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名词解释题
复合物I( complex I)
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更多 “名词解释题复合物I( complex I)” 相关考题
考题
有如下程序：#includeusing namespace std;class Complex{double re, im;public:Complex(double r, double i):re(r), im(i){}double real() const{return re;}double image() const{return im;}Complex operator +=(Complex a){re += a.re;im += a.im;return *this;}};ostream operator(ostream s,const Complex z){return s'('}int main(){Complex x(1, -2), y(2, 3);cout(x += y)return 0;}执行这个程序的输出结果是A ． (1, -2)B ． (2, 3)C ． (3, 5)D ． (3, 1)
考题
有以下程序include using namespace std;class Complex{public: Complex(double r=O,
有以下程序 #include＜iostream＞ using namespace std； class Complex { public： Complex(double r=O,double i＝0)：re(r),im(i){} double real() const {return re；} double imag()const {return im；} Complex operator ＋(Complex C) const {return Complex (re＋c.re,im＋c.im)；} private： double re,im； }； int main() { Complex a=Complex(1，1)＋Complex (5)； cout＜＜a．real()＜＜'＋'＜＜a.imag()＜＜'i'＜＜endl； retum 0； } 程序执行后的输出结果是A．6＋6iB．6＋1iC．1＋6iD．1＋1i
考题
有以下程序include using namespacestd;class Complex{public:Complex (doubler=0, d
有以下程序 #include ＜iostream＞ using namespace std; class Complex { public: Complex (double r=0, double i =0 :re(r) ,im (i) {} double real() const {return re;} double imag() const { return im;} Complex operator + (Complex c} const {return Complex(re+c.re, im+c.im);} privane: double re,im; }; int main { Complex a =Complex (1,1)+Complex(5); cout＜＜a.real()＜＜'+'＜＜a.imag() ＜＜ 'i' ＜＜endl return 0; } 程序执行后的输出结果是A．6+6iB．6+1iC．1+6iD．1+1i
考题
阅读以下说明和Java 码，将应填入(n)处的字名写在的对应栏内。[说明] 编写一个完整的JavaApplet 程序使用复数类Complex 验证两个复数1+2i 和3+4i 相加产生一个新的复数4+6i。复数类Complex 必须满足如下要求：(1) 复数类Complex 的属性有：RealPart: int 型，代表复数的实数部分ImaginPart: int 型，代表复数的虚数部分(2) 复数类Complex 的方法有：Complex()：构造函数，将复数的实部和虚部都置0Complex (intr，inti)：构造函数，形参r为实部的初值，i为虚部的初值。ComplexeomplexAdd (Complexa)：将当前复数对象与形参复数对象相加，所得的结果仍是一个复数值，返回给此方法的调用者String ToString()：把当前复数对象的实部、虚部组合成s+ bi 的字符串形式，其中a和b分别为实部和虚部的数据。importjava. applet. * ;importjava. awt. * ;publicclassabcextends Applet{Complex a, b, c;publi cvoid init( ){a = newComplex(1,2);b = newComplex(3,4);c = newComplex();}publievoidpaint (Graphicsg){(1)g. drawstring( “第一个复数：” + a. toString(), 10,50);g. drawstring( “第二个复数：” + b. toString( ), 10,70 );g. drawstring( “两复之和：” + c. toString( ), 10,90);}}class Complex{int RealPart;int ImaginPart;Complex( ) { (2) }Complex( intr , inti){ (3) }ComplexeomplexAdd (Complexa){Complextemp = newComplex( );temp. BealPart = RealPart + a. BealPart;(4)returntemp;}public StringtoString( ){ return( RealPart + " + " + ImaginPart + " i "); }}
考题
有如下程序: include using namespace std; class Complex { double re, im, public
有如下程序： #include ＜iostream＞ using namespace std; class Complex { double re, im, public: Complex(double r, double i): re(r), im(i) {} double real() const {return re;} double image() const {return im,} Complex operator +=(Complex a) { re +=a.re; im +=a.im; return *this; } }; ostream operator ＜＜ (ostream s, const Complex z) { return s＜＜'('＜＜z.real()＜＜','＜＜z.image()＜＜')'; } int main() { Complex x(1,-2), y(2,3); cout ＜＜ (x+=y) ＜＜ endl; return 0; } 执行这个程序的输出结果是( )。A．(1，-2)B．(2，3)C．(3，5)D．(3，1)
考题
有以下程序,输出结果()。includeusing namespace std;class Complex{public:Complex(d
有以下程序，输出结果( )。 #include＜iostream＞ using namespace std; class Complex { public: Complex(double r=0,double i=0):re(r),im(i){} double real()const{return re;} double imagoconst{return im;} Complex operator+(Complex C) const {return Complex(re+c.re,im+c.im);} private: double re,im; }; int main() { Complex a=Complex(1,1)+Complex(5); cout＜＜a.real()＜＜'+'＜＜a.imag()＜＜'i'＜＜end1; return 0; }A．6+iB．2i+5C．6+1iD．1i+5
考题
与“for(i=0；i＜10；i++)putchar('a'+i)；”功能不同的语句是______。A．for(i=0；i＜10；)putchar('a'+(++i))；B．for(i=0；i＜10；)putchar('a'+(i++))；C．for(i=0；i＜10；putchar('a'+i)，i++)；D．for(i=0；i＜=9；i++)putchar('a'+i)；
考题
