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How can I get legal advice for free?()
A. You can get nothing for free.
B. To be frank, I don't know for sure.
C. You can go to a law firm and ask about that.
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更多 “ How can I get legal advice for free?()A. You can get nothing for free.B. To be frank, I don't know for sure.C. You can go to a law firm and ask about that. ” 相关考题
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Lodger: I’m terribly sorry that I broke you precious vase. I’ll pay for it.Landlady:____.
A.Can’t complainB.Take careC.Relax yourselfD.Never mind
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22．In the daytime， when you dive in the sea， you ________A． can see everything green and blueB． can- t be in dangerC． can catch nothingD． can't see anything clearly
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---Good morning. I've got an appointment with Miss Smith in the PersonnelDepartment.--Ah, good morning. You ____be Mrs. Peters.A. mightB. mustC. wouldD. can
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—_______ I return the book to the library this week?— No, you _______.You can keep it until the end of this month.
A.Must; needn’tB.Can; can’tC.May; mustn’tD.Can; mustn’t
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下面的代码用于输出字符数组ch中每个字符出现的次数，应该填入的代码是（）public static void main（String[] args) { char[] ch = { 'a', 'c', 'a', 'b', 'c', 'b' }; HashMap map = new HashMap（); for （int i = 0; i ＜ ch.length; i++) { ＜ 填入代码 ＞ } System.out.println（map); }A．if (map.contains(ch[i])) { map.put(ch[i], map.get(ch[i]) + 1); } else { map.put(ch[i], 1); }B．if (map.contains(ch[i])) { map.put(ch[i], (Integer) map.get(ch[i]) + 1); } else { map.put(ch[i], 1); }C．if (map.containsKey(ch[i])) { map.put(ch[i], (int) map.get(ch[i]) + 1); } else { map.put(ch[i], 1); }D．if (map.containsKey(ch[i])) { map.put(ch[i], (Integer) map.get(ch[i]) + 1); } else { map.put(ch[i], 1); }
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