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Let us ___ to the next item on the agenda.
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●试题六阅读下列程序说明和C++代码，将应填入(n)处的字句写在答卷的对应栏内。【程序6说明】本程序实现两个多项式的乘积运算。多项式的每一项由类Item描述，而多项式由类List描述。类List的成员函数有：createList()：创建按指数降序链接的多项式链表，以表示多项式。reverseList()：将多项式链表的表元链接顺序颠倒。multiplyList(List L1，List L2)：计算多项式L1和多项式L2的乘积多项式。【程序6】#includeiostream.hclass List；class ltem{friend class List；private：double quot；int exp；Item*next；public：Item(double_quot，int_exp){ (1) ；}}；class List{private:Item*list；public：List(){list=NULL；}void reverseList()；void multiplyList(List L1，List L2)；void createList()；}；void List::createList(){Item*p，*u，*pre；int exp；double quot；list=NULL；while (1) {cout"输入多项式中的一项(系数、指数)："endl；cinquotexp：if(exp0)break；//指数小于零，结束输入if(quot==0)continue；p=list；while( (2) ){//查找插入点pre=p；p=p-next；}if(p!=NULLexp==p-exp){ p-quot+=quot；continue；}u= (3) ；if(p==list) list=u；else pre-next=u；u-next=p；}}void List::reverseList(){Item*p，*u；if(list＝＝NULL)return；p=list-next；list-next=NULL；while(p!=NULL){u=p-next；p-next=list；list=p；p=u；}}void List::multiplyList(List L1，List L2){Item*pLl，*pL2，*u；int k，maxExp；double quot；maxExp= (4) ；L2．reverseList()；list=NULL;for(k=maxExp；k=0；k--){pL1=L1．list；while(pL1!=NULLpL1-expk)pL1=pL1-next；pL2=L2．list；while(pL2!=NULL (5) pL2=pL2-next；quot=0．0；while(pL1!=NULLpL2!=NULL){if(pL1-exp+pL2-exp==k){(6) ；pL1=pL1-next；pL2=pL2-next；}else if(pL1-exp+pL2-expk)pL1=pL1-next；else pL2=pL2-next；}if(quot!=0．0){u=new Item(quot，k)；u-next=list；list=u；}}reverseList()；L2．reverseList()：}void main(){ListL1，L2，L；cout"创建第一个多项式链表＼n"；L1．createList()；cout"创建第二个多项式链表＼n"；L2．createList()；L．multiplyList(L1，L2)；}
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阅读以下应用说明、图和C++程序，将C++程序中(1)～(6)空缺处的语句填写完整。【说明】以下【C++程序】用于实现两个多项式的乘积运算。多项式的每一项由类Item描述，而多项式由类List描述。类List的成员函数主要有：createList()：创建按指数降序链接的多项式链表，以表示多项式：reverseList()：将多项式链表的表元链接顺序颠倒：multiplyList(ListL1，ListL2)计算多项式L1和多项式L2的乘积多项式。【C++程序】include ＜iostream.h＞class List;class Item {friend class List;private:double quot ;int exp ;Item *next;Public:Item(double_quot,int_exp){ (1) ;}};class List{private:Item *list;Public:List(){list=NULL:}void reverseList();void multiplyList(List L1,List L2);void createList();};void List::createList(){ Item *p,*U,*pre;int exp;double quot;list = NULL;while (1) {cout ＜＜ "输入多项式中的一项(系数、指数) :" ＜＜ endl;cin ＞＞ quot ＞＞ exp:if ( exp＜0 )break ; //指数小于零，结束输入if ( quot=0 )continue;p = list;while ( (2) ) { //查找插入点pre = p;p = p-＞next;}if ( p != NULL exp = p-＞exp ) {p-＞quot += quot;continue ;}u =(3);if (p == list)list = u;elsepre-＞next = u;u -＞next = p;}}void List::reverseList(){ Item *p, *u;if ( list==NULL )return;p = list -＞next;list -＞ next = NULL;while ( p != NULL) {u = p -＞ next;p -＞next = list;list = p;p = u;}}void List::multiplyList ( List L1, List L2 ){ Item *pL1,*pL2,*u;int k, maxExp;double quot;maxExp =(4):L2.reverseList();list=NULL;for ( k = maxExp;k ＞= 0;k-- ){pL1 = L1.list;while ( pL1 != NULL pL1 -＞ exp ＞ k )pL1 = pL1 -＞next;pL2 = L2.1ist;while (pL2 NULL (5))pL2 = pL2 -＞ next;quot = 0.0;while (pL1 != NULL pL2 != NULL){if(pL1-＞exp+pL2-＞exp==k) {(6)pL1 = pL1 -＞ next;pL2 = pL2 -＞ next;} else if ( pL1 -＞ exp + pL2 -＞ exp ＞ k )pL1 = pL1 -＞ next;elsepL2 = pL2 -＞ next;}if ( quot !=0.0 ) {u = new item( quot, k );u -＞ next = list;list = u;}}reverseList ();L2. reverseList ():}void main(){ List L1,L2,L;
