设计一个 Rectangle 类数据成员包含height和width；成员函数包含：void set（double w, double h); // 设置边长 double getWidth（); // 取矩形宽 double getHeight（); // 取矩形高 double area（); // 计算矩形面积 double perimeter（); // 计算矩形周长

考题若程序中定义了以下函数：double myadd(double a,double b){ return(a+b);}并将其放在调用语句之后，则在调用之前应该对该函数进行说明，以下选项中错误的说明是（）。A．double myadd(double a, b)B．double myadd(double ,double )C．double myadd(double b,double a)D．double myadd(double x,double y)

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考题 ●试题六阅读以下说明和C＋＋程序，将应填入(n)处的语句写在答题纸的对应栏内。【说明】以下程序的功能是计算三角形、矩形和正方形的面积并输出。程序由4个类组成：类Triangle、Rectangle和Square分别表示三角形、矩形和正方形；抽象类Figure提供了一个纯虚拟函数getArea()，作为计算上述3种图形面积的通用接口【C＋＋程序】#includeiostream．h#includemath．hclass Figure{public：virtual double getArea()=0：∥纯虚拟函数}；class Rectangle： (1) {protected：double height；double width；public：Rectangle(){}；Rectangle(double height，double width){this-height=height；this-width=width；}double getArea(){return (2) ；}}；class Square： (3) {public：Square(double width){(4) ；}}；class Triangle： (5) {double la；double Ib；double lc；public：Triangle(double la，double lb，double lc){This-la=la；this-lb=lb；this-lc=lc；}double getArea(){double s=(la+lb+±c)／2．0；return sqrt(s*(s-1a)*(s-1b)*(s-1c))；}}；void main(){Figure*figures［3］={new Triangle(2，3，3)，new Rectangle(5，8)，new SqUare (5) )；for (int i=0；i3；i＋＋){cout"figures［"i"］area="(figures［i］)-getArea()endl；}}

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考题阅读以下说明和Java程序，将应填入(n)处的字句写在对应栏内[说明]以下程序的功能时三角形、矩形和正方形的面积输出。程序由5个类组成：areatest是主类，类Triangle，Rectangle和Square分别表示三角形、矩形和正方形，抽象类Figure提供了一个计算面积的抽象方法。[Java程序]public class areatest {public static viod main(string args[]){Figure[]Figures={New triangle(2,3,3),new rectangle(5,8),new square(5)};for(int i=0; i＜Figures.length;i++){system.out.println(Figures+"area="+Figures.getarea());}}}public abstract class figure {public abstract double getarea();}public class rectangle extends (1) {double height;double width;public rectangle (double height,double width){this.height=height;this.width=width;}public string tostring(){return"rectangle:height="+height+",width="+width+":";}public double getarea(){return (2)}}public class square exends (3){public square(double width){(4);}public string tostring(){return"square:width="+width":";}}public class triangle entends (5){double la;double lb;double lc;public triangle(double la,double lb,double lc){this.la=la;this.lb=lb;this.lc=lc;}public string tostring()(return"triangle:sides="+la+","+lb+","+lc+":";}public double get area(){double s=(la+lb+lc)/2.0;return math．sqrt(s*(s-la)*(s-lb)*(s-lc));}}

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考题阅读以下说明和Java源程序，将应填入(n)处的字句写在对应栏内。【说明】以下程序能够计算三角形、矩形和正方形的周长并输出。程序由5个类组成：AreaTest是主类，类Triangle、Rectangle和Square分别表示三角形、矩形和正方形，抽象类Figure提供了一个计算周长的抽象方法。【程序】public class girthTest{public static void main (String args[]){Figure[]figures={new Triangle (2，3，3)，new Rectangle(5，8)，new Square(5)}；for(int i=0；i＜figures．length；i++){System．out．println(figures[i]+"girth="+figures[i]．getGirth())；}}}public abstract class Figure{public abstract double getGirth()；}public class Rectangle extends (1) {double height；double width；public Rectangle(double height，double width){this．height=height；this．width=width；}public String toString(){return "Rectangle：height="+height+"，width="+width+"："；}public double getGirth(){return (2)；}}public class Square extends (3) {public Square(double width){(4)；}public Stdng toString(){return "Square：width='+width+"："；}}public class Triangle extends (5) {double la；double lb；double lc；public Triangle(double la，double lb，double lc){this．la=la；this.lb=lb；this．lc=lc；}public String toString(){return "Triangle：sides=" +la+"，" +lb+"，" +lc+"："；}public double getGirth(){return la+lab+lc；}}

