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单选题
How many different four-digit integers can be formed using the digits 3, 4, 5, 6, 7, 8, 9 if the tens digit is 5 and no digit is repeated within an integer?
A

16

B

45

C

63

D

120

E

840

参考答案

参考解析
解析：
首先需要想一下每个位置有几种选择，然后将这些选择相城可得出结果。因为十位数上数字已经确认定，所以只能有一种选择，又因为一个数中3, 4, 5, 6, 7, 8, 9不能重复，个位上有6中选择，那么百位上和千位上则分别有5种和4种选择，故总的可能为4×5×1×6=120种。
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