO column of the EMP table?（）A、CREATE TABLE EMP (empno NUMBER(4), ename VARCHAR2(35), deptno NUMBER(7,2) NOT NULL, CONSTRAINT emp_deptno_fk FOREIGN KEY deptno REFERENCES dept deptno);B、CREATE TABLE EMP (empno NUMBER(4), ename VARCHAR2(35), deptno NUMBER(7,2) CONSTRAINT emp_deptno_fk REFERENCES dept (deptno));C、CREATE TABLE EMP (empno NUMBER(4), ename VARCHAR2(35), deptno NUMBER(7,2) NOT NULL, CONSTRAINT emp_deptno_fk REFERENCES dept (deptno) FOREIGN KEY (deptno));D、CREATE TABLE EMP (empno NUMBER(4), ename VARCHAR2(35), deptno NUMBER(7,2) FOREIGN KEY CONSTRAINT emp_deptno_fk REFERENCES dept (deptno));
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Given the following requirements:Create a table named TESTTAB, which has an identity column named ACTIVITYNO. Define the identity column to generate the values for the column by default. Start the values at 10 and increment by 10. Make the identity column unique. Which of the following CREATE statements will successfully create this table?（）A、CREATE TABLE TESTTAB (ACTIVITYNO SMALLINT NOT NULL GENERATED ALWAYS AS IDENTITY (START WITH 10 INCREMENT BY 10), ACTKWD CHAR(6) NOT NULL, ACTDESC VARCHAR(20) NOT NULL, UNIQUE(ACTIVITYNO))B、CREATE TABLE TESTTAB (ACTIVITYNO SMALLINT NOT NULL GENERATED ALWAYS AS IDENTITY (START WITH 1 INCREMENT BY 10), ACTKWD CHAR(6) NOT NULL, ACTDESC VARCHAR(20) NOT NULL, UNIQUE(ACTNO))C、CREATE TABLE TESTTAB (ACTIVITYNO SMALLINT NOT NULL GENERATED BY DEFAULT AS IDENTITY (START WITH 10 INCREMENT BY 1), ACTKWD CHAR(6) NOT NULL, ACTDESC VARCHAR(20) NOT NULL, UNIQUE(ACTIVITYNO))D、CREATE TABLE TESTTAB (ACTIVITYNO SMALLINT NOT NULL GENERATED BY DEFAULT AS IDENTITY (START WITH 10 INCREMENT BY 10), ACTKWD CHAR(6) NOT NULL, ACTDESC VARCHAR(20) NOT NULL, UNIQUE(ACTIVITYNO))
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单选题FACULTY表包含以下各列： FACULTYID VARCHAR2(5) NOT NULL PRIMARY KEY FIRST_NAME VARCHAR2(20) LAST_NAME VARCHAR2(20) ADDRESS VARCHAR2(35) CITY VARCHAR2(15) STATE VARCHAR2(2) ZIP NUMBER(9) TELEPHONE NUMBER(10) STATUS VARCHAR2(2) NOT NULL COURSE 表包含以下各列： COURSEID VARCHAR2(5) NOT NULL PRIMARY KEY SUBJECT VARCHAR2(5) TERM VARCHAR2(6 FACULTYID VARCHAR2(5) NOT NULL FOREIGN KEY 您需要制定一个报表，用于确定在下学期任教的所有副教授。您要创建一个视图来简化报表的创建过程。以下哪条CREATE VIEW语句将完成此任务（）A
CREATE VIEW（SELECT first_name，last_name，status，courseid，subject，term FROM faculty，course WHERE facultyid=facultyid）B
CREATE VIEW pt_view ON（SELEC Tfirst_name，last_name，status，courseid，subject，term FROM faculty f and coursec WHERE f.facultyid=c.facultyid）C
CREATE VIEW pt_view IN（SELECT first_name，last_name，status，courseid，subject，term FROM faculty course）D
CREATE VIEW pt_view AS（SELECT first_name，last_name，status，courseid，subject，term FROM facultyf，coursec WHERE f.facultyid=c.facultyid）
考题
问答题已知数据表Student存储在SQL Server服务器的School数据库中，用户名为sa，密码为xyz123，创建student数据表的命令为： CREATE TABLE Student （ SName varchar（20） Primary Key Not NULL， SPwd Varchar（15） Not NULL ） 试根据下面的代码使用命令对象完成在student数据表中插入一条记录。
考题