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考题 ●试题五阅读下列程序说明和C++代码，将应填入(n)处的字句写在答卷的对应栏内。【说明】①在类体中添加函数move(double ax, double ay)的定义，使得点的坐标x和y分别移动ax和ay个单位。②在类定义外完成重载的两个构造函数CPosition()和CPosition(double dx, double dy)，其中前者为不带参数的构造函数，使CPosition对象的默认值为x=0，y=0，后者为带参数的构造函数，把数据成员x和y分别初始化为参数dx和dy的值。③完成函数double distance(double bx, double by)的定义，该函数返回*this和点(bx,by)的距离。注意：除在指定的位置添加语句外，请不要改动程序中的其他语句。源程序文件test5.cpp清单如下：#includeiostream.h#include math.hclass CPosition{public:CPosition();CPosition(double dx, double dy);double getx();double gety();(1)double distance(double bx, double by);private:double x;double y;};(2){x=0; y=0;}CPosition::CPosition(double dx, double dy){x=dx; y=dy;}double CPosition::getx(){return x;}double CPosition::gety(){return y;}double CPosition::distance(double bx, double by){(3)}void main(){double a,b;cout "Input x, y position of a point: ";cin a b;CPosition psA(a, b);cout "Input x, y position of another point: ";cin a b;cout "The distance is " psA．distance(a,b) endl;}

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考题若已经声明了函数原型“void fun(int a，double b=0.0);”，则下列重载函数声明中正确的是( )。A．void fun(int a=90，double b=0.0)；B．int fun(int a，double Ｂ)；C．void fun(double a，int Ｂ)；D．bool fun(int a，double b=0.0)；

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考题（ 13 ）补充完整下面的类定义：const double PI=3 .14;class Circle{ // 圆形物体的抽象基类protected:double r; // 半径public:Circle （ double radius=0 ）： r （ radius ） {}【 13 】； // 计算圆形物体表面积的纯虚函数声明};class Cylinder:public Circle { // 圆柱体类double h; // 高度public:Cylindr （ double radius=0, doubli height=0 ）：Circle （ radius ）， h （ height ） {}Virtual double Area （） { // 计算圆柱体的表面积return 2*PI*r* （ r+h ）；}};

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考题阅读下列程序说明和C++代码，将应填入(n)处。【说明】①在类体中添加函数move(double ax，double ay)的定义，使得点的坐标x和y分别移动 ax和ay个单位。②在类定义外完成重载的两个构造函数CPosition()和CPosition(double dx，double dy)，其中前者为不带参数的构造函数，使CPosition对象的默认值为x=0，y=0，后者为带参数的构造函数，把数据成员x和y分别初始化为参数dx和dy的值。③完成函数double distance(double bx，double by)的定义，该函数返回*this和点(bx， by)的距离。注意：除在指定的位置添加语句外，请不要改动程序中的其他语句。源程序文件test5.cpp清单如下：include＜iostream.h＞include＜math.h＞class CPosition{public：CPosition()；CPosition(double dx，double dy)；double getx()；double gety()；(1)double distance(double bx，double by)；private：double x；double y；}；(2){x=0；y=0；}CPosition：：CPosition(doub，e dx，doub，e dy){x=dx； y=dy；}double CPosition：：getx(){return x；}double CPosition：：gety(){return y；}double CPosition：：distance(double bx，double by){(3)}vold main(){double a，b；cout＜＜"|nput x，y position of a point："；cin ＞＞ a ＞＞ b；CPosition psA(a，b)；cout＜＜"Input x，y position of another point："；cin ＞＞a ＞＞ b；cout ＜＜"The distance is" ＜＜psA.distance(a，b) ＜＜end1；}