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请完成下列Java程序：实现2个下拉式菜单，一个包含exit菜单项，另一个包含item1和item2共2个菜单项。要求选择exit菜单项时，退出程序；选择item1菜单项之后，item1项变为不可选而item2可选；选择item2菜单项时，item2变为不可选而item1可选。注意：请勿改动main()主方法和其他已有语句内容，仅在下划线处填入适当的语句。程序运行结果如下：import java.awt.*;import java.awt.event.*;public class ex18_2 extends Frame. implements ActionListener {private choiceHandler ch;private MenuItem item1;private MenuItem item2;public static void main(String[] arg) {new ex18_2 ( );}ex18_2 ( ) {setTitle("ex18_2");MenuItem item;ch = new choiceHandler();MenuBar mb = new MenuBar();Menu fm = new Menu("File");fm.addSeparator();fm.add(item = new MenuItem("Exit"));item.addActionListener(this);fm.add(item);mb.add(fm);Menu mm = new Menu("Choice");mm.add(item1 = new MenuItem("item1"));item1.addActionListener(ch);mm.add(item2 = new MenuItem("item2"));item2.addActionListener(ch);mb.add(mm);setMenuBar(mb);setSize(200,200);show();}public void actionPerformed(ActionEvent ae) {if(ae.getActionCommand().equals("Exit"))System.exit(0);elseSystem.out.println(ae.getActionCommand());}class choiceHandler implements ActionListener {public void actionPerformed(ActionEvent ae) {String strCommand = ae.getActionCommand();if(_________________) {item2.setEnabled(true);item1.setEnabled(false);} else if(______________________) {item2.setEnabled(false);item1.setEnabled(true);}}}}
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An application needs a table for each connection that tracks the ID and Name of all items previously ordered and committed within the connection. The table also needs to be cleaned up and automatically removed each time a connection is ended. Assuming the ITEMS table was created with the following SQL statement:CREATE TABLE items item_no INT, item_name CHAR(5), item_qty INT)Which of the following SQL statements will provide the table definition that meets the specified requirements?（）A.DECLARE GLOBAL TEMPORARY TABLE tracker AS (SELECT item_no, item_name FROM items) WITH NO DATA ON COMMIT PRESERVE ROWS ON DISCONNECT DROP TABLEB.DECLARE GLOBAL TEMPORARY TABLE tracker AS (SELECT item_no, item_name FROM items) WITH NO DATA ON COMMIT PRESERVE ROWSC.CREATE TABLE systmp.tracker AS (SELECT item_num, item_name FROM items) WITH NO DATA ON COMMIT PRESERVE ROWSD.CREATE TABLE tracker AS (SELECT item_num, item_name FROM items) ON COMMIT PRESERVE ROWS ON DISCONNECT DROP TABLE
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（）阅读下列说明和C语言程序，将应填入 （n）处的语句写在答题纸的对应栏内。[说明]设有定义 #define ITEM struct item #define SIZE sizeof(ITEM) ITEM { int num; ITEM *next; }; ITEM *head=NULL; 下述函数定义实现按插表尾形式（即每一新表元素插入至当前所生成链表的表尾之后）生成一个正向线性链表。最后指向所生成链表表头的指针作为函数值返回。为生成一个线性链表，要求输入一批整型数据，并以-1作为结束标志。请填空完善程序。 ITEM *gene(ITEM *head) { ITEM *temp,*tail;/*tail指向当前链表尾结点*/ int intno; printf("Enter integer NO.,-1 to stop:\n"); scanf("%d",intno); while (intno!=-1) { temp=(____(1)_____)malloc(SIZE); temp-num=intno; if (head==_____(2)_____) /*空表*/ { head=temp; tail=______(3)______; } else /*非空表*/ { ____(4)_______=temp; tail=temp; } scanf("%d",intno); } return (_______(5)_______);
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淘宝买东西时卖家发来一个链接,打开之后就是你要的商品页面,该链接不安全,请问最可能有什么风险?()(链接地址http:／／item.taobao.com.kq.us／auction／item_detail.asp?id=15421&c9438.jhtml)
A.跨站B.SQL注入C.远程溢出D.网络钓鱼
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8、通过下面的代码片段来回答问题。 struct ToDoList { var item:[String]？ var number:Int } 下列可以作为这个结构体的构造器的是？A.可以没有构造器###SXB###B.init (item:[String], number:Int) { self.item = item }###SXB###C.init (item:[String], number:Int) { self.number = number }###SXB###D.init (item:[String], number:Int) { self.item = item self.number = number }
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【单选题】以下程序的运行结果是（）。 int main（) { int sum = 0, item = 0; while（item ＜ 5) { item++; sum += item; if（sum＞=6) break; } printf（"%dn",sum); return 0; }A．10B．15C．6D．7
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