有以下程序； #includeiostream usingnamespacestd； classComplex { public： Complex(doubler=0，doublei=O)：re(r)，im(i){} doublereal（）const{returnre；} doubleimag（）const{returnim；} Complexoperator＋(Complexc)const {returnComplex(re＋C．re，im＋C．im)；} private： doublere，im； }； intmain（） { Complexa=Complex(1，1)＋Complex(5)； couta．real（）＋a．imag（）iendl； return0； } 程序执行后的输出结果是（ ）。A.6＋6iB.6＋1iC.1＋6iD.1＋1i
考题
下面是复数类complex的定义，其中作为友元函数重载的运算符“--”的功能是将参数对象的实部减1，然后返回对该对象的引用；请补充完整。class complex{private:int real;int imag;public:complex(int r=0,int i=0):real(r),imag(i){}void show (){cout＜＜real＜＜(imag＜0?"-":"+")＜＜imag＜＜'i';}______;};complex operator -- (complex c){c.real --;return c;}
考题
有下列程序:includeusing namespace std;class Complex{double re,im;public:Complex
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考题
有以下程序:includeusing namespace std;class Complex{public:Complex(dOuble r=0,d
有以下程序： #include＜iostream＞ using namespace std； class Complex { public： Complex(dOuble r=0，dOuble i=0)：re(r)，im(i){} doublereal()const{return re；} doubleimag()const{return im；} Complex operator+(Complex c)const {return ComplexA．6+6iB．6+1iC．1+6iD．1+1i
考题
有以下程序；#includeiostreamusingnamespacestd；classComplex{public：Complex(doubler=0，doublei=O)：re(r)，im(i){}doublereal（）const{returnre；}doubleimag（）const{returnim；}Complexoperator＋(Complexc)const{returnComplex(re＋C．re，im＋C．im)；}private：doublere，im；}；intmain（）{Complexa=Complex(1，1)＋Complex(5)；couta．real（）＋a．imag（）iendl；return0；}程序执行后的输出结果是（ ）。A.6＋6iB.6＋1iC.1＋6iD.1＋1i
考题
阅读下列短文，从每题所给的A、B、C、D四个选项中，选出最佳选项，AHow I Turned to Be OptimisticI began to grow up that winter night when my parents and I were returning from my aunt's house, and my mother said that we might soon be leaving for America. We were on the bus then. I was crying, and some people on the bus were turning around to look at me. I remember that I could not bear the thought of never hearing again the radio program for school children to which I listened every morning.I do not remember myself crying for this reason again. In fact, I think I cried very little when I was saying goodbye to my friends and relatives. When we were leaving I thought about all the places I was going to see-—the strange and magical places I had known only from books and pictures. The country I was leaving never to come back was hardly in my head then.The four years that followed taught me the importance of optimism, but the idea did not come to me at once. For the first two years in New York I was really lost—having to study in three schools as a result of family moves. I did not quite know what I was or what I should be. Mother remarried, and things became even more complex for me. Some time passed before my stepfather and I got used to each other. I was often sad, and saw no end to "the hard times."My responsibilities in the family increased a lot since I knew English better than everyone else at home. I wrote letters, filled out forms, translated at interviews with Immigration officers, took my grandparents to the doctor and translated there, and even discussed telephone bills with company representatives.From my experiences I have learned one important rule: almost all common troubles eventually go away! Something good is certain to happen in the end when you do not give up, and just wait a little! I believe that my life will turn out all right, even though it will not be that easy.56. How did the author get to know America?A.Fromherrelatives.B.Fromhermother.C.Frombooksandpictures.D.Fromradioprograms.
考题
事故树的最小径集为：{x1，x2，x3，x4}、{x5，x6}、{x7}{x8}其结构重要度排序为：（）的特征。A、IΦ（7）= IΦ（8）＞IΦ（5）= IΦ（6）＞IΦ（1）= IΦ（2）= IΦ（3）=IΦ（4）B、IΦ（7）= IΦ（8）＞IΦ（5）= IΦ（1）＞IΦ（6）= IΦ（2）= IΦ（3）=IΦ（4）C、IΦ（7）= IΦ（8）＞IΦ（5）= IΦ（3）＞IΦ（6）= IΦ（1）=IΦ（2）=IΦ（4）D、IΦ（5）=IΦ（7）= IΦ（8）＞IΦ（3）＞IΦ（6）= IΦ（1）=IΦ（2）=IΦ（4）
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单选题Which of the following shows the general intonation pattern in a complex sentence?A
When I started my ↗ career there was no↗ unemployment.B
When I started my↗ career there was no↘ unemployment.C
When I started my↘career there was no↗unemployment.D
When I started my↘career there was no↘unemployment.
考题
名词解释题anaphase-promoting complex,APC (后期促进复合物)
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