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考题阅读以下说明和C++代码，将应填入(n)处的字句写在对应栏内。【说明】以下C++程序的功能是计算三角形、矩形和正方形的面积并输出。程序由4个类组成：类 Triangle、Rectangle和Square分别表示三角形、矩形和正方形：抽象类Figure提供了一个纯虚函数getAxea()，作为计算上述3种图形面积的通用接口。【C++代码】include＜iostream＞include＜cmath＞using namespace std;class Figure{public:virtual double getArea()=0;//纯虚函数};class Rectangle ： (1) {protected:double height;double width;public:Rectangle(){}Rectangle(double height, double width){this-＞height=height;this-＞width=width;}double getArea(){return (2);}};class Square： (3) {public:Square(double width){(4);}};class Triangle： (5) {private:double la,lb,lc;public:Triangle(double la,double lb,double lc){this-＞la=la;this-＞1b=1b;this-＞lc=lc;}double getArea(){double s=(la+lb+lc)/2.0;return sqrt(s*(s-la)*(s-lb)*(s-lc));}int main(){Figure *figures[3]={new Triangle(2,3,3),new Rectangle(5,8), new Square(5)};for(int i=0;i＜3;i++){cout＜＜"figures["＜＜i＜＜"]area="＜＜(figures[i])-＞getArea()＜＜endl;}return 0;}

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考题阅读下列C++程序和程序说明，将应填入(n)处的字句写在对应栏内。【说明】Point是平面坐标系上的点类，Line是从Point派生出来的直线类。include ＜iostream.h＞class Point{public:Point (int x, int y) ;Point (Point p) ;～Point();void set (double x, double y) ;void print();private:double X,Y;};Point::Point (int x, int y) //Point 构造函数{X=x; Y=y; }Point::Point ( (1) ) //Point 拷贝构造函数{X=p.X; Y=p.Y；}void Point::set (double x, double y){X=x; Y=y; }void Point::print(){cout＜＜' ('＜＜X＜＜","＜＜Y＜＜") "＜＜endl; }Point::～Point(){cout＜＜"Point 的析构函数被调用! "＜＜endl;class Line: public Point{public:Line (int x, int y, int k) ;Line (Line s) ;～Line();void set (double x, double y, double k)void print();private:double K;};(2)//Line 构造函数实现{ K=k;}(3)//Line 拷贝构造函数实现{K=s.K;}void Line::set (double x, double y, double k){ (4);K=k;}void Line::print(){cout＜＜" 直线经过点";(5);cout＜＜"斜率为: k="＜＜K＜＜endl;}Line: :～Line(){cout＜＜"Line 析构函数被调用! "＜＜endl;}void main(){Line 11 (1,1,2) ;11 .print();Linel2 (11) ;12.set (3,2,1) ;12.print();}

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考题阅读以下说明及C++程序代码，将应填入(n)处的语句写在对应栏内。【说明】本程序的功能是根据矩形左上角和右下角顶点坐标生成一个矩形对象，然后输出该矩形4个顶点的坐标，计算并输出该矩形的面积。【C++代码】include＜iostream＞using namespace std;class MyPoint( //表示平面坐标系中的点的类double x;double y;public:MyPoint (double x,double y){this-＞x=x;this-＞y=y;}double getX()const{(1);}double getY()const{ return y;}void show()const{ cout＜＜'('＜＜x＜＜','＜＜y＜＜')';}};class MyRectangle{ //表示矩形的类MyPoint upleft; //矩形的左上角顶点MyPoint down right; //矩形的右下角顶点public:MyRectangle(MyPoint upleft,MyPoint downright);MyPoint getUpLeft()const{return up_left;} //返回左上角坐标MyPoint getDownRight()const{return down_right;} //返回右下角坐标MyPoint getUpRight()const; //返回右上角坐标MyPoint getDownLeft()const; //返回左下角坐标double area()const; //返回矩形的面积};MyRectangle:: MyRectangle((2)):up left(p1),down_right(p2){}MyPoint MyRectangle::getUpRight()const{return MyPoint(down_right.getX(),up_left.getY());}MyPoint MyRectangle::getDownLeft()const{return MyPeint((3));}double (4) ::area()const{return (getUpLeft(),getX()-getDownRight().getX())*(getDownRight().getY()-getUpLeft().getY());}int main( ){MyRectangle r(MyPoint(0,2),MyPoint(2,0));r.getUpLeft(),show();r.getUpRight().show();r.getDown Right().show();(5);cout＜＜r.area()＜＜end1;return 0;}