单选题评估此CREATE TABLE语句的执行结果： CREATE TABLE part( part_id NUMBER, part_name VARCHAR2(25), manufacturer_id NUMBER(9), retail_price NUMBER(7,2) NOT NULL, CONSTRAINT part_id_pk PRIMARY KEY(part_id), CONSTRAINT cost_nn NOT NULL(cost), CONSTRAINT FOREIGN KEY (manufacturer_id) REFERENCES manufacturer(id)); 哪一行会导致产生错误（）A
6B
7C
8D
9
考题
单选题You need to produce a report for mailing labels for all customers. The mailing label must have only the customer name and address. The CUSTOMERS table has these columns: CUST_ID NUMBER(4) NOT NULL CUST_NAME VARCHAR2(100) NOT NULL CUST_ADDRESS VARCHAR2(150) CUST_PHONE VARCHAR2(20) Which SELECT statement accomplishes this task?（）A
SELECT* FROM customers;B
SELECT name, address FROM customers;C
SELECT id, name, address, phone FROM customers;D
SELECT cust_name, cust_address FROM customers;E
SELECT cust_id, cust_name, cust_address, cust_phone FROM customers;
考题
填空题使用连接对象的Execute方法可以执行各种SQL语句，以完成创建数据库、创建表、添加新记录、修改记录及删除记录等任务。试完成填空题。
创建一个名为 student的表，包含：sid（int，标识列，标识种子和增量为1，主键）、sname（varchar（10） Not NULL），pwd varchar（15） NOT NULL，sAge（int，Default 0）， 则语句为： conn.Execute（）
考题
单选题Which SQL statement defines a FOREIGN KEY constraint on the DEPTNO column of the EMP table?（）A
CREATE TABLE EMP (empno NUMBER(4), ename VARCHAR2(35), deptno NUMBER(7,2) NOT NULL, CONSTRAINT emp_deptno_fk FOREIGN KEY deptno REFERENCES dept deptno);B
CREATE TABLE EMP (empno NUMBER(4), ename VARCHAR2(35), deptno NUMBER(7,2) CONSTRAINT emp_deptno_fk REFERENCES dept (deptno));C
CREATE TABLE EMP (empno NUMBER(4), ename VARCHAR2(35), deptno NUMBER(7,2) NOT NULL, CONSTRAINT emp_deptno_fk REFERENCES dept (deptno) FOREIGN KEY (deptno));D
CREATE TABLE EMP (empno NUMBER(4), ename VARCHAR2(35), deptno NUMBER(7,2) FOREIGN KEY CONSTRAINT emp_deptno_fk REFERENCES dept (deptno));
考题
单选题Given the following requirements: Create a table to contain employee data, with a unique numeric identifier automatically assigned when a row is added, has an EDLEVEL column that permits only the values 'C', 'H' and 'N', and permits inserts only when a corresponding value for the employee's department exists in the DEPARTMENT table. Which of the following CREATE statements will successfully create this table?（）A
CREATE TABLE emp ( empno SMALLINT NEXTVAL GENERATED ALWAYS AS IDENTITY, firstname VARCHAR(30) NOT NULL, lastname VARCHAR(30) NOT NULL, workdept CHAR(3) NOT NULL, edlevel CHAR(1), PRIMARY KEY emp_pk (empno), FOREIGN KEY emp_workdept_fk ON (workdept) REFERENCES department (deptno), CHECK edlevel_ck VALUES (edlevel IN ('C','H','N')), );B
CREATE TABLE emp ( empno SMALLINT NOT NULL GENERATED BY DEFAULT AS IDENTITY, firstname VARCHAR(30) NOT NULL, lastname VARCHAR(30) NOT NULL, workdept CHAR(3), edlevel CHAR(1), CONSTRAINT emp_pk PRIMARY KEY (empno), CONSTRAINT emp_workdept_fk FOREIGN KEY (workdept) REFERENCES department (deptno), CONSTRAINT edlevel_ck CHECK edlevel VALUES ('C','H','N') );C
CREATE TABLE emp ( empno SMALLINT NEXTVAL GENERATED BY DEFAULT AS IDENTITY, firstname VARCHAR(30) NOT NULL, lastname VARCHAR(30) NOT NULL, workdept CHAR(3) NOT NULL, edlevel CHAR(1) CHECK IN ('C','H','N')), CONSTRAINT emp_pk PRIMARY KEY (empno), CONSTRAINT emp_workdept_fk FOREIGN KEY department (deptno) REFERENCES (workdept) );D
