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I can ( ) be a teacher. I’m not a very patient person.
A. seldom B. ever C. never D. always
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B.P(F/P,i,m-l)=A(P/A,i,n-m)
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根据(A/F,i,n)=i÷[(1+i)^n-1],可以推断()成立。A.(A/F,i,n)*(1+i)^n=(A/P,i,n)
B.(A/F,i,n)*(1+i)^n=(P/A,i,n)
C.(A/F,i,n)xi=(A/P,i,n)
D.(A/F,i,n)-i=(P/A,i,n)
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根据(A/F,i,n)=,可以推断( )成立。A.(A/F,i,n)+i=(A/P,i,n)
B.(A/F,i,n)×i=(A/P,i,n)
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根据可以推断()成立。
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B. (A/F, i,n) Xi= (A/P, i,n)
C. (A/F, i,n) +i= (P/A, i,n)
D. (A/F, i,n) -i= (P/A, i,n)
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