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考题阅读以下说明和C++程序，将应填入(n)处的语句写在的对应栏内。【说明】以下程序的功能是计算三角形、矩形和正方形的面积并输出。程序由4个类组成：类Triangle、Rectangle和Square分别表示三角形、矩形和正方形；抽象类Figure提供了一个纯虚拟函数getArea()，作为计算上述3种图形面积的通用接口。【C++程序】include＜iostream.h＞include＜math.h＞class Figure {public:virtual double getArea()=0; //纯虚拟函数};class Rectangle:(1){protected:double height;double width;public:Rectangle() {};Rectangle(double height,double width) {this-＞height=height;this-＞width=width;}double getArea() {return (2);}};class Square:(3){public:Square(double width){(4);}};class Triangle:(5){double la;double lb;double lc;Public:Triangle(double la, double lb, double lc) {This-＞la=la; this-＞lb=lb; this-＞lc=lc;}double getArea() {double s = (la+lb+±c)/2.0;return sqrt(s,(s-la)*(s-lb)*(s-Ic));}};void main() {Figure*figures[3]={new Triangle(2,3,3), new Rectangle(5,8), new SqUare(5));for(int i=0;i＜3;i++){cout＜＜"figures["＜＜i＜＜"]area="＜＜(figures[i])-＞getArea()＜＜endl;}}

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考题阅读下列C++程序和程序说明，将应填入(n)处的字句写在对应栏内。【说明】以下C++程序的功能是计算三角形、矩形和正方形的面积并输出。程序由4个类组成：类Triangle、Rectangle和Square分别表示三角形、矩形和正方形；抽象类Figure提供了一个纯虚拟函数getArea()，作为计算上述3种图形面积的通用接口。include＜iostream.b＞include＜math.h＞class Figure{public:virtual double getArea0=0; //纯虚拟函数};class Rectangle: (1) {protected:double height;double width;public:Rectangle(){};Rectangle(double height, double width){This-＞height=height;This-＞width=width;}double getarea(){return (2);}};class Square: (3) {public:Square(double width){(4);}};class Triangle: (5) {double la;double lb;double lc;public:Triangle(double la, double lb, double lc){this-＞la=la; this-＞lb; this-＞lc;}double getArea(){double s=(la+lb+lc)/2.0;return sqrt(s*(s-la)**(s-lb)*(s-lc));}};viod main(){Figure* figures[3]={new Triangle(2,3,3), new Rectangle(5,8), new Square(5));for(int i=0;i＜3;i++){cout＜＜"figures["＜＜i＜＜"]area="＜＜(figures[i])-＞getarea()＜＜endl;}}

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考题阅读以下函数说明和Java代码，将应填入(n)处的字句写在对应栏内。【说明】现要编写一个画矩形的程序，目前有两个画图程序：DP1和DP2，DP1用函数draw_a_line(x1，y1，x2，y2)画一条直线，DP2则用drawline(x1，x2，y1，y2)画一条直线。当实例画矩形时，确定使用DP1还是DP2。为了适应变化，包括“不同类型的形状”和“不同类型的画图程序”，将抽象部分与实现部分分离，使它们可以独立地变化。这里，“抽象部分”对应“形状”，“实现部分”对应“画图”，与一般的接口(抽象方法)与具体实现不同。这种应用称为Bridge(桥接)模式。图9-6显示了各个类间的关系。这样，系统始终只处理3个对象：Shape对象、Drawing对象、DP1或DP2对象。以下是 Java语言实现，能够正确编译通过。【Java代码】//DP1.java文件public class DP1{static public void draw_a line(double x1,double y1,double x2,double y2){//省略具体实现}}//DP2.java文件public class DP2{static public void drawline(double x1,double y1,double x2,double y2){//省略具体实现}}//Drawing.java文件(1) public class Drawing{abstract public void drawLine(double x1, double y1, double x2, double y2);}//V1Drawing.java文件public class V1Drawing extends Drawing{public void drawLine(double x1, double y1, double x2, double y2){DP1.draw_a_line(x1,y1,x2,y2);}}//V2Drawing.java文件public class V2Drawing extends Drawing{public void drawLine(double x1,double y1,double x2, double y2)(//画一条直线(2);}}//Shape.java文件abstract public class Shape{abstract public void draw();private (3) _dp;Shape(Drawing dp){_dp=dp;}protected void drawLine(double x1,double y1,double x2, double y2){(4);}}//Rectangle.java文件public class Rectangle extends Shape{private double_x1,_x2,_y1,_y2;public Rectangle(Drawing dp,double x1,double y1,double x2,double y2){(5);_x1=x1;_x2=x2;_y1=y1;_y2=y2;}public void draw(){//省略具体实现}}

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考题下列函数中对调用它的函数没有起到任何作用的是______ 。A．void fl(double x){--x；}B．double f2(double x){return x-1.5；}C．void f3(double x){--x；}D．double f4(double *x){--*x；return *x；}