CREATE TABLE emp ( empno SMALLINT NOT NULL GENERATED BY DEFAULT AS IDENTITY, firstname VARCHAR(30) NOT NULL, lastname VARCHAR(30) NOT NULL, workdept CHAR(3), edlevel CHAR(1), CONSTRAINT emp_pk PRIMARY KEY (empno), CONSTRAINT emp_workdept_fk FOREIGN KEY (workdept) REFERENCES department (deptno), CONSTRAINT edlevel_ck CHECK (edlevel IN ('C','H','N')) );
考题
单选题The CUSTOMERS table has these columns: CUSTOMER_ID NUMBER(4) NOT NULL CUSTOMER_NAME VARCHAR2(100) NOT NULL STREET_ADDRESS VARCHAR2(150) CITY_ADDRESS VARCHAR2(50) STATE_ADDRESS VARCHAR2(50) PROVINCE_ADDRESS VARCHAR2(50) COUNTRY_ADDRESS VARCHAR2(50) POSTAL_CODE VARCHAR2(12) CUSTOMER_PHONE VARCHAR2(20) A promotional sale is being advertised to the customers in France. Which WHERE clause identifies customers that are located in France?（）A
WHERE lower(country_address) = franceB
WHERE lower(country_address) = 'france'C
WHERE lower(country_address) IS 'france'D
WHERE lower(country_address) = '%france%'E
WHERE lower(country_address) LIKE %france%
考题
单选题You executed the following code： SQL CREATE TABLE COUNTRY （COUNTRY_ID CHAR（2） CONSTRAINT COUNTRY_ID_nn NOT NULL， COUNTRY_NAME VARCHAR2（20）， CURRENCY_NAME VARCHAR2（20）， CONSTRAINT COUNTRY_ID_PK PRIMARY KEY （COUNTRY_ID）） ORGANIZATION INDEX； In which tablespace will the mapping table be created？（）A
SYSTEM tablespaceB
SYSAUX tablespaceC
Undo tablespaceD
The tablespace of the Index Organized Table （IOT）
考题
单选题Given the following requirements:Create a table named TESTTAB, which has an identity column named ACTIVITYNO. Define the identity column to generate the values for the column by default. Start the values at 10 and increment by 10. Make the identity column unique. Which of the following CREATE statements will successfully create this table?（）A
CREATE TABLE TESTTAB (ACTIVITYNO SMALLINT NOT NULL GENERATED ALWAYS AS IDENTITY (START WITH 10 INCREMENT BY 10), ACTKWD CHAR(6) NOT NULL, ACTDESC VARCHAR(20) NOT NULL, UNIQUE(ACTIVITYNO))B
CREATE TABLE TESTTAB (ACTIVITYNO SMALLINT NOT NULL GENERATED ALWAYS AS IDENTITY (START WITH 1 INCREMENT BY 10), ACTKWD CHAR(6) NOT NULL, ACTDESC VARCHAR(20) NOT NULL, UNIQUE(ACTNO))C
CREATE TABLE TESTTAB (ACTIVITYNO SMALLINT NOT NULL GENERATED BY DEFAULT AS IDENTITY (START WITH 10 INCREMENT BY 1), ACTKWD CHAR(6) NOT NULL, ACTDESC VARCHAR(20) NOT NULL, UNIQUE(ACTIVITYNO))D
CREATE TABLE TESTTAB (ACTIVITYNO SMALLINT NOT NULL GENERATED BY DEFAULT AS IDENTITY (START WITH 10 INCREMENT BY 10), ACTKWD CHAR(6) NOT NULL, ACTDESC VARCHAR(20) NOT NULL, UNIQUE(ACTIVITYNO))
考题
单选题You executed the following code： SQL CERATE TABLE COUNTRY （COUNTRY_ID CHAR（2） CONSTRAINT COUNTRY_ID_nn NOT NULL， COUNTRY_NAME VARCHAR2（20）， CURRENCY_NAME VARCHAR2（20）， CONSTRAINT COUNTRY_ID_PK PRIMARY KEY （COUNTRY_ID）） ORGANIZATION INDEX； Which types of tables will be created automatically？（）A
journal tableB
clustered tableC
mapping tableD
partitioned table
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