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考题阅读以下说明和Java源程序，将应填入(n)处的字句写在答题纸的对应栏内。说明以下程序的功能是计算三角形、矩形和正方形的面积并输出。程序由5个类组成：AreaTest是主类，类Triangle、Rectangle和Square分别表示三角形、矩形和正方形，抽象类Figure提供了一个计算面积的抽象方法。程序public class AreaTest{public static void main(String args[]){Figure[]figures={new Triangle(2,3,3)，new Rectangle(5,8)， new Square(5)}；for(int i=0；i＜figures．1ength；i++){System.out.println(figures[i]+"area="+figures[i]．getArea())；}}}public abstract class Figure{public abstract double SetAJea()；public class Rectangle extends (1) {double height;double width;public Rectangle(double height,double width){this.height=height;this.width=width;}public String toString(){return "Rectangle:height="+height+",width="+width+":";}public double getArea() { return (2);} } public class Square extends (3) {public Square(double width) {(4);}public String toString() {return "Square:width="+width+":";} } public class Triangle extends (5). {double la;double lb;double lc;public Triangle(double la,double lb,double lc) {this.la=la; this.lb=lb; this.lc=lc;public String toString(){return "Triangle: sides="+la+","+lb+","+lc+":";public double getArea() {double s=(la+lb+lc)/2.0;return Math.sqrt(s*(s-la)*(s-lb)*(s?1c))；}}

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考题如下程序声明了一个二维图形类TwoDShape,从其派生出矩形类Rec。 include include 如下程序声明了一个二维图形类TwoDShape，从其派生出矩形类Rec。include＜iostream＞include＜string＞using namespaee std,class TwoDShape{// 二维图形类char name[20];public:TwoDShape (char * n="unknown") {strcpy(name, n);}Char * getName(){return name;}【】=0;};class Rec: public TwoDShape{double width, heightpublic:Rec(double w-=0. 0,double h=0. 0):TwoDShape("rectangle"){ width=w; height=h; }double getWidth() {return width;}double getHeight() {return height;}double area() {return width * height;}};int main() {TwoDShape * shape;Shape=new Rec(2.1,3.0);cout＜＜"object is"＜＜shape-＞getName()＜＜"\n";cout＜＜"Area is"＜＜shape-＞area()＜＜"\n";return 0}请将程序补充完整，使程序在运行时输出：abject is triangleArea is 6.3

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考题下列函数中，对调用它的函数没有起到任何作用的是( )。A．void f1(double x){--x;}B．double f2(double x){return x-1.5;}C．void f3(double x){--x;}D．double f4(double *x){--*x;return*x;}

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考题阅读以下说明和C++代码，[说明]现要编写一个画矩形的程序，目前有两个画图程序：DP1和DP2，DP1用函数draw_a_line(x1，y1，x2，y2)画一条直线，DP2则用drawline(x1，x2，y1，y2)画一条直线。当实例化矩形时，确定使用DP1还是DP2。为了适应变化，包括“不同类型的形状”和“不同类型的画图程序”，将抽象部分与实现部分分离，使它们可以独立地变化。这里，“抽象部分”对应“形状”，“实现部分”对应“画图”，与一般的接口(抽象方法)与具体实现不同。这种应用称为Bridge(桥接)模式。图6-1显示了各个类间的关系。[图6-1]这样，系统始终只处理3个对象：Shape对象、Drawingg对象、DP1或DP2对象。以下是C++语言实现，能够正确编译通过。[C++代码]class DP1{public：static void draw_a_line(double x1，double y1，double x2，double y2){//省略具体实现}}；class DP2{public：static void drawline(double x1，double x2，double y1，double y2){//省略具体实现}}；class Drawing{public：(1) void drawLine(double x1，double y1，double x2，double y2)=0;};class V1Drawing：public Drawing{public：void drawLine(double x1，double y1，double x2，double y2){DP1：：draw_a_line(x1，y1，x2，y2)；}}；class V2Drawing：public Drawing{public:void drawLine(double x1，double y1，double x2，double y2){(2)}}；class Shape{privatc：(3) dp;public：Shape(Drawing*dp)；virtual void draw()=0;void drawLine(double x1，double y1，double x2，double y2);};Shape：：Shape(Drawing*dp){_dp=dp;}void Shape：：drawLine(double x1，double y1，double x2，double y2){ //画一条直线(4)；}class Rectangle：public Shape{privatc：double_x1，_y1，_x2，_y2；public：Rectangle(Drawing *dp，double x1，double y1，double x2，double y2)；void draw()；}；Rectangle：：Rectangle(Drawing*dp，double x1，double y1，double x2，double y2)： (5){_x1=x1；_y1=yl;_x2=x2；_y2=y2；}void Rectangle：：draw(){//省略具体实现}(1)

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考题下列程序的执行结果为【】。include class Point{public:Point(double i, double j) 下列程序的执行结果为【】。include ＜iostream. h＞class Point{public:Point(double i, double j) { x=i; y=j;}double Area() const { return 0.0;}private:double x, y;};class Rectangle: public Point{public:Rectangle(double i, double j, double k, double 1)double Area() const {return w * h;}private:double w, h;};Rectangle: :Rectangle(double i, double j, double k. double 1): Point(i,j).{w=k, h=1}void fun(Point s){cout＜＜s. Area()＜＜end1;}void main( ){Rectangle rec(3.0, 5.2, 15.0. 25.0);fun(rec)}

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考题使用VC6打开考生文件夹下的工程test11_3。此工程包含一个test11_3.cpp，其中定义了类CPosition，但该类的定义都并不完整。请按要求完成下列操作，将类CPosition的定义补充完整。(1)在类定义外完成重载的两个构造函数CPosition()和CPosition(double dx，double dy)，其中前者为不带参数的构造函数，使CPosition对象的默认值为x=0，y=0，后者为带参数的构造函数，把数据成员x和y分别初始化为参数dx和dy的值。请在注释“//**1**”之后添加适当的语句。(2)在类体中添加函数move(double ax，double ay)的定义，使得点的坐标x和y分别移动ax和ay个单位，请在注释“// **2**”之后添加适当的语句。(3)完成函数double distance (double bx，double by)的定义，该函数返回*this和点(bx,by)的距离，请在注释“//**3**”之后添加适当的语句。注意：除在指定的位置添加语句外，请不要改动程序中的其他语句。源程序文件test11_3.cpp清单如下：include＜iostream.h＞include＜math.h＞class CPosition{public：CPosition()；CPosition(double dx，double dy)；double getx()；double gety()；// ** 2 **double distance(double bx，double by)；private：double x；double y；}；// ** 1 **{x=0；y=0；}CPosition：：CPosition(double dx，double dy){x=dx；y=dy；}double CPosition：：getx(){return x；}double CPosition：：gety(){return y；}double CPosition：：distance(double bx，double by){// ** 3 **}void main(){double a，b；cout ＜＜ "Input x， y position of a point："；cin ＞＞ a ＞＞ b；CPosition psA(a，b)；cout ＜＜ “Input x，y position of another point："；cin ＞＞ a ＞＞ b；cout ＜＜ "The distance is " ＜＜ psA．distance(a，b) ＜＜endl；}

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考题使用VC6打开考生文件夹下的工程test1_1，此工程包含一个源程序文件test1_1．cpp，但该程序运行有问题，请改正main函数中的错误，使该程序的输出结果如下：Constructor called.Default constructor called.Area is 6Area is 0Area is 6源程序文件test1_1,cpp清单如下：include＜iostream.h＞class RectAngle{private:double ledge,sedge;public:RectAngle(){cout＜＜"Default constructor called.";}RectAngle(double l,double s){ledge=l;sedge=s;cout＜＜"Constructor called.";}void Set(double l,double s){ledge=l;sedge=s;}void Area(){cout＜＜"Area is"＜＜ledge*sedge＜＜endl;}};void main(){／***************** found *****************／RectAngle Rect1(2,3);RectAngle Rect2(1);／**************** found *****************／RectAnglC Rect3;Rectl.Area();／***************** found *****************／RecL2.lodge=0;Rect2.sedge=0;Reck2.Area();Rect3.Area();}

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考题阅读以下说明和C++程序，将应填入(n)处的字句写在对应栏内。【说明】以下程序的功能是计算正方体、球体和圆柱体的表面积和体积并输出。程序由4个类组成：类cube、sphere和cylinder分别表示正方体、球体和圆柱体；抽象类 container为抽象类，提供了两个纯虚拟函数surface_area()和volum()，作为通用接口。【C++程序】include＜iostream.h＞define pi 3.1416class container｛protected:double radius;public:container(double radius) {container::radius=radius;}virtual double surface_area()=0;virtual double velum()=0;};class cube:(1){ //定义正方体类public:cube(double radius):container(radius){};double surface_area () {return 6 * radius * radius;}double volum() {return radius * radius * radius;}};class sphere:(2){ //定义球体类public:sphere(double radius): container(radius){};double surface_area() { return (3);}double volum() {return pi * radius * radius * radius * 4/3;}};class cylinder:(4){ //定义圆柱体类double height;public:cylinder(double radius,double height):container(radius){container::height=height;}double surface_are a () { return 2 * pi * radius * (height+radius); }double volum () {return (5);}};void main(){container * p;cube obj1 (5);sphere obj2(5);cylinder obj3(5,5);p=obj1;cout＜＜“正方体表面积”(＜＜p-＞surface_area()＜＜end1;cont＜＜“正方体体积”＜＜p-＞volume()＜＜end1;p=obj2;cout＜＜“球体表面积”＜＜p-＞surface_area()＜＜end1;cout＜＜“球体体积”＜＜p-＞volume()＜＜end1;p=obj3;cout＜＜“球体表面积”＜＜p-＞surface_area()＜＜end1;cout＜＜“球体体积”＜＜p-＞volume()＜＜end1;}

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考题下列程序中，先声明一个圆类circle和一个桌子类table，另外声明一个圆桌类roundtable，它是由 circle和table两个类派生的，要求声明一个圆桌类对象，并输出圆桌的高度，面积和颜色。请填空完成程序include＜iostream.h＞include＜string.h＞class circle{double radius；public：circle(double r){radius=r；}double get_area(){return 3.416*radius*radius；}}；class table{double height；public：table(double h)＜height=h；}double get_height(){return height；}}；class roundtable：public table，public circle{char *color;public：roundtable(double h，double r，char c[])：【】 {color=new char[strlen(c) +1]；【】；}；char*get_color(){return color；}}：void main(){roundtable rt(0.8，1.0，“白色”);cout＜＜"圆桌的高:"＜＜rt. get_height()＜＜end1;cout＜＜"圆桌面积:"＜＜rt.get_area()＜＜end1;cout＜＜"圆桌颜色:"＜＜n.get color()＜＜end1;}

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考题以下程序的主函数中调用了在其面前定义的fun函数 #includestdio．h . . . main（） {double a[15]，k； k=fun(a)； . . .} 则以下选项中错误的fun函数首部是（）。、A.double fun(double a[l5])B.double fun(double *a) 。C.double fun(double a[])D.double fun(double a)

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考题若主函数中有以下定义和语句： main() { double a[3][4]； …… fun(a) ； } 则正确的fun函数的首部是( )A．void fun(double *s)B．fun(double *s[4])C．fun(double(*s)[3])D．void fun(double(*s)[4])

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考题阅读以下说明和C++程序，将应填入(n)处的字句写在对应栏内[说明]以下程序的功能是计算三角形、矩形和正方形的面积并输出。程序由4个类组成：类Triangle，Rectangle和Square分别表示三角形、矩形和正方形；抽象类Figure提供了一个纯虚拟函数getArea()，作为计算上述三种图形面积的通用接口。[C++程序]include＜iostream.h＞include＜math.h＞class Figure{public:virtual double getArea()=0; //纯虚拟函数};class Rectangle: (1) {protected:double height;double width;public:Rectangle(){};Rectangle(double height,double width){This-＞height=height;This-＞width=width;}double getarea(){return (2);}};class Square: (3)public:square(double width){(4);}};class triangle: (5) {double la;double lb;double lc;public:triangle(double la,double lb,double lc){this-＞la=la;thiS-＞ib;this-＞lc;}double getArea(){double s=(la+lb+lc)/2.0;return sqrt(s*(s-la)**(s-lb)*(s-lc));}};viod main(){figure*figures[3]={new triangle(2,3,3),new Rectangle(5,8),new Square(5)};for(int i=0; i＜3;i++){cout＜＜"figures["＜＜i＜＜"]area="＜＜(figures)-＞getarea()＜＜endl;}}};

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考题若程序中定义了以下函数 double myadd（double a，double b） { return（a+b）； } 并将其放在调用语句之后，则在调用之前应该对该函数进行说明，以下选项中错误的说明是（）A、double myadd（double a，b）；B、double myadd（double，double）；C、double myadd（double b，double a）；D、double myadd（double x，double y